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y = |x + 3|
{tex} \Rightarrow y = \left( {x + 3} \right){/tex}, {tex}if\ x\geq-3{/tex}
y = -(x + 3), if x < -3
{tex}\int_{ - 6}^0 {\left| {x + 3} \right|dx = ?} {/tex}
Area {tex}= \int_{ - 6}^{ - 3} {-\left( {x + 3} \right)dx + \int_{ - 3}^0 {\left( {x + 3} \right)dx} } {/tex}
{tex}= \left[ {-\frac{x^2}{2}-3x} \right]_{-6}^{-3}+ \left[ {\frac{x^2}{2}+3x} \right]_{-3}^{0}{/tex}
{tex}= \left[ {(-\frac{9}{2}+9)-(-\frac{36}{2}+18)} \right]+ \left[ {(0+0)-(\frac{9}{2}-9)} \right]{/tex}
{tex}= \left[ {(\frac{9}{2}+0)+(0+\frac{9}{2})} \right]{/tex}
= 9 sq units

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If cosx^y+siny^x=k then find dy/dx

Posted by Oru Pavam Padippi 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Shreyansh Jain 6 years ago

Let cosx^y = u and cosy^x = v Taking log both sides y log (cos x) =log u and x log (cos y ) = log v Now , differentiating both sides .. Like this we will get du/dx & dv/dx u +v =k (as per our assumption ) Therefore , du/dx +dv/dx = 0 Now put the values of du/dx & dv/dx .. And you will get your ans

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F(x)=(sinx÷x)+cosx if x≠0 f(x)=2 if x=0 Find the continuity at x=0

Posted by Oru Pavam Padippi 6 years ago

CBSE > Class 12 > Mathematics

0 answers

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In integrals by partali fraction,how we equate the coffiecient and constant term to get the value of A and B.

Posted by Priyanshi Jaiswal 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Isha Raj 6 years ago

by comparing the coefficients with the given numerator

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In how many ways 5 rings of different types can be worn in 4 fingers

Posted by Dj . 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 6 years ago

Each ring can be worn on any of four fingers and this can be done in 5 ways.
Hence, the required number of ways = (4)⁵.

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What is the weightage of every chapter??

Posted by Shruti Omar 6 years ago

CBSE > Class 12 > Mathematics

2 answers

Anshul Sharma 6 years ago

It is around same for every chapter but you have to focus on calculas which is very important

1Thank You

Ujjwal Moral 6 years ago

Calculas is alone 45 marks

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Exercise 2.1

Posted by Bhwirab Mochahary 6 years ago

CBSE > Class 12 > Mathematics

0 answers

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Integration of sin x/1+sin x

Posted by Ankini Nema 6 years ago

CBSE > Class 12 > Mathematics

2 answers

Shikha Maurya 6 years ago

Sinx(1-sinx)/(1+sinx)(1-sinx) sinx-sinx^2/cosx^2 secxtanx-tanx^2 Secx-(secx^2-1) secx-(tanx-x) secx-tanx+x

1Thank You

Prince Maurya 6 years ago

Sinx\1+sinx*1-sinx\1-sinx= sinx -sin²x/cos²x=sinx\cos²x-sin²x\cos²x =

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Integration of sec x/sec x+tan x

Posted by Ankini Nema 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Vishakha Dhiman 6 years ago

Convert it into sin-cos......and then rationalise it

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If R is a relation from a non empty A to a non empty set B then

Posted by Prince Rathore 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Arisha Ashraf 6 years ago

Then R is a subset of A Cartesian product B

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Integrate y=(6x+4)^1/2 with limit x=0 to x=2

Posted by Shikha Maurya 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Tez Rez 6 years ago

Simply apply the rule of integration of (ax + b)^n

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Integrate e^ln(1+1/x^2)÷x^2+1/x^2

Posted by Shruti Nigam 6 years ago

CBSE > Class 12 > Mathematics

0 answers

ANSWER

If mode A = 3 then , what is mode adj A is equal to ?

Posted by Rajkumar Bansal 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Devashish Upadhyay 6 years ago

Adj A = 3 × A^-1

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Please give me intruction about kvpy exam.......

Posted by Pooja Bhakar 6 years ago

CBSE > Class 12 > Mathematics

0 answers

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Maths Activity of class 12 cbse

Posted by Isha Jamnal 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Archana Goel 6 years ago

Do it from ncert activities dowload the pdf and ask the ch from your teachers.

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Verify lagrange's mean theorem F(x)=e* on [0,1]

Posted by Sakshi Ranjan 6 years ago

CBSE > Class 12 > Mathematics

0 answers

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If root x+ root y=root a, prove that dy /dx=-whole root y/x

Posted by Rizwana Multani 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Arpita Sharma 6 years ago

1/2√x + 1/2√y * dy/dx = 0 1/2√x = -1/2√y * dy/dx dy/dx = -1/2√y /1/√x dy/dx = -√y/√x... Hence, proved

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If the diagonals of a parallelogram are equal then show that it is a rectangle

Posted by Saboor Ahmad 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 6 years ago

Given: The diagonals of a parallelogram are equal.

To prove: Parallelogram is a rectangle.
Proof : In {tex}\triangle{/tex}ACB and {tex}\triangle{/tex}BDA,
AC = BD . . . [Given]
AB = BA . . . [Common]
BC = AD . . . [Opposite sides of parallelogram]
{tex}\therefore{/tex} {tex}\triangle{/tex}ACB {tex}\cong{/tex}{tex}\triangle{/tex}BDA . . .[By SSS property]
{tex}\therefore{/tex} {tex}\angle{/tex}ABC = {tex}\angle{/tex}BAD . . . [c.p.c.t.] . . . .(1)
As AD || BC . . . [Opposite sides of parallelogram]
transversal AB intersects them.
{tex}\therefore{/tex} {tex}\angle{/tex}BAD + {tex}\angle{/tex}ABC = 180^o . . . [Sum of interior angle on the same side of a transversal] . . . .(2)
{tex}\angle{/tex}BAD = {tex}\angle{/tex}ABC = 90^o . . . [From (1) and (2)]
{tex}\therefore{/tex} {tex}\angle{/tex}A = 90^o
^{{tex}\therefore{/tex}}Parallelogram ABCD is a rectangle.