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  • 3 answers

Nikhil Kumar 4 years, 2 months ago

f[1] = 1 f[1.2] = 1 f[1.9] = 1 f[1.99] = 1 Since different elements have same image 1 , f is not one - one CHECK ONTO , f(x) =[x] Let , y=f[x] y=[x] i.e , y= Greatest integer less than or equal to x . Hence , value of y will always come an integer . But y is a real number . Hence f is not onto

Shree Ram Faujdar 4 years, 2 months ago

How are you ji

Shree Ram Faujdar 4 years, 2 months ago

Hello ji
  • 3 answers

Khushboo Gupta 4 years, 2 months ago

Question=tan^2(sec^-1 2 )+ cot^2 (cosec^-1 3) Solution= sec^2(sec^-1 2)-1+cosec^2(cosec^-1 3)-1 = 2^2×1+3^2-2 =11(answer)

Khushboo Gupta 4 years, 2 months ago

11 answer hai

Shree Ram Faujdar 4 years, 2 months ago

Ji kya likha hai kuch smj mein ni aya??
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  • 1 answers

Khushi Shahi 4 years, 2 months ago

By using formula tan(a+b)
  • 1 answers

Dhivya Shanthi 4 years, 2 months ago

853.58
  • 2 answers

Mishti ???? 4 years, 2 months ago

By practising more objective one because after knowing the subjective part or theory sometimes we r not able to do them because of lack of deep knowledge of concept & main the practise of such type s of questions?? U can find diffrent websites objective questions to make strong u'r practice. Hope it will help u ?? Regards. ??

Tannu Rao 4 years, 2 months ago

For this, u must have proper understanding of basic concepts bcoz 1 markers usually test our understanding of a particular topic. Also u must have enough practice to have speed and accuracy both.
  • 1 answers

Khushi Shahi 4 years, 2 months ago

ANSWER R={(x,y:x,y∈z,x−yisdivisiblebyn}ForReflexive,x∈zSo⇒(x−x)isdivisiblebyn⇒(x,x)∈z​ So, Relation is Reflexive ForSymmetric⇒Let(x,y)∈R⇒(x−y)isdivisiblebyn.⇒nx−y​=c,Remainderis0.⇒ny−x​=−c,Remainderisalso0.⇒(y−x)isdivisiblebyn(y,x)∈RSo,RisSymmetric.ForTransitive⇒Let(x,y)∈R&(y,z)∈R⇒(x−y)isdivisiblebyn⇒(y−q)isdivisiblebyn​ add both these equation (i) & (ii) (x−y)=xc,c∈z−v,(y−q)=na,(a∈z)⇒(x−y+y−q)=nc+na,c,a∈z⇒(x−q)=n(a+c),c,a∈z(x−q)isdivisiblebyn⇒(x,q)∈R​ So, R is Transitive So, the R is Reflexive, Symmetric and Transitive Then it is Equivalence Relation.
  • 1 answers

Suryakant Swain 4 years, 2 months ago

ln|secx|+c
  • 1 answers

Yogita Ingle 4 years, 3 months ago

Onto function could be explained by considering two sets, Set A and Set B, which consist of elements. If for every element of B, there is at least one or more than one element matching with A, then the function is said to be onto function or surjective function. The term for the surjective function was introduced by Nicolas Bourbaki.

  • 3 answers

Ashish Kumar Khosla 892026 4 years, 3 months ago

X^3

Ajay Kumar Meena 4 years, 3 months ago

X^3

Praduman Sharma 4 years, 3 months ago

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  • 2 answers

Gungun Arya Gupta 4 years, 2 months ago

Thanks for help

Gaurav Seth 4 years, 3 months ago

1. Understand the contents and weightage of the syllabus

Firstly, go through the latest CBSE Class 12th Maths syllabus 2020, where you will find the weightage of different units 

2. Preparation from NCERT textbooks is the most important part

Though supplementary books may be used as references, the NCERT textbooks offer an exhaustive range of exercise questions and solved examples on every topic, which is more than enough to do well in your board examinations.

3. Strategize and THEN prepare!

The long form questions (5-6 marks), which are the most feared aspect of a paper, usually come from one of the following sections:

  • Calculus, which carries a whopping 44% weightage, and can be really scoring
  • Differential Equations consisting of the application based difficult questions.
  • Vectors and 3D geometry carry the next highest 17% weightage.

The aforementioned topics are practice-based and the best way to gain perfection in them is to practice and solve more and more problems on them. Then,

  • Probability, Relations and Functions and Algebra have a weightage of 10%, 10% and 13% respectively.
  • Linear Programming: 6%

4. Practice sample papers and previous years’ papers

Examiners follow a pattern of repetition for specific important questions over a number of years, which is why it is very important to go through previous years’ papers.

Make sure that you solve the last few year’s papers on a timer, it will improve your speed, reasoning ability, and time management skills.

 

5. Say goodbye to rote learning!

Mathematics is all about understanding the concepts. So mugging up is not going to be of much help on the day of the examination.

Try to understand the fundamentals of the formulas; usually, they are all based on a single conceptual framework, and once you understand that, you can automatically do away with the mugging up of endless formulas.

 

6. Self-evaluation

As a step toward feeling less anxious, start by acknowledging your grey areas and your weaknesses.

Devote more time to improving them instead of making yourself feel bad about it. Maintaining a peaceful frame of mind is more significant than any preparation.

 

7. Presentation is very important

Neat work is a non-negotiable perk that always benefits a student. Make sure to label the graphs and figures properly.

Avoid overwriting and scribbling, if you’ve made a mistake then strike it off and start from below. Always leave some space between two questions, and start a new section on a fresh page.

 

8. Time management

The reading time is the most crucial and must be used judiciously. This involves reading the paper thoroughly, especially the ones involving statements, underlining keywords and then choosing the most scoring questions based on your understanding.

If you’re stuck on a question, leave some space and keep moving forward. You can revisit it later with a fresh mind.

Always keep 15-20 minutes buffer time for revising and rectifying your answers at the end.

  • 2 answers

Aman Bedi 4 years, 3 months ago

Ans is 24

Udit Thardak 4 years, 3 months ago

If x=3, than after putting value in equation Y= 27-9+2 = 20 Now taking derivative on both sides in equation dy/dx= 3x² At(3,20) dy/dx = 3(9)= 27 So slope of tangent in 27
Hch
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  • 1 answers

Gaurav Seth 4 years, 3 months ago

Given equations of a line is          ........ (i)

  • 1 answers

Tannu Rao 4 years, 3 months ago

If a function is continuous at a point then it means that limit exists at that point or LHL=RHL
  • 1 answers

Thakkar Dhruv 4 years, 3 months ago

1
  • 5 answers

Thakkar Dhruv 4 years, 3 months ago

36

Pragati Rai 4 years, 3 months ago

Hii

Rahul Moraingthem 4 years, 3 months ago

7(9)

Gayatri Guntreddi 4 years, 3 months ago

36

Manoj Meena 4 years, 3 months ago

36
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  • 1 answers

Arun Patel 4 years, 3 months ago

Int of y DC Limto 0 and 1 = int cos x dx lim 0 and 1
  • 1 answers

Mohit Mahra 4 years, 3 months ago

Hi
2.1
  • 0 answers

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