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  • 2 answers

Tushar Jaryal 7 years, 2 months ago

I think theory is enough from NCERT ....but you need to understand each and every line and but for the numericals you can also practice from other books as it will make your speed up and also increase your confidence level.......

Akshat Sharma 7 years, 2 months ago

No
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  • 3 answers

Medhavi Singh 7 years, 2 months ago

probability!!!!!!! Really fast ha....... ????

G K 7 years, 2 months ago

Vector 3D

Arslaan Panwar 7 years, 2 months ago

Probability
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  • 1 answers

Satyam Kumar 7 years, 2 months ago

Simply differentiate the equation you get 2x+x.dy/dx+y+2y.dy/dx=0 On solving the last you get dy/dx=-(2x+y)/x+2y
  • 7 answers

G K 7 years, 2 months ago

Sekhar.....I think u speak in english daily.....thatswhy u write very nicely....so much impressed....?....

G K 7 years, 2 months ago

Thnx shekhar.....but plzzzz dont write anything.....i dont like....sorry if u feel bad......

Vishnu Tiwari 7 years, 2 months ago

It came in the 12th class exam

Shrey Shekhar 7 years, 2 months ago

I see you helping a lot of people Megha Yadav (and tolerating their bullshit). You have a kind heart and I respect that. I am kinda jealous of your knowledge of things

G K 7 years, 2 months ago

(A-I)^3 + (A+I)^3 - 7A = A^3 - 3A^2 + 3A - I^3 + A^3 + 3A^2 + 3A + I^3 - 7A = 2A^3 + 6A - 7A = 2A^2 . A + 6A - 7A = 2I.A + 6A - 7A = 2A + 6A - 7A = 8A - 7A = A

G K 7 years, 2 months ago

For ex. ...2^4=16....2 to the power 4 is 16

Bhanu Behl 7 years, 2 months ago

What does ^ this sign mean?
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  • 2 answers

Ramesh Sahu 7 years, 2 months ago

log(1+sinx) /(2+sinx)

Nishchay Shakya 7 years, 2 months ago

Sinx ko t manlo uska differential hota h cosx fir to ho jayega
  • 3 answers

Srishti Khare 7 years, 2 months ago

Please answer somebody

Srishti Khare 7 years, 2 months ago

Yes

Jeetu Sharma 7 years, 2 months ago

Question is not clear........do u mean......(2x-4)√(4+3x-x^2)
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  • 5 answers

Medhavi Singh 7 years, 2 months ago

AOD?

Nidhi Katariya 7 years, 2 months ago

Tere ghnte ko tere pichwade me ghusa le

Bhanu Behl 7 years, 2 months ago

Tune kya ghnta lena

Jeetu Sharma 7 years, 2 months ago

Intigration

Nidhi Katariya 7 years, 2 months ago

In your's opinion
  • 4 answers

G K 7 years, 2 months ago

Why r u prooving urself as fool...

Aditi _Chouhan_ 7 years, 2 months ago

60 how simple it is...

Deepak Jindal 7 years, 2 months ago

Sixty(60) so simple???????????????

Priyal Rathi 7 years, 2 months ago

60
  • 1 answers

Tushar Jaryal 7 years, 2 months ago

1. In elecrical, to find power factor, 2. In mechanics, to find angle of repose, 3 In chemistry, to find bond angle.
  • 1 answers

Gaurav Jena 7 years, 2 months ago

because we cannot find the value of "c" as it is arbitrary constant with each diff. expressions its values changes and not fixed for one that's why its indefinite cuz we exactly tell the value of it
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  • 5 answers

Deepak Jindal 7 years, 2 months ago

No there is removal of value based question

G K 7 years, 2 months ago

Okk thanx....?

Akshat Sharma 7 years, 2 months ago

No it is confirm you can check

G K 7 years, 2 months ago

Really...I dont think so...

Akshat Sharma 7 years, 2 months ago

No board has removed value based questions thses year
  • 5 answers

Akshat Sharma 7 years, 2 months ago

Answer which i had written had some mistake just usko niche se upar pado to sahi he

Akshat Sharma 7 years, 2 months ago

Harsh. Since , e = - d (phi) / dt = 0. Phi = BACos(theta) [constant] B=munot n I [constant] For DC, I = CONSTANT That's why transformer.........................

Nidhi Katariya 7 years, 2 months ago

Tnx.

Saurabh Katoch 7 years, 2 months ago

Because transformer contains inductors and we know that for dc the inductive reactance has infinite value.That's why it cannot work on dc

Nidhi Katariya 7 years, 2 months ago

Sorry it's a physics question
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  • 1 answers

Dyhhj Fyjjjh 7 years, 2 months ago

I = Int.(0 - pie/2)Sin2x.log tanx dx.............(1) = Int.Sin2[(pie/2)-x].log tan[(pie/2) - x]dx = Int.(0 - pie/2)Sin2x.log Cotx.dx............(2) By Adding (1) and (2) 2I = Int.(0 - pie/2)Sin2x.[logTanx + logCotx]dx =Int.Sin2x.log[Tanx.Cotx]dx Int.Sin2x.log1dx Since Sin(2×pie/2)=Sinpie=0 》2I=0 》I=0(solved)
  • 2 answers

Gaurav Bansal 7 years, 2 months ago

∫√(tan x) dx Let tan x = t2 ⇒ sec2 x dx = 2t dt ⇒ dx = [2t / (1 + t4)]dt ⇒ Integral ∫ 2t2 / (1 + t4) dt ⇒ ∫[(t2 + 1) + (t2 - 1)] / (1 + t4) dt ⇒ ∫(t2 + 1) / (1 + t4) dt + ∫(t2 - 1) / (1 + t4) dt ⇒ ∫(1 + 1/t2 ) / (t2 + 1/t2 ) dt + ∫(1 - 1/t2 ) / (t2 + 1/t2 ) dt ⇒ ∫(1 + 1/t2 )dt / [(t - 1/t)2 + 2] + ∫(1 - 1/t2)dt / [(t + 1/t)2 -2] Let t - 1/t = u for the first integral ⇒ (1 + 1/t2 )dt = du and t + 1/t = v for the 2nd integral ⇒ (1 - 1/t2 )dt = dv Integral = ∫du/(u2 + 2) + ∫dv/(v2 - 2) = (1/√2) tan-1 (u/√2) + (1/2√2) log(v -√2)/(v + √2)l + c = (1/√2) tan-1 [(t2 - 1)/t√2] + (1/2√2) log (t2 + 1 - t√2) / t2 + 1 + t√2) + c = (1/√2) tan-1 [(tanx - 1)/(√2tan x)] + (1/2√2) log [tanx + 1 - √(2tan x)] / [tan x + 1 + √(2tan x)] + c

Shivam Sagar 7 years, 2 months ago

Let karo tanx ko t square
  • 1 answers

Aisha Gupta 7 years, 2 months ago

Y=log(1+tanx/2)/1-tanx/2 =>y=log[(cosx/2+sinx/2)/(cosx/2-sinx/2)]. =>y=log[(cosx/2+sinx/2)²/(cos²x/2-sin²x/2)] =>y=log(1+sinx)/cosx =>y=log(secx+tanx). Now diff w.r.t x dy/dx=secxtanx+sec²x/secx+tanx =>dy/dx=secx. =>dy/dx-secx=0
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  • 2 answers

Prashant Chaudhary 7 years, 2 months ago

First of all you take sin inverse x is first function and x is second function then use integration by parts.

G K 7 years, 2 months ago

Solve it by integration by parts.....

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