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S.S={gg,bb,bg,gb} [E]=( bb , bg , gb ) [F]=(bb) [E intersection F] = ( bb) P(E) = 3/4 P(F) = 1/4 P (E intersection F) = 1/4 P( E/F)= P(E intersection F)/P(F) P(E/F)= (1/4)/(1/4) = 1

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Alok Mittal 2 years, 3 months ago

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Find a vector of magnitude 5 unit and parallel to resultant of the vector a is 2i+ 3i -k and b is i -2j+ k

Posted by Baria Shubham 2 years, 3 months ago

CBSE > Class 12 > Mathematics

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consider the number of 4where is n natural no.check whether there is any value of n for which 4 end with the digit zero

Posted by Shalvi Dhawan 2 years, 3 months ago

CBSE > Class 12 > Mathematics

1 answers

Preeti Dabral 2 years, 3 months ago

For the number 4ⁿ to end with digit zero for any natural number n, it should be divisible by 5. This means that the prime factorisation of 4ⁿ should contain the prime number 5.But it is not possible because 4ⁿ =(2) 2ⁿ so 2 is the only prime in the factorisation of 4ⁿ . Since 5 is not present in the prime factorization, so there is no natural number n for which 4ⁿ ends with the digit zero.

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Does inverse of matrix by elementary operation is in syllabus of class 12 cbse maths

Posted by Rohini Singh 2 years, 3 months ago

CBSE > Class 12 > Mathematics

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Sofil Dangi 2 years, 3 months ago

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516999

Posted by Diksha Ahuja 2 years, 3 months ago

CBSE > Class 12 > Mathematics

1 answers

Muskan Sharma 2 years, 3 months ago

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Maths project file...

Posted by Shalu Yadav 2 years, 3 months ago

CBSE > Class 12 > Mathematics

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Simplify tan^1√1-x^2-1/x x$0

Posted by Sandeep Kaur Sandeep Kaur 2 years, 3 months ago

CBSE > Class 12 > Mathematics

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How to find the principal value of sin^-1 (sin x + cos x /√2) where -π/4 < x < π/4 ?

Posted by Harini S 2 years, 4 months ago

CBSE > Class 12 > Mathematics

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suppose that m and n are positive integers with m≥2. the (m, n)-sawtooth sequence is a sequence of consecutive integers that starts with 1 and has n teeth, where each tooth starts with 2. goes up to m and back down to 1. for example, the (3,4)-sawtooth sequence is 3 2 2 3 3 3 2 2 2 2 2 2 1 1 1 1 1 the (3, 4)-sawtooth sequence includes 17 terms and the average of these terms is (a) determine the sum of the terms in the (4, 2)-sawtooth sequence. (b) for each positive integer m ≥2, determine a simplified expression for the sum of the terms in the (m, 3)-sawtooth sequence. (c) determine all pairs (m, n) for which the sum of the terms in the (m, n)-sawtooth sequence is 145. (d) prove that, for all pairs of positive integers (m, n) with m> 2. the average of the terms in the (m, n)-sawtooth sequence is not an integer.

Posted by Udit Mehra 2 years, 4 months ago

CBSE > Class 12 > Mathematics

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to minimise the cost of food meeting the dietary requirements of the staple food of adolescent students of your school

Posted by Piyush Negi 2 years, 4 months ago

CBSE > Class 12 > Mathematics

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2add2

Posted by Khan Boy 2 years, 4 months ago

CBSE > Class 12 > Mathematics

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If A = [120] [-2-1-2] [0-11] Find A'

Posted by Umang Agarwal 2 years, 4 months ago

CBSE > Class 12 > Mathematics

1 answers

Aditya Prasad 2 years, 4 months ago

[120][-5][-11] [120][+55] [6600]

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Solution of diffrential equation dy/dx = sec(x+y)

Posted by Uday Shukla 2 years, 4 months ago

CBSE > Class 12 > Mathematics

1 answers

Preeti Dabral 2 years, 4 months ago

$Put x+y=t \begin{aligned} & \frac{d y}{d x}=\frac{d t}{d x}-1 \\ & \frac{d t}{d x}-1=\operatorname{sect} \\ & \frac{d t}{d x}=\operatorname{sect}+1 \\ & \int \frac{d t}{\operatorname{sect}+1}=\int d x \\ & \int \frac{\operatorname{costdt}}{1+\operatorname{cost}} d t=x \\ & \int \frac{1+\operatorname{costdt}-1}{1+\operatorname{cost}} d t=x \\ & \int\left(d t-\frac{1}{1+\cos t}\right) d t=x \end{aligned}$

$\begin{aligned} & \mathrm{t}-\frac{1}{2} \int \sec ^2 \frac{\mathrm{t}}{2} \mathrm{dt}=\mathrm{x} \\ & \mathrm{t}-\tan \frac{\mathrm{t}}{2}=\mathrm{x}+\mathrm{C} \\ & \mathrm{x}+\mathrm{y}-\tan \left(\frac{\mathrm{x}+\mathrm{y}}{2}\right)=\mathrm{x}+\mathrm{C} \\ & \mathrm{y}-\tan \left(\frac{\mathrm{x}+\mathrm{y}}{2}\right)=C \end{aligned}$