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  • 4 answers

Ron Vineetahuja 5 years, 11 months ago

Log X ka integration nhi hai derivative hai or woh hai 1/X dx

Anshu Dwivedi 5 years, 11 months ago

Xlogx -x +c

Chandra Kant Singh 5 years, 11 months ago

A trick#do according to "ILATE".

Ansh Preet 5 years, 11 months ago

Uh should multiply log x with 1 nd then integrate it with respect to dx by using product rule.. Answer is: xlogx-x+c
  • 1 answers

Anuradha Chhonkar 5 years, 11 months ago

It is the shape which having three adjacent side with respective angle of sum 180° .
  • 1 answers

Suman Gupta 5 years, 11 months ago

X-1/2-1=y-2/5-2=z+1/1+1 X-1/1=y-2/3=z+1/2 Since c lies in eq. =-1=-1=-1
  • 6 answers

Md Yousuf Ahmed Khan 5 years, 11 months ago

1/2

Ron Vineetahuja 5 years, 11 months ago

1/2

Kunal M 5 years, 11 months ago

10/20

Suman Gupta 5 years, 11 months ago

3/6

Areeba Nezam 5 years, 11 months ago

Sin 30'=1/2

Deeya Singh 5 years, 11 months ago

½
  • 1 answers

Shikha Maurya 5 years, 11 months ago

X^-1/2(x^3+3x+4) then multiply by x^-1/2 we get x^5/2+3x^1/2+4x^-1/2 now integrate it by using basic rule of integration
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  • 1 answers

Ashmeet Kaur 5 years, 11 months ago

X^3/(x^2+1)^3
  • 2 answers

Anshu Dwivedi 5 years, 11 months ago

Ans=- 2cosx/2+2sinx/2 +c

Ananya Mishra 5 years, 11 months ago

Put 1 as sin2x/2 + cos2x/2 and sinx as 2sinx/2cosx/2 then it will become (sinx/2+cosx/2) its whole square then the root will get removed and it will become integration of sinx/2+cosx/2 and now integrate it using basic rules
  • 2 answers

Ron Vineetahuja 5 years, 11 months ago

By ILATE

Aditya Jha 5 years, 11 months ago

Use the ILATE procedure
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  • 1 answers

Sia ? 5 years, 11 months ago

{tex}\frac{1}{x^{2}\left(x^{4}+1\right)^{\frac{3}{4}}}{/tex}
{tex}\int \frac{1 d x}{x^{2}\left(x^{4}+1\right)^{\frac{3}{4}}}{/tex}
Taking x4 common from denominator
{tex}=\int \frac{1 d x}{x^{2}\left(x^{4}\right)^{\frac{3}{4}}\left(1+\frac{1}{x^{4}}\right)^{\frac{3}{4}}}{/tex}
{tex}=\int \frac{d x}{x^{2}\left(x^{3}\right)\left(1+\frac{1}{x^{4}}\right)^{\frac{3}{4}}}{/tex}
{tex}=\int \frac{d x}{x^{5}\left(1+\frac{1}{x^{4}}\right)^{\frac{3}{4}}}{/tex}
{tex}\text { Let } t=1+\frac{1}{x^{4}}{/tex}
{tex}\frac{d t}{d x}=-\frac{4}{x^{5}}{/tex}
{tex}-\frac{d t}{4}=\frac{d x}{x^{5}}{/tex}
Substituting value of x and dx
{tex}=\frac{-1}{4} \int \frac{d t}{t^{\frac{3}{4}}}{/tex}
{tex}=\frac{-1}{4} \int t^{\frac{-3}{4}} d t{/tex}
{tex}=\frac{-1}{4} \int t^{\frac{-3}{4}} d t{/tex}
{tex}=\frac{-1}{4}\left[\frac{t^{\frac{-3}{4}}+1}{\frac{-3}{4}+1}\right]+C{/tex}
{tex}=-t^{\frac{1}{4}}+C {/tex}
{tex}=-\left(1+\frac{1}{x^{4}}\right)^{\frac{1}{4}}+c{/tex}

  • 1 answers

Miss Mor 5 years, 11 months ago

1-cosx=2sin^2x/2 1+cosx=2cos^2x/2 Integration 1-cosx/1+cosx dx =2tan^2x/2dx =2(sec^2x/2-1)dx =2Tanx/2×1/2-2x+c =tanx/2-2x+c
  • 1 answers

Ron Vineetahuja 5 years, 11 months ago

Which chapter
  • 1 answers

Mahender Singh 5 years, 11 months ago

Sin (x-c+c-c)=Sin (x+c-2c) After Sin (x-y) using formula
  • 1 answers

Om Shinde 5 years, 11 months ago

As per the ILATE rule x should be taken as 1st function and (sinx)^2 as second funtion. Then apply the formula of by parts and solve it. The final answer is :-) x^2/4 - xsin2x/4 - cos2x/8
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  • 3 answers

Harshvardhan Gupta 5 years, 11 months ago

Take first function as tanx and second as 1 Then apply by parts If any doubt then analyze the by-parts formula and procedure from maths book

Harshvardhan Gupta 5 years, 11 months ago

By by-parts 1.√tanx Take first function tanx and function 1 √tanx.integration of 1-integration(derivative of tanx.integration of 1) Then after the derivation substitute tanx=t^2 Then again apply by parts to solve tan inverse t^2

Aditya Kumar 5 years, 11 months ago

-log|cosx+C| or log|secx+C|
  • 1 answers

Kriti Kumari 5 years, 11 months ago

Let t=3x andthen integrate tan t
  • 1 answers

Piyush Mahajan 5 years, 11 months ago

-3/(x+1)^3
  • 1 answers

Khushi Singh 5 years, 11 months ago

A point where all lines makes contact with each other
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  • 1 answers

Harshvardhan Gupta 5 years, 11 months ago

Cosx(1+cosy)/siny(1+sinx)=dy/dx
  • 2 answers

Ron Vineetahuja 5 years, 11 months ago

Concern your teacher by telling your problems to them

Ishan G❤ 5 years, 11 months ago

Firstly you will write the all formulae of integration on a single paper then read it when u have a time From this integration is quite easy 4 u
  • 1 answers

Manas Mishra 5 years, 11 months ago

Sin(a-b)= sin a.cos b - cos a.sin b Sin(a+b)=sin a.cos b + cos a.sin b

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