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For the number 4n to end with digit zero for any natural number n, it should be divisible by 5. This means that the prime factorisation of 4 n should contain the prime number 5.But it is not possible because 4n =(2) 2n so 2 is the only prime in the factorisation of 4n . Since 5 is not present in the prime factorization, so there is no natural number n for which 4n ends with the digit zero.
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Vastav Bansal 2 years, 7 months ago
1Thank You