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    • Posted by Anjali Khandalkar 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anjan Karthi 1 year, 10 months ago

    Surface tension is a property of a liquid that makes it behave as if its surface is enclosed in an elastic skin. So, being a "surface" property, we often consider calculating it as the responsive force exerted by the surface molecules of the fluid along A UNIT LENGTH of the surface where the impact of external force is seen. So, surface tension S is F/L which, in SI units, is N/m and it's dimensions are [MT^-2]. Hope it was useful !!!!

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    • Posted by Shrestha Kumar Verma 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Arbind Dada 1 year, 10 months ago

    0Thank You

    Akanksha. Nain 1 year, 10 months ago

    Zero

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    Akansha Bisht 1 year, 10 months ago

    I) Assuming C is in the middle Therefore no net force II) Assuming C is at the corner F net= √2 F + F/√2 F = kq²/a. (assuming a is the sides of the square)

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    • Posted by Account Deleted 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 5 answers

    Account Deleted 1 year, 10 months ago

    Is it your id ?

    0Thank You

    Aseem Mahajan 1 year, 10 months ago

    <font face ="Times New Roman">Nai

    2Thank You

    Account Deleted 1 year, 10 months ago

    Oh I didn't saw 🤦🏻‍♀️... I don't use insta and currently I am not active on tele to ...tell me yours tele I'd I will text you whenever I will be active in that space ...

    0Thank You

    Aseem Mahajan 1 year, 10 months ago

    <font face ="Times New Roman">When I asked your insta/tele

    2Thank You

    Account Deleted 1 year, 10 months ago

    When did I ignored you ?

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    • Posted by Priya Rai 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Lakshita 💜 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Jaspal Sidhu Sidhu 1 year, 10 months ago

    Extremely closed space charges form continuous charge distribution

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    • Posted by Toral Ojha 1 year, 10 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anjan Karthi 1 year, 10 months ago

    W = qV = 20 × 400 × 10^-6 = 8000 × 10^-6 = 8 mJ. //

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    • Posted by Ankit Parida 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Krishna Tyagi 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Bhavyansh Sharma 1 year, 10 months ago

    Notes

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    • Posted by Samiksha Gautam 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Satya Swaroop . 1 year, 11 months ago

    This happens during induction.Say the charged body is with positive charge. When a neutral boday is brought close enough to this positively charged body, such that it is in charged body's Electric field, there is a development of negative charge on the side of the neutral body which is facing the charged body. This makes the neutral body get attracted to charged body.

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    • Posted by Shreesha Naik 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Anjan Karthi 1 year, 10 months ago

    Now, if frequency is not given and velocity is, then there is a long way we have to go. T = 2πR/v, and then I = q/t = qv/2πR.

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    Anjan Karthi 1 year, 10 months ago

    This appears to be a bit difficult, but no worries, there is always a solution in the question itself. We must find current which is I = q/t, and we know 1/T = υ. We know q = e = 1.602 × 10^-19 C. So, in that case, I = eυ.

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    • Posted by Yasmin Sultana 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Satya Swaroop . 1 year, 11 months ago

    Q=n×e So n = 64×10^-17/1.6×10^-19 Solve for answer

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    • Posted by Account Deleted 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Aseem Mahajan 1 year, 11 months ago

    <font face ="Times New Roman">F = qE
    F = 3.2 × 10-19 C × 4000 N/C
    F = 1.28 × 10-15N

    1Thank You

    Ritesh Meena 1 year, 11 months ago

    1.28*10ki power minus 15

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    • Posted by Gunjan Sharma 12Th 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Anjan Karthi 1 year, 10 months ago

    This is just F = G(m')^2 / R^2 = 6.67 × 10^-11 × (9.1 × 10^-31)^2 / (10^-2)^2.

    1Thank You

    Account Deleted 1 year, 11 months ago

    You don't have your own ??

    1Thank You

    Hk Honey 1 year, 11 months ago

    Send me your Instagram I'd

    2Thank You

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    • Posted by Tumngam Karbak 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Sudha Suresh 10 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Jyoti Negi Jyoti 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Hk Honey 1 year, 11 months ago

    Hey

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    • Posted by Sneha Sneha 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anil Tadvi 1 year, 11 months ago

    Hi

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    • Posted by Vandana Sangwaiya 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Hk Honey 1 year, 11 months ago

    Hey vandana

    1Thank You

    Uttam Kumar 1 year, 11 months ago

    It is the branch of success

    3Thank You

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    • Posted by Shashwat Shukla 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 5 answers

    Anjali Dhanraj 1 year, 11 months ago

    Biology seep pahuja Phy. Unacedemy neet toper

    0Thank You

    Babu Lal Teli 1 year, 11 months ago

    Biology - DR. ANAND MANI

    0Thank You

    Babu Lal Teli 1 year, 11 months ago

    Chemistry - CHEMISTRY GURUJI

    0Thank You

    Babu Lal Teli 1 year, 11 months ago

    Physics - Baba SSP YouTube Channel - Sachin sir physics

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    Mohammad Affan 1 year, 11 months ago

    No

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    • Posted by Gur _Sidhu 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Kirti Giri 1 year, 11 months ago

    As soon as possible

    1Thank You

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    • Posted by G.K Talent Genius Satendra 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Kirti Giri 1 year, 11 months ago

    Comming soon

    0Thank You

    Vishal Sharma 1 year, 11 months ago

    Still not given by cbse

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    • Posted by Gangana Pandey 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gur _Sidhu 1 year, 11 months ago

    Not released by cbse yet ..

    1Thank You

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    • Posted by Priyanshu Gautam 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Karnav Nathani 1 year, 11 months ago

    6×10-³

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    • Posted by Priya Naudiyal 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Kunal Kumar Kumar 1 year, 11 months ago

    Doesn't matter it's alright

    0Thank You

    Ayush Gautam 1 year, 11 months ago

    It's ok. If other information provided by you is correct .

    0Thank You

    Account Deleted 1 year, 11 months ago

    It's ok if you have wrote everything thing else correct..

    1Thank You

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    • Posted by Shivi Shrma 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Preeti Dabral 1 year, 11 months ago

    The answer is Yes. An object can move even when there is no force acting upon it. This can be understood from Newton's first law of motion.

    0Thank You

    Anjan Karthi 1 year, 11 months ago

    If the object has already started moving and there are no forces opposing or retarding it's motion, then the object can actually move without any applied force.

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    • Posted by Anuja Ajagekar 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Aman Bamal 1 year, 10 months ago

    F = kqq /r^2 0.2=9×10^9×2q /(0.02) ^2 Solve it you will get the answer

    1Thank You

    Ayush Gangwar 1 year, 11 months ago

    2.22×10^-12 C

    2Thank You

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    • Posted by Neeraj Kumar 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Diya Siwach 2 years ago

    CBSE > Class 12 > Physics
    • 2 answers

    Ayush Mishra 1 year, 11 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    1Thank You

    Aman Tyagi 1 year, 11 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Vishal Kumar Sharma 2 years ago

    CBSE > Class 12 > Physics
    • 3 answers

    Anjan Karthi 1 year, 11 months ago

    Yes, irrespective of the mass number, the density of the nucleus is always a constant ≈ 2 × 10^17 kg/m^3.

    0Thank You

    Swarnim _ 1 year, 11 months ago

    True

    0Thank You

    Aman Tyagi 1 year, 11 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

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    • Posted by Hiba Rafeek 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anjan Karthi 2 years ago

    Ammeter is required to be used to detect the current flowing through it. So, it is important to maintain it with as low as possible and thus, a shunt resistance is used and that too in parallel. But, in the case of voltmeter, the voltage across two points in the circuit is detected using it, so there is no requirement that current must be passed through it but it is necessary to maintain it at infinite resistance if possible. So, it is connected with high resistance in series.

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    • Posted by Vijayshree Soni 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Anjan Karthi 2 years ago

    - 1.602 × 10^-19 C

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