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  • 2 answers

Amandeep Kumar 7 years, 2 months ago

There is nothing easy in this world

Albert Einstein 7 years, 2 months ago

No
  • 3 answers

Princesses Kaur 7 years, 2 months ago

-4

Deepak Jindal 7 years, 2 months ago

2(3)+5-(3)(5)= -4

G K 7 years, 2 months ago

2(3)+5-(3)(5)=-4
  • 2 answers

Jeetu Sharma 7 years, 2 months ago

Thnks

Aisha Gupta 7 years, 2 months ago

d/dx(sinx/sin(x-a)) =sin(x-a)d/dxsinx-sinxd/dxsin(x-a)/[sin(x-a)]² =sin(x-a)cosx-sinxcos(x-a)/[sin(x-a)]² =sin(x-a-x)/[sin(x-a)]² =-sina/[sin(x-a)]²
  • 4 answers

Akash Rounit 7 years, 2 months ago

Same

Tamoghna Roy 7 years, 2 months ago

Mera chal raha hai....

Deepak Jindal 7 years, 2 months ago

Mere bhi

Manan Bedi 7 years, 2 months ago

Me
  • 1 answers

Aisha Gupta 7 years, 2 months ago

(X-Y)e^x/x-y=a ->e^x/x-y=a/x-y Taking log both side we have. Log(e^x/x-y)=Loga/x-y ->x/x-y=loga-log(x-y) Now diff both side w.r.t x x-y-(1-dy/dx)x/(x-y)²=dy/dx-1/(x-y) ->-y+xdy/dx=(x-y)(dy/dx-1) ->-y+xdy/dx=xdy/dx-ydy/dx-x+y ->-y+ydy/dx+x=y ->ydy/dx+x=2y
  • 7 answers

Akash Rounit 7 years, 2 months ago

Only do exception or variation

G K 7 years, 2 months ago

Tell

G K 7 years, 2 months ago

Yell me in which year these Q. comes..Aisha

Aisha Gupta 7 years, 2 months ago

It is in cbse cyllabse and also these question has came several time in cbse exam. And it is done by same method as you have solved.

G K 7 years, 2 months ago

There is no simple function whose differentiation is root(tanx)....not in CBSE syllabus...

G K 7 years, 2 months ago

∫√(tan x) dxLet tan x = t^2⇒ sec2 x dx = 2t dt⇒ dx = [2t / (1 + t^4)]dt⇒ Integral ∫ 2t2 / (1 + t4) dt⇒ ∫[(t2 + 1) + (t2 - 1)] / (1 + t4) dt⇒ ∫(t2 + 1) / (1 + t4) dt + ∫(t2 - 1) / (1 + t4) dt⇒ ∫(1 + 1/t2 ) / (t2 + 1/t2 ) dt + ∫(1 - 1/t2 ) / (t2 + 1/t2 ) dt⇒ ∫(1 + 1/t2 )dt / [(t - 1/t)2 + 2] + ∫(1 - 1/t2)dt / [(t + 1/t)2 -2]Let t - 1/t = u for the first integral ⇒ (1 + 1/t2 )dt = duand t + 1/t = v for the 2nd integral ⇒ (1 - 1/t2 )dt = dvIntegral= ∫du/(u2 + 2) + ∫dv/(v2 - 2)= (1/√2) tan-1 (u/√2) + (1/2√2) log(v -√2)/(v + √2)l + c= (1/√2) tan-1 [(t2 - 1)/t√2] + (1/2√2) log (t2 + 1 - t√2) / t2 + 1 + t√2) + c= (1/√2) tan-1 [(tanx - 1)/(√2tan x)] + (1/2√2) log [tanx + 1 - √(2tan x)] / [tan x + 1 + √(2tan x)] + c

Vishwas Kheterpal 7 years, 2 months ago

Put tan x as square of t
  • 5 answers

G K 7 years, 2 months ago

I can understand..?

G K 7 years, 2 months ago

Ok

Akash Rounit 7 years, 2 months ago

I think , isse rt lo becoz same problem with me. Ok??

G K 7 years, 2 months ago

Yrr to hme kese pta chalega ki ye syllabus M h ya ni.......for ex. mujhe pahle ye pta ni tha ki root(sinx) ka integration ka answer simple form M h ya ni....mera kafi time waste hua....dekhne M to simple lagta h.....

Aisha Gupta 7 years, 2 months ago

Well I think rest ex are out of cbse syllabus but if u want to learn more then you have to concentrate on the methods and I think by solving tough question 3 to 4 times it automatically comes under memory.
  • 1 answers

Bharat Kumar 7 years, 2 months ago

- 2x/(1+x^2)^2
  • 0 answers
  • 5 answers

G K 7 years, 2 months ago

If u r preparing for IIT or any other engineering test then Cengage is best book .....It contains whole syllabus i.e. both class 11th and 12th.....for CBSE RD Sharma.....

Tushar Jaryal 7 years, 2 months ago

Is whole syllabus of maths is in 5 books of cengage

G K 7 years, 2 months ago

Maths : Cengage and RD Sharma,... Chemistry : Pradeep's and GRB...... Physics : Cengage and SL Arora.... And off course NCERT.....

Tushar Jaryal 7 years, 2 months ago

Which books do you (megha) for PCM

G K 7 years, 2 months ago

,∫ex2dx=∑n=0∞x2n+1(2n+1)n!.......there is no elementary function that describes the antiderivative of e^x^2......not in syllabus of CBSE.....
Ch2
  • 0 answers
  • 5 answers

G K 7 years, 2 months ago

No Aakash....its not correct.....let me tell u the answer....2[summation n->o to infinite {(2n)!sinx^2n+3/2} / 4^n (n!)^2 (4n+3)] +C

Akash Rounit 7 years, 2 months ago

First of all , consider t= since ,then she get dt/cosx= dxnow int root of rupon cosx ,1/cosx take out and solve she get 2/3cosx since ka power 3/2then as u written here since and root of sinx Unknown that sin2x =2sinxcosx then put finally u get sin2x/3 root of sinx Got it?????????

Tushar Jaryal 7 years, 2 months ago

Hmm..we can little bit solve it by substituting sinx as t sq. But whole is'nt possible.

G K 7 years, 2 months ago

Its not in syllabus......iska ans ajib sa h......

Yash Gupta 7 years, 2 months ago

-cosx + c
  • 0 answers
  • 4 answers

Rahul Singh 7 years, 2 months ago

2×2

Aman Patel 7 years, 2 months ago

The resulting matrix would be of the order 2cross2

Akash Pathak 7 years, 2 months ago

2x2

Akash Pathak 7 years, 2 months ago

2x
  • 2 answers

Rahul Singh 7 years, 2 months ago

r u mad ?

Abhi Shukla 7 years, 2 months ago

Circle has no volume it may be sphere which you mean to say .. volume of sphere is 4÷3pie r^3
  • 1 answers

Akash Rounit 7 years, 2 months ago

Equivalence relation contain symmetric ,transitive ,reflexive
  • 1 answers

Deepak Jindal 7 years, 2 months ago

X^2+y^2+2hx+2ky+c=0 A.T.Q Put x=4 and y=3.
  • 1 answers

Prashant Saini 7 years, 2 months ago

continuous function is a function for which sufficiently small changes in the input result in arbitrarily small changes in the output. Otherwise, a function is said to be a discontinuous function. A continuous function with a continuous inverse function is called a homeomorphism
  • 3 answers

Deepak Jindal 7 years, 2 months ago

????

Akshat Sharma 7 years, 2 months ago

?????

Deepak Jindal 7 years, 2 months ago

There is a given matrix. Then find co-factor. Then arrange in matrix form. Then you have to transpose of arrange matrix.. i.e..convert either rows to column or convert columns to rows. You will get adjoint of matrix..
  • 1 answers

Apar Chauhan 7 years, 2 months ago

Book 2 because of its main part integration

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