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  • 2 answers

Vastav Bansal 2 years, 11 months ago

Can be done due 1st and 2nd order derivative test

Kartik Sahni 2 years, 11 months ago

From stationery points
  • 1 answers

Kartik Sahni 2 years, 11 months ago

3x-2cosx+sinx+C
  • 2 answers

Nashra Khan 2 years, 11 months ago

It is another equivalence relation

Arpit Bhardwaj 2 years, 11 months ago

Hiii
  • 1 answers

Bhavesh Kapure 2 years, 11 months ago

2sinαcosα or 2Tanα/(1+ tan²α)
  • 5 answers

Kartik Sahni 2 years, 11 months ago

Use cbse guide follow criteria

Nashra Khan 2 years, 11 months ago

Study 20 hours

Divyanshu Patel 2 years, 11 months ago

Use rotation study methods

Garima Chaudhary 2 years, 11 months ago

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Bhanu Kumawat 2 years, 11 months ago

Focus on study
  • 1 answers

Amrendra Singh 2 years, 11 months ago

take x^n common from denominator and then take the denominator as = t differentiate put in integral solve
  • 3 answers

Nashra Khan 2 years, 11 months ago

- cos x

Mansi Sharma 3 years ago

Perpendicular/hypotenuse Or ( 1- cos ^2 theta)

Aditya Tripathi 3 years ago

bro SinX= (Perpendicular/Hypotenuse) = ROOT(1 - COS^2 theta)
  • 1 answers

Suryaa Narayana 3 years ago

Put log cotx =t and then solve
  • 3 answers

M Pavan Teja 3 years ago

Nno it take minimum 4yrs to clear it

Aman Kumar 3 years ago

Yess

Indraneel Dutta 3 years ago

Yes off course 😊
  • 1 answers

Ayush Kumar 3 years ago

Sinsidal
  • 0 answers
  • 1 answers

Alok Mittal 3 years ago

Which activity
  • 2 answers

Alok Mittal 3 years ago

S.S={gg,bb,bg,gb} [E]=( bb , bg , gb ) [F]=(bb) [E intersection F] = ( bb) P(E) = 3/4 P(F) = 1/4 P (E intersection F) = 1/4 P( E/F)= P(E intersection F)/P(F) P(E/F)= (1/4)/(1/4) = 1

Alok Mittal 3 years ago

1
  • 1 answers

Preeti Dabral 3 years ago

For the number 4n to end with digit zero for any natural number n, it should be divisible by 5. This means that the prime factorisation of 4 n should contain the prime number 5.But it is not possible because 4n =(2) 2n so 2 is the only prime in the factorisation of 4n . Since 5 is not present in the prime factorization, so there is no natural number n for which 4n ends with the digit zero.

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