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x+y=60 => x=60-y Let S=xy³ S = (60-y)y³ S= 60y³-y⁴ dS/dy = 180y²-4y³ For max/min dS/dy =0 180y²-4y³=0 4y²(45-y)=0 Either y=0 ( not possible) Or y=45 (correct ✅ ) If we check by double differentiation then at y=45 it will be negative which means that value of function xy³ is maximum at y=45. And x+y = 60 (given) x = 60 - 45 = 15 Therefore two numbers are 15 and 45. THANK YOU!

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Laboratory manual class 12 answers

Posted by Jyothika P S 3 years ago

CBSE > Class 12 > Mathematics

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Vansh Bhardwaj 3 years ago

Cos2x / 2

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Parveen Dixit 3 years ago

Sin2x find in integration

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Math lab manual activity 11-20 solution class 12

Posted by Agnita Bal 3 years ago

CBSE > Class 12 > Mathematics

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Class 7exercise 8.1

Posted by Abhishek Yadav 3 years ago

CBSE > Class 12 > Mathematics

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Chapter 7exercise 8.1

Posted by Abhishek Yadav 3 years ago

CBSE > Class 12 > Mathematics

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Sanskar Singh 3 years ago

What

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real estate company is going to build a new residential complex. The land they have purchased can hold at most 4500 apartments. Also, if they make x apartments, then the monthly maintenance cost for the whole complex would be as follows: Fixed cost = ₹50,00,000. Variable cost = ₹(160x - 0.04x2) The maintenance cost as a function of x will be 5000000 5000000 + 160x - 0.04x2 160x - 0.04x2 None of these If C(x) denote the maintenance cost function, then the maximum value of C(x) occur at x = 2000 4500 5000 0 The maximum value of C(x) would be ₹4000000 ₹5160000 ₹5000000 ₹5225000 To practice more questions & prepare well for exams, download myCBSEguide App. It provides complete study material for CBSE, NCERT, JEE (main), NEET-UG and NDA exams. The number of apartments, that the complex should have in order to minimize the maintenance cost, is 5000 4500 1750 3500 If the minimum maintenance cost is attained, then the maintenance cost for each apartment would be ₹1000 ₹2000 ₹1091.11 ₹1200

Posted by Sudhanshu Rajput 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Mangalavathi.M David 1 year, 5 months ago

A real estate company is going to build a new residential complex. The land they have purchased can hold at most 4500 apartments. Also, if they make apartments, then the monthly maintenance cost for the whole complex would be as follows : Fixed cost . Variable cost Based on the above information, answer the following questions.

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in a forest a big tree got broken due to heavy rain and wind due to this rain the big branches ab and ac

Posted by Shrishti Singh 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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The function f(x) = x², for all real x, is A None of these B Neither decreasing nor increasing Decreasing C D Increasing

Posted by Ankush Arora 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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X(x-1)+1*1/3

Posted by Ibrahim Ibrahim Z 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Practical

Posted by Shashwat Lamba 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Archana Kumari 3 years, 1 month ago

Sin 3 pi by 4

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34 %85

Posted by Yash Aggarwal 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Does date sheet is realeased...or not

Posted by Tejesh Saini 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Vishwajeet Bhardwaj 3 years, 1 month ago

Yes

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Ranger King 3 years, 1 month ago

Released

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Can you pls give the solutions of sample question paper 1??

Posted by Divya Abraham 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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About matrices

Posted by Raunak Yadav 3 years, 1 month ago

CBSE > Class 12 > Mathematics

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Preeti Dabral 3 years, 1 month ago

In mathematics, a matrix is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, which is used to represent a mathematical object or a property of such an object.

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If, x=a secα ,y=b tanα then find d²y/dx²

Posted by Dark_ Eagle 3 years, 1 month ago

CBSE > Class 12 > Mathematics

2 answers

James Pradhan 3 years, 1 month ago

Solution :- x= a sec alpha , d(x)/d(alpha)=a sec alpha.tan alpha....(i) And y=b tan alpha, then, d(y)/d(alpha)= b sec²alpha ....(ii). Now we have to find, dy/dx={ dy/d(alpha)}/{dx/d(alpha)}=( bsec² alpha) /(asec alpha.tan alpha)=b/a sec alpha/tan alpha = b/a .1/cos alpha/sin alpha/ cos alpha = b/a .cosec alpha. Then d²/dx²= d(b/a.cosec alpha)/dx=b/a.(-cosec alpha.cot alpha).d(alpha)/ dx =-b/a.cosec alpha.cot alpha×1/dx/d(alpha)=-b/a.cosec alpha.cot alpha×1/a sec alpha.tan alpha=-b/a². 1/sin alpha.cot alpha×cos alpha×cot alpha=-b/a² cot³alpha (Ans.)

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Pallavi Prasad 3 years, 1 month ago

x=a secα dx = a secα tanα dα......(i) And y=b tanα dy = b sec²α dα.......(ii) Dividing both equations dy/dx= a/b cosecα Again differentiate wrt to x d²y/dx²= a/b (-cotα cosecα)×dα/dx = a/b(-cotα cosecα)×1/a secα tanα =-cot³α/b

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250)x 1-t² 1+t² 2t 1+t² y=

Posted by Dikshita Kochrekar 3 years, 1 month ago

CBSE > Class 12 > Mathematics