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Pankhuri Verma 8 years, 2 months ago

Take log of both sides n then do the differentiation
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Megha Goswami 8 years, 2 months ago

Feb
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Vaibhav Singh 8 years, 2 months ago

d/dx sin(3x+5) = cos(3x+5) *d/dx(3x+5) =3cos(3x+5)
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Vandit Jain 8 years, 2 months ago

Just substitute the value of x.... x= cos2A nd expand the formula of cos2A
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Gaurav Kumar 8 years, 2 months ago

Do +1 n -1 in numerator so it becomes 1- 1/(1+x^2) then integrate n finally X - tan^-(x)
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Anupam Singh 8 years, 2 months ago

Aggsgs
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Shristi Mourya 8 years, 2 months ago

cos 3x = -3cos sin2+cos3
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Prince Yadav 8 years, 2 months ago

Maximum time give to study
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Samir Kumar Basu 8 years, 3 months ago

{tex}\style{font-size:36px}{1.\;\;\;\int\frac{\cos5x+\cos4x}{1-2\cos3x}dx}{/tex}          {tex}\style{font-size:28px}{2.\;\;\;\int5^x.5^{5^x}.5^{5^{5^x}}dx}{/tex}   {tex}\style{font-size:28px}{3.\;\;\int\frac{\left(x+x^3\right)^{\displaystyle\frac13}}{x^4}dx}{/tex}

4. {tex}\style{font-size:36px}{\int\frac{dx}{x^{22}(x^7-6)}}{/tex}                    5.  {tex}\style{font-size:36px}{\int\frac{dx}{\sin(x-\alpha).\sin(x-\beta)}}{/tex}

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Saurabh Yadav 8 years, 3 months ago

Take help of videos to get better visual understanding??
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