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  • 1 answers

Amritanshu Srivastav 5 years, 1 month ago

Minimum value is 3 at x=0.there is no maximum value
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  • 4 answers

Harsh Patel 5 years, 1 month ago

Mohit tyagi sir

Ankush Negi 5 years, 1 month ago

arpit Chaudhary

Ankush Negi 5 years, 1 month ago

neha agarwal vedantu math

Vivek Kumar 5 years, 1 month ago

Cengage books ?
  • 5 answers

Akanksha Kumari 5 years ago

Oswaal

Manvi Munpariya 5 years, 1 month ago

Both

Harshit Kabra 5 years, 1 month ago

Oswal solve paper

Mishti ???? 5 years, 1 month ago

Oswal is also a good choice dear it have chapter wise so many question to solve also previous year question also Regards. ??

Rakshit Kaushik 5 years, 1 month ago

Arihant is good for chapterwise questions and in sample papers most of the questions are similar in both books.
H
  • 1 answers

Shubham Sharma 5 years, 1 month ago

I
  • 1 answers

Shraddha ✨ 5 years, 1 month ago

Cos-¹(√3/2) = π - π/6 =5π/6
  • 1 answers

Udaya Kumar Mp 5 years, 1 month ago

R={(1,6),(2,7),(3,8)}

R is not reflexive,symmetric but it is transitive

  • 2 answers

Suryakant Swain 5 years ago

-ln|2sinx+cosx|+c

Xyz .. 5 years, 1 month ago

Take (2sinx + cosx) = t Differentiate both side w.r.t x d/dx(2sinx + cosx)=d/dx(t) 》2cosx - sinx = dt/dx 》》dx= dt/2cosx - sinx Now  I= ∫(2cosx - sinx/2sinx + cosx) dx This can be written as: I=  ∫(2cosx - sinx/t) dt/2cosx - sinx =  ∫1/t dt = log|t|+C = log|2sinx + cosx| +C
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  • 1 answers

Itzz Aayu 5 years ago

sin^2(A+B)=P^2/(1-q)^2+p^2 i think it will be correct.....
  • 3 answers

Nikhil Kumar 5 years, 1 month ago

f[1] = 1 f[1.2] = 1 f[1.9] = 1 f[1.99] = 1 Since different elements have same image 1 , f is not one - one CHECK ONTO , f(x) =[x] Let , y=f[x] y=[x] i.e , y= Greatest integer less than or equal to x . Hence , value of y will always come an integer . But y is a real number . Hence f is not onto

Shree Ram Faujdar 5 years, 1 month ago

How are you ji

Shree Ram Faujdar 5 years, 1 month ago

Hello ji
  • 3 answers

Khushboo Gupta 5 years, 1 month ago

Question=tan^2(sec^-1 2 )+ cot^2 (cosec^-1 3) Solution= sec^2(sec^-1 2)-1+cosec^2(cosec^-1 3)-1 = 2^2×1+3^2-2 =11(answer)

Khushboo Gupta 5 years, 1 month ago

11 answer hai

Shree Ram Faujdar 5 years, 1 month ago

Ji kya likha hai kuch smj mein ni aya??
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  • 1 answers

Khushi Shahi 5 years, 1 month ago

By using formula tan(a+b)
  • 2 answers

Mishti ???? 5 years, 1 month ago

By practising more objective one because after knowing the subjective part or theory sometimes we r not able to do them because of lack of deep knowledge of concept & main the practise of such type s of questions?? U can find diffrent websites objective questions to make strong u'r practice. Hope it will help u ?? Regards. ??

Tannu Rao 5 years, 1 month ago

For this, u must have proper understanding of basic concepts bcoz 1 markers usually test our understanding of a particular topic. Also u must have enough practice to have speed and accuracy both.
  • 1 answers

Khushi Shahi 5 years, 1 month ago

ANSWER R={(x,y:x,y∈z,x−yisdivisiblebyn}ForReflexive,x∈zSo⇒(x−x)isdivisiblebyn⇒(x,x)∈z​ So, Relation is Reflexive ForSymmetric⇒Let(x,y)∈R⇒(x−y)isdivisiblebyn.⇒nx−y​=c,Remainderis0.⇒ny−x​=−c,Remainderisalso0.⇒(y−x)isdivisiblebyn(y,x)∈RSo,RisSymmetric.ForTransitive⇒Let(x,y)∈R&(y,z)∈R⇒(x−y)isdivisiblebyn⇒(y−q)isdivisiblebyn​ add both these equation (i) & (ii) (x−y)=xc,c∈z−v,(y−q)=na,(a∈z)⇒(x−y+y−q)=nc+na,c,a∈z⇒(x−q)=n(a+c),c,a∈z(x−q)isdivisiblebyn⇒(x,q)∈R​ So, R is Transitive So, the R is Reflexive, Symmetric and Transitive Then it is Equivalence Relation.
  • 1 answers

Suryakant Swain 5 years ago

ln|secx|+c
  • 1 answers

Yogita Ingle 5 years, 1 month ago

Onto function could be explained by considering two sets, Set A and Set B, which consist of elements. If for every element of B, there is at least one or more than one element matching with A, then the function is said to be onto function or surjective function. The term for the surjective function was introduced by Nicolas Bourbaki.

  • 3 answers

Ashish Kumar Khosla 892026 5 years, 1 month ago

X^3

Ajay Kumar Meena 5 years, 1 month ago

X^3

Praduman Sharma 5 years, 1 month ago

  • 0 answers

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