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  • 1 answers

Amritanshu Srivastav 5 years, 3 months ago

Minimum value is 3 at x=0.there is no maximum value
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  • 4 answers

Harsh Patel 5 years, 3 months ago

Mohit tyagi sir

Ankush Negi 5 years, 3 months ago

arpit Chaudhary

Ankush Negi 5 years, 3 months ago

neha agarwal vedantu math

Vivek Kumar 5 years, 3 months ago

Cengage books ?
  • 5 answers

Akanksha Kumari 5 years, 2 months ago

Oswaal

Manvi Munpariya 5 years, 3 months ago

Both

Harshit Kabra 5 years, 3 months ago

Oswal solve paper

Mishti ???? 5 years, 3 months ago

Oswal is also a good choice dear it have chapter wise so many question to solve also previous year question also Regards. ??

Rakshit Kaushik 5 years, 3 months ago

Arihant is good for chapterwise questions and in sample papers most of the questions are similar in both books.
H
  • 1 answers

Shubham Sharma 5 years, 3 months ago

I
  • 1 answers

Shraddha ✨ 5 years, 3 months ago

Cos-¹(√3/2) = π - π/6 =5π/6
  • 1 answers

Udaya Kumar Mp 5 years, 3 months ago

R={(1,6),(2,7),(3,8)}

R is not reflexive,symmetric but it is transitive

  • 2 answers

Suryakant Swain 5 years, 3 months ago

-ln|2sinx+cosx|+c

Xyz .. 5 years, 3 months ago

Take (2sinx + cosx) = t Differentiate both side w.r.t x d/dx(2sinx + cosx)=d/dx(t) 》2cosx - sinx = dt/dx 》》dx= dt/2cosx - sinx Now  I= ∫(2cosx - sinx/2sinx + cosx) dx This can be written as: I=  ∫(2cosx - sinx/t) dt/2cosx - sinx =  ∫1/t dt = log|t|+C = log|2sinx + cosx| +C
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  • 1 answers

Itzz Aayu 5 years, 3 months ago

sin^2(A+B)=P^2/(1-q)^2+p^2 i think it will be correct.....
  • 3 answers

Nikhil Kumar 5 years, 3 months ago

f[1] = 1 f[1.2] = 1 f[1.9] = 1 f[1.99] = 1 Since different elements have same image 1 , f is not one - one CHECK ONTO , f(x) =[x] Let , y=f[x] y=[x] i.e , y= Greatest integer less than or equal to x . Hence , value of y will always come an integer . But y is a real number . Hence f is not onto

Shree Ram Faujdar 5 years, 3 months ago

How are you ji

Shree Ram Faujdar 5 years, 3 months ago

Hello ji
  • 3 answers

Khushboo Gupta 5 years, 3 months ago

Question=tan^2(sec^-1 2 )+ cot^2 (cosec^-1 3) Solution= sec^2(sec^-1 2)-1+cosec^2(cosec^-1 3)-1 = 2^2×1+3^2-2 =11(answer)

Khushboo Gupta 5 years, 3 months ago

11 answer hai

Shree Ram Faujdar 5 years, 3 months ago

Ji kya likha hai kuch smj mein ni aya??
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  • 0 answers
  • 1 answers

Khushi Shahi 5 years, 3 months ago

By using formula tan(a+b)
  • 1 answers

Dhivya Shanthi 5 years, 3 months ago

853.58
  • 2 answers

Mishti ???? 5 years, 3 months ago

By practising more objective one because after knowing the subjective part or theory sometimes we r not able to do them because of lack of deep knowledge of concept & main the practise of such type s of questions?? U can find diffrent websites objective questions to make strong u'r practice. Hope it will help u ?? Regards. ??

Tannu Rao 5 years, 3 months ago

For this, u must have proper understanding of basic concepts bcoz 1 markers usually test our understanding of a particular topic. Also u must have enough practice to have speed and accuracy both.
  • 1 answers

Khushi Shahi 5 years, 3 months ago

ANSWER R={(x,y:x,y∈z,x−yisdivisiblebyn}ForReflexive,x∈zSo⇒(x−x)isdivisiblebyn⇒(x,x)∈z​ So, Relation is Reflexive ForSymmetric⇒Let(x,y)∈R⇒(x−y)isdivisiblebyn.⇒nx−y​=c,Remainderis0.⇒ny−x​=−c,Remainderisalso0.⇒(y−x)isdivisiblebyn(y,x)∈RSo,RisSymmetric.ForTransitive⇒Let(x,y)∈R&(y,z)∈R⇒(x−y)isdivisiblebyn⇒(y−q)isdivisiblebyn​ add both these equation (i) & (ii) (x−y)=xc,c∈z−v,(y−q)=na,(a∈z)⇒(x−y+y−q)=nc+na,c,a∈z⇒(x−q)=n(a+c),c,a∈z(x−q)isdivisiblebyn⇒(x,q)∈R​ So, R is Transitive So, the R is Reflexive, Symmetric and Transitive Then it is Equivalence Relation.
  • 1 answers

Suryakant Swain 5 years, 3 months ago

ln|secx|+c
  • 1 answers

Yogita Ingle 5 years, 3 months ago

Onto function could be explained by considering two sets, Set A and Set B, which consist of elements. If for every element of B, there is at least one or more than one element matching with A, then the function is said to be onto function or surjective function. The term for the surjective function was introduced by Nicolas Bourbaki.

  • 3 answers

Ashish Kumar Khosla 892026 5 years, 3 months ago

X^3

Ajay Kumar Meena 5 years, 3 months ago

X^3

Praduman Sharma 5 years, 3 months ago

  • 0 answers

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