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    • Posted by Abby Ohhh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Avinash Kumar 6 years, 4 months ago

    Chill kr bro exam tough nahi aata Bs overconfident mt ho jana apna 100% do fir baad me ye feel nahi hona chahiye "thoda aur padh leta" ya fir "kaash pubg pehle chhod deta"

    1Thank You

    Vikas Semwal 6 years, 4 months ago

    Look, basically before examinations everyone have daubts related to question pprs but we have to make our mind set that we are not the 1 st batch to give physics exam, many batches were passed out such examinations before......... Therefore study as much potential as u can

    3Thank You

    Neha Choudhary 6 years, 4 months ago

    Dont wry all is well Dont take tension

    2Thank You

    ANSWER

    • Posted by Shreya Kashyap 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Devesh Sinha 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Akhilesh Chaurasia 6 years, 4 months ago

    Define electrostatic

    0Thank You

    Akhilesh Chaurasia 6 years, 4 months ago

    H

    0Thank You

    ANSWER

    • Posted by Dharamveer Sharma 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Ranuma Begum 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Ajendra Singh 6 years, 4 months ago

    answer : 9 × 10¹³ J explanation : mass of substance , m = 1g = 10^-3 kg velocity of light , v = 3 × 10^8 m/s according to Enstien's energy - mass equivalent theory, Mass can be converted into pure energy . it is expressed by = 10^-3 × (3 × 10^8)² = 10^-3 × 9 × 10^16 J = 9 × 10¹³ J hence, 9 × 10¹³ J amount of energy is equivalent of 1g of substance. 5.0 explanation : mass of substance , m = 1g = 10^-3 kg velocity of light , v = 3 × 10^8 m/s according to Enstien's energy - mass equivalent theory, Mass can be converted into pure energy . it is expressed by E=mc^2 = 10^-3 × (3 × 10^8)² = 10^-3 × 9 × 10^16 J = 9 × 10¹³ J hence, 9 × 10¹³ J amount of energy is equivalent of 1g of substance.

    1Thank You

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    • Posted by Ajendra Singh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Ajendra Singh 6 years, 4 months ago

    Thanks avantika

    0Thank You

    Avantika Negi 6 years, 4 months ago

    Due to electromagnetic induction

    2Thank You

    ANSWER

    • Posted by Pradeep Singh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Ritik Kapil 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Rahul Gupta 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Ritesh Gupta 6 years, 4 months ago

    Diamagnetic material

    0Thank You

    ANSWER

    • Posted by Yugratan Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Yugratan Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anjali Jain 6 years, 4 months ago

    Location is at the a/2. nature can be negative or positive both. Magnitude is q/2 since the forces must balance each other.

    0Thank You

    ANSWER

    • Posted by Yugratan Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Vaibhav Singh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Gursharn Kaur 6 years, 4 months ago

    B= f/ qv U can calculate using this

    0Thank You

    Sohan .G 6 years, 4 months ago

    [M L^0 T^-2 A^-1]

    0Thank You

    ANSWER

    • Posted by Kunj Parmar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gaurav Seth 6 years, 4 months ago

    According to Gauss’s law, the total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The total electric flux through a closed surface is zero if no charge is enclosed by the surface.

    • Gauss’s law is true for any closed surface, no matter what its shape or size.
    • The term q on the right side of Gauss’s law includes the sum of all charges enclosed by the surface. The charges may be located anywhere inside the surface.
    • In the situation when the surface is so chosen that there are some charges inside and some outside, the electric field is due to all the charges, both inside and outside S. The term q on the right side of Gauss’s law, however, represents only the total charge inside S.
    • The surface that we choose for the application of Gauss’s law is called the Gaussian surface. The Gaussian surface can pass through a continuous charge distribution.
    • Gauss’s law is useful for the calculation of the electrostatic field for a symmetric system.
    • Gauss’s law is based on the inverse square dependence on distance contained in the Coulomb’s law. Any violation of Gauss’s law will indicate departure from the inverse square law.

    1Thank You

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    • Posted by Sohan .G 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Harsh Mishra 6 years, 4 months ago

    I know that You'd copied it from Meritnation, Gaurav Bhaiya.....But, I'm not going to do the Same.....

    Well, Vandana If you want similar Questions, So You'n try my home website Brainly.... we don't get the exact Q. there but a lot of similar ones..... For Instance :-

    <article data-quality-tier="3" data-question-id="2751716" data-z="{"id": "2751716"}" id="question">

    Q. Light of wavelength 2000 Angstrom falls on a metal surface of work function 4.2 ev. What is the kinetic energy in ev of fastest and slowest photo electron emitted from the surface?

    </article> <section id="answers">

    Hope this helps you....

    </section>

    1Thank You

    Harsh Mishra 6 years, 4 months ago

    Kya Hua Gaurav Bhaiya, Copy karne ke liye exact Answer naheen Mila.....That's why, You're advising us to do the similar Question!!!

    1Thank You

    Gaurav Seth 6 years, 4 months ago

    Take help from similar ques:

    Light of wavelength 2500Å falls on a metal surface of work function 3.5V. What is the kinetic energy (in eV) of (i) the fastest and (ii) the slowest electronic emitted from the surface? If the same light falls on another surface of work function 5.5eV, what will be the energy of emitted electrons?

     

    Wavelength of incident radiation (λ) = 2500Å

    Work function (W0) =3.5eV

    (i) KE of fastest electron =1.47eV
    (ii) KE of slowest electron = 0eV
    If the same light (having energy 4. 97eV) falls on the surface (of work function 5.5eV), then no photoelectrons will emit.

    2Thank You

    ANSWER

    • Posted by Vaibhav Singh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Vaibhav Singh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 4 answers

    Gursharn Kaur 6 years, 4 months ago

    F/ m

    0Thank You

    Shubham Gupta 6 years, 4 months ago

    C²/N-m²

    0Thank You

    Shatayu Ganvir 6 years, 4 months ago

    Ur is unitless

    0Thank You

    Tanisha Sharma 6 years, 4 months ago

    Hm^-1

    0Thank You

    ANSWER

    • Posted by Satyam Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Uk Umesh 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gursharn Kaur 6 years, 4 months ago

    B= F/ qv

    0Thank You

    ANSWER

    • Posted by Himu Saini 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Prakhar Jhamb 6 years, 4 months ago

    Volume field density

    1Thank You

    Prakhar Jhamb 6 years, 4 months ago

    Sorry

    1Thank You

    Prakhar Jhamb 6 years, 4 months ago

    Linear field density

    1Thank You

    ANSWER

    • Posted by Manoj S 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Jaya Mishra 6 years, 4 months ago

    A compound microscope is used to see very small objects like virus,bacteria,e.t.c.

    0Thank You

    ANSWER
    Hey

    • Posted by Sanjeevi Raj 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Unique Girl.. ? 6 years, 4 months ago

    Hi

    0Thank You

    ANSWER

    • Posted by Dilip Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Paras Dubey 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Prerna Jaiswal 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Priya Upadhyay 6 years, 4 months ago

    Ya in december

    1Thank You

    Naval Singh 6 years, 4 months ago

    December

    1Thank You

    ANSWER

    • Posted by Rohit Patil 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Naval Singh 6 years, 4 months ago

    Derive of semiconduct semiconductors

    0Thank You

    ANSWER

    • Posted by Vicky Kumar 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 5 answers

    Ron Vineetahuja 6 years, 4 months ago

    20 marks

    0Thank You

    Gursharn Kaur 6 years, 4 months ago

    15-17 average

    1Thank You

    Naval Singh 6 years, 4 months ago

    12 marks

    1Thank You

    Adarsh Deep Gupta 6 years, 4 months ago

    10-12

    1Thank You

    Tapan Pandey 6 years, 4 months ago

    From new curricular, it contains 23 marks

    4Thank You

    ANSWER

    • Posted by Harishsai Harishsai 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Naval Singh 6 years, 4 months ago

    Very simple

    0Thank You

    ANSWER

    • Posted by Sanket Srivastava 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Gursharn Kaur 6 years, 4 months ago

    According to Faraday's first law whenever there is a change in magnetic field intensity ,induced current is produced

    0Thank You

    Naval Singh 6 years, 4 months ago

    Very simple

    0Thank You

    Deeya Singh 6 years, 4 months ago

    First Law of Faraday's Electromagnetic Induction state that whenever a conductor are placed in a varying magnetic field emf are induced which is called induced emf, if the conductor circuit are closed current are also induced which is called induced current.

    0Thank You

    ANSWER

    • Posted by Richa Tyagi 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Mp? Mp? 6 years, 4 months ago

    For the prism it will depend on which side the plane wavefront attack. The side on which the upcoming rays attack will give the emerging wavefront as per the shape of that side.

    3Thank You

    Mp? Mp? 6 years, 4 months ago

    Converging lens will converge the plane wavefront and diverging lens will give the diverging wavefront for emerging rays

    2Thank You

    ANSWER

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