CBSE > Class 12 > Physics | CBSE Board | Homework Help

If white light is used in YDSE no interference will be there and different colors form their own fringes being red the widest and violet the narrowest

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Prashant Sher Yadavanshi 2 years, 2 months ago

Simple answer is fringe width will increase

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Aman Meena 2 years, 2 months ago

Because white.is combination of all seven colours so when we pass white light from narrow slits it will give a better pattern fringes

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Fun

Posted by Goyal Pranav 2 years, 2 months ago

CBSE > Class 12 > Physics

2 answers

Raj Yadav 2 years ago

1min =se 0

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Prajwal Sharma 2 years, 2 months ago

Having something which you can do with your own desire and enjoying the work

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Main application of wheastone bride with mathematical expression

Posted by Tania Debnath 2 years, 2 months ago

CBSE > Class 12 > Physics

2 answers

Anjan Karthi 2 years, 2 months ago

Balanced wheatstone bridge used to calculate unknown resistance in the presence of a known resistance, with the help of metre bridge apparatus. The expression is P/Q = R/S where P and Q are resistances on the same arm of the combination but still separate and so are R and S.

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Prashant Sher Yadavanshi 2 years, 2 months ago

😂😂😂😂bride

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Superposition principal

Posted by Nitin Bhardwaj 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Sri . 2 years, 2 months ago

The principle of superposition states that every charge in space creates an electric field at point independent of the presence of other charges in that medium. The resultant electric field is a vector sum of the electric field due to individual charges.

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When electrons drift from lower to higher potential, does it means that all the free electron of the metal are moving in the same direction?

Posted by Saurabh Kumar 2 years, 2 months ago

CBSE > Class 12 > Physics

3 answers

Rshi Kumar 2 years, 2 months ago

No because some electrons have different potential .

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Sri . 2 years, 2 months ago

When electron drift in a metal from lower to higher potential all the free electrons of the metal do not move in the same direction. When electric field is applied, the net drift of the electrons is from lower to higher potential.

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Anjan Karthi 2 years, 2 months ago

No, all the free electrons do not move in the same direction. The net movement of the electron is from the lower to the higher potential. Some electrons may move in higher potential to lower potential, may not move or may move in any other direction and although all electrons do not flow in the same direction, a large fraction of the electrons flows from the lower potential to the higher potential. There is a very small fraction of electrons that do not flow in that direction. Hence the net movement will always be from lower potential to the higher potential.

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Basic assumptions of Rutherford atom model

Posted by Gaurav Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Sri . 2 years, 2 months ago

Rutherford's model proposed that the negatively charged electrons surround the nucleus of an atom. He also claimed that the electrons surrounding the nucleus revolve around it with very high speed in circular paths. He named these circular paths as orbits.

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Electroscope working

Posted by Sai Kedar 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Abhishek Maurya 2 years, 2 months ago

D third lduoxioy sa udisuizudoyxi

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The refractive index of first medium is 1.25 and focal length of convex lens is 20cm if the radius of curvature first side of lens is 20cm and second radius of curvature is 10cm then find the refractive index of other medium

Posted by Deepu Kumar Yadav 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

According to lens makers' formula, 1/f = (n 21 - 1) 1/R1 - 1/R2. n 21 - 1 = 1/f ( R1 R2 / R1 + R2). n 21 - 1 = 1/20 (20 × 10 / 30). n 21 - 1 = 1/20 (20/3) = 1/3. n 21 = 1 + 1/3 = 4/3. n2/n1 = 4/3. n2 / 1.25 = 4/3. Therefore, the refractive index of the second medium n2 = 4 × 1.25 / 3 = 5/3 = 1.67. //

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Why bohrs theory of atom failed??

Posted by Uday Shukla 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

1) Couldn't explain Zeeman and Stark effects (Variations in fine atomic spectra with alternating electric and magnetic fields). 2) Couldn't explain the existence of fine thin spectral lines in the atomic spectra. 3) The theory was limited to hydrogen-like species. 4) Later, discovered that electrons revolved not around circular energy states, but across a fixed range of energy levels around atoms (called subshells or orbitals).

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Which lens is converging

Posted by Adarsh Kumar 2 years, 2 months ago

CBSE > Class 12 > Physics

4 answers

Sri . 2 years, 2 months ago

Converging lens is convex lens whereas diverging lens is a concave lens. Converging lens converge and focus the light ray to meet at a single point whereas diverging lens, diverge the light falling on its surface and not meet at a single point

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Gulshan Kumar 2 years, 2 months ago

Concave lens

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Anjan Karthi 2 years, 2 months ago

Convex lens when the surrounding medium is optically rarer than the lens itself, and concave lens is the surrounding medium is optically denser than the material of the lens.

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Uday Shukla 2 years, 2 months ago

Convex lens

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Is it true sini /sin r is equal to 1by refractive index

Posted by Payal Verma 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

sin i / sin r = 1/Relative refractive index of medium 1(from where the light came) with respect to medium 2 (to which the light enters on leaving medium 1)

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Ampere circutial law derivation

Posted by Gunnjanaa Singhh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Mayank Chauhan 2 years, 2 months ago

B.ds cos Q = unI

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A small candle 2.5 cm in size is placed at 27 in front of a concave mirrir of radius of curvature 36 cm at what distance from the mirror should a screen be placed in a order to obtain a sharp image ? Describe the nature and size of the image if the candle is moved closer to the mirror , how would the screen have to be moved ?

Posted by Deepu Kumar Yadav 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

h = 2.5 cm. u = - 27 cm. R = 2f = - 36 cm. Therefore, according to mirror formula, 1/f = 1/v + 1/u. 1/v = 1/f - 1/u = 1/18 - 1/27 = - 9 / 18 × 27 = - 1 / 54. v = - 54 cm. Magnification m = -v/u = 54/-27 = - 2 = h'/h. h' = mh = - 2 × 2.5 = -5 cm. So, the image is real, inverted and enlarged and is formed at a distance greater than R in front of the mirror. If the candle is brought closer to the mirror, then the screen should be moved far away from the mirror.

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What is glycogen

Posted by Ajitha Kumari 2 years, 2 months ago

CBSE > Class 12 > Physics

3 answers

Satya Swaroop . 2 years, 2 months ago

Animal fat

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Anjan Karthi 2 years, 2 months ago

Also known as animal starch, glycogen is the form in which carbohydrates and saccharides are stored in animal body. Unlike starch which has both amylose and amylopectin components, glycogen solely consists of amylopectin.

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Ajitha Kumari 2 years, 2 months ago

Answer

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Project on compound microscope

Posted by Arnav Thakur 2 years, 2 months ago

CBSE > Class 12 > Physics

0 answers

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dm =0.05% of 1kg 0.05/100 dm=5×10^-4 kg How 10^-4 come

Posted by Vishal Sharma 2 years, 2 months ago

CBSE > Class 12 > Physics

0 answers

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Define electric flux. Write its SI unit. Gauss' law in electrostatics is true for any closed surface, no matter what its shape or size is. Justify this statement with the help of a suitable example. (ii) Use Gauss' law to prove that the electric field inside a uniformly charged spherical shell is zero.

Posted by Maahnoor Quraishi 2 years, 2 months ago

CBSE > Class 12 > Physics

2 answers

Preeti Dabral 2 years, 2 months ago

The electric flux through an area is defined as the electric field multiplied by the area of the surface projected on a plane, perpendicular to the field. Its S.I. unit is voltmeter (V_m) or Newton metre square per coulomb (Nm² C^-1). The given statement is justified because while measuring the flux, the surface area is more important than its volume on its size.
Electric field inside the shell:

The charge resides on the surface of a conductor. Thus, a hollow charged conductor is equivalent to a charged spherical shell. Let's consider a spherical Gaussian surface of radius (r < R). If E is the electric field inside the shell, then by symmetry electric field strength has the same magnitude E_i on the Gaussian surface and is directed radially outward.
Electric flux through the Gaussian surface is given by,
{tex}=\int_{s} \vec{E}_{i} \cdot d \vec{S}{/tex}
{tex}=\int E_{i} d S \cos 0=E_{i} .4 \pi r^{2}{/tex}
Now, Gaussian surface is inside the given charged shell, so charge enclosed by Gaussian surface is zero.
Therefore, using Gauss's theorem, we have
{tex}\int_{S} \vec{E}_{i} \cdot d \vec{S}=\frac{1}{\epsilon_{0}} \times \text { charge enclosed }{/tex}
{tex}\Rightarrow E_{i} \cdot 4 \pi r^{2}=\frac{1}{\epsilon_{0}} \times 0{/tex}
{tex}\Rightarrow{/tex} E_i = 0
Thus, electric field at each point inside a charged thin spherical shell is zero.

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Mayank Chauhan 2 years, 2 months ago

The no. Of electric field lines passing through a area vector perpendicularly Its S.I unit is Nm²per C

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An alpha particle is accelerated through a potential difference of 10kV and moves along the x-axis. It enters in a region of uniform magnetic field B= 2 × 10-3 T acting along the Y-axis. Find the radius of its path

Posted by Aayush Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Preeti Dabral 2 years, 2 months ago

r=√(2mqV) / qB

as given alpha particle q=2e=2×1.6×10^-19

V=10^4V

m=6.4×10^-27kg

B=2×10^-3T

r=√(2 × 6.4×10^-27 × 2× 1.6×10^-19 × 10^4) /1.6×10^-19 × 2×10^-3

=√(4096×10^-44) / 64 × 10^-23

=(64 × 10^-22) / (64 × 10^-23)

=10

therefore radius is 10m

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Write down the properties of wavefront.

Posted by Muskan Khatun 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Kashu Verma 2 years, 2 months ago

1- The energy of light flows perpendicular to the wave front. 2- All points are in the same phase on the same wavefront. 3- Space between a pair of wavefront is constant along anyway

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Activities of term 1 12th class

Posted by Manish Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Adarsh Kumar 2 years, 1 month ago

Contact me

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Application of gauss theoram

Posted by Deepanshu Goyal 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

The theory is basically used to determine the nature and properties of electric field passing through macroscopic objects (such as infinitely long thin charged wire, infinitely thin charged plane sheet, spherical charged shell, spherical solid charged ball)

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Define motion?

Posted by Shivansh Devaliya 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Nidhi Rathod 2 years, 2 months ago

any object move from one place to another place is with respect to time called motion

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To identify point charges q each are kept 2m apart in air a third point charges q an unknown magnitude an since is placed on a line joining are charges such that the system remains equilibrium find the position on nature of q

Posted by Sakshi Pundir 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Yashi Kushwaha 2 years, 2 months ago

You can try by super position principle.

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About titration practical

Posted by Rana Pratap Singh Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Kashu Verma 2 years, 2 months ago

First the aim of your titration project then material, procedure, theory,table , observations, result , precautions. But you can also write the define of titration after material required.ok

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Question no. 26 of samples paper 2023

Posted by Gunjan 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Kashu Verma 2 years, 2 months ago

Which subject

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Series combination parallel combination graph

Posted by Niharika Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

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Radiation of frequency 1015 Hz is incident on three photosensitive surfaces A, B and C. Following observations are recorded: Surface A: no photoemission occurs Surface B: photoemission occurs but the photoelectrons have zero kinetic energy. Surface C: photo emission occurs and photoelectrons have some kinetic energy. Using Einstein’s photo-electric equation, explain the three observations

Posted by Jatin Grewal 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

A must have had a work function greater than 1015h. So, no matter how intense the light is or for how long the radiation has been falling on the surface, neither would electrons gain energy to be emitted out of the surface. But, in the case of B (as per Einstein equation " hv = hv° + eV° "), emission happened but eV° is ZERO. So, Work function = 1015h for B. For C, Work function would be much lesser than 1015h due to which the surface could emit electrons with some eV° with radiation of 1015 Hz.

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Investigatory project pdf for electromagnetic induction

Posted by Akriti Singh 2 years, 2 months ago

CBSE > Class 12 > Physics