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  • 2 answers

Noddy Dev 5 years ago

Yes right answer at the top

Jass . 5 years ago

When carboxylic acid (having alpha-hydrogen) reacts with Red P , X2 (X=F,Cl,Br,I) and water, then there is formation of alpha halogenated carboxylic acid. For eg. Ch3Cooh + Red P + Cl2 + H2O = ch2(cl)cooh
  • 2 answers

Devil ? 5 years ago

Very easy for bio students

Gourav Sharma 5 years ago

Ha ye chapter h chemistry me both chota sa chapter h aur khafi portion b reduce hua
  • 1 answers

Aayan Patel 5 years ago

Magnetic moment μ=n(n+2)​ where, n= Number of unpaired electrons i) Number of unpaired electrons in [CoF6​]3−=4 Magnetic moment =n(n+2)​=4(4+2)​=24​=4.9 BM
  • 1 answers

Yogita Ingle 5 years ago

Chemical Methods of Preparation of Colloids

Hydrophilic or Lyophobic colloidal solutions can be prepared by various chemical techniques such as:

  • Double Decomposition Technique: When hydrogen sulphide is passed through a solution of arsenious oxide in distilled water, we get a colloidal solution of arsenious chloride.

As2O3 + 3H2S → As2S3 +  3H2O

  • Oxidation Technique: A colloidal solution of Sulphur is made to pass through an aqueous solution of sulphur dioxide. It can also be obtained by passing the gas through a solution of an oxidization agent such as bromine water as well as nitric acid.

SO2 + 2H2S →  2H2O + 3S

H2S + [O] →  H2O + S

  • 4 answers

Gourav Sharma 5 years ago

Aur btao kya puchna h

Diksha Singh 5 years ago

Waise questions board ke ncert exercise me se hi aaenge kya

Gurneet Singh 5 years ago

Same here

Aditya Singh 5 years ago

Diksha if you want to learn conversions so learn all the named reactions in all chapters
  • 2 answers

Amrita Thakur 5 years ago

I have

Rajveer Chauhan 5 years ago

I have a notes
  • 3 answers

Himanshu Saini 5 years ago

All in one is the bestest book for theory and questions for boards...

Ni Na Atsuko 5 years ago

Xam idea Question bank

Aditya Singh 5 years ago

Moderns abc
  • 2 answers

Amrita Thakur 5 years ago

Octahedral voids -such voids are formed where triangular voids of second layer covers the triangular voids of first layer but apex of each is in opposite direction

Amrita Thakur 5 years ago

Tetrahedral voids- such voids are formed when a sphere of second layer covers the voids of first layer
  • 1 answers

Suraj Kumar 5 years ago

Chemical phenomena that occurs at interface of two surfaces.
  • 1 answers

Mk 10 5 years ago

Electrochemistry is the process of production of electricity from the energy released during spontaneous chemical reactions (or) using electrical energy to undergo a non-spontaneous reactions.
  • 1 answers

Sia ? 4 years, 7 months ago

SN1 • Polar solvent stabilizes transition state and carbocation intermediate. group. SN2 • Need polar solvent to dissolve nucleophile. Protic solvent slows rate by solvating nucleophile • Aprotic solvent increases rate by binding cation and thus freeing nucleophile.

  • 4 answers

Gourav Sharma 5 years ago

Dekho both easy h thoda sa socho aur answer mil jaye ga

Himesh Rawat 5 years ago

Ncert Book mai saaf saaf de rkha hai proper way mai

Yogita Ingle 5 years ago

Wurtz - Fitting reaction:
Aryl halide and alkyl halide couple in presence of sodium metal / dry ether to form alkyl benzene.
For example, bromobenzene reacts with methyl bromide in presence of sodium. dry ether to form toluene.
C6​H5​−Br+CH3​−Br+2Na  → dryether ​C6​H5​−CH3​+2NaBr

The basic diff. Is that in wurtz fittig rxn alkyl halide and aryl halide combine but in Fitting rxn both the compound which react are aromatic halide
  • 1 answers
Propene + HBr forms Ch3ch2ch2 -Br inthe presence of peroxide and Ch3ch2ch2-Br heat with KOH gives rise to Ch3ch2ch2OH Hope it's help u ??
  • 2 answers

Yogita Ingle 5 years ago

A ligand is an ion or molecule, which donates a pair of electrons to the central metal atom or ion to form a coordination complex. Ambidentate ligand is a type of ligands which have the ability to bind to the central atom via the atoms of two different elements.

Examples: thiocyanate ion(NCS) which can bind to the central metal atom or ion with either nitrogen or sulfur atoms.

If a ligand has more than 1donating site like in CN the bond can be formed from either C or N atom .so is the ambientate ligand.
  • 2 answers

Jassi Midha 4 years, 11 months ago

Deleted from syllabus
To find abnormal molar mass of a compound
  • 2 answers

Devil ? 5 years ago

Tentative dates aa gyi h
Hamara bhi abhi nahi huaa hai bahi
  • 3 answers

Aditya Singh 5 years ago

Due to absence of vacant d orbitals

Vansh Prajapati 5 years ago

Due to the absence of d orbital

Yogita Ingle 5 years ago

Nitrogen with n = 2 has s and p orbitals only. If does not have d orbitals to expand its valence shell. That is why it does not form pentahalide.

  • 1 answers
Those milecules/elements who have lone pair are electron donating grps. Alkyl are always electron donating .You can simply identify them in alliphatic molecules but the confusion arise in aromatic compound for example halogens are normally electron withdrawing but when connected in aromatic compound it act as electron donating. You can clear your confusion by just remembering 2 things:- 1. Halogens connected in aromatic compound are always E.D.G 2.any compound like (OCH3) in which Oxygen is more negative than carbon. If it is connected to ar.compound from Oxygen side (more -ve) than it will act as E.D.G as bcz carbon will try to repell the electrons.but if it is cnnctd through Carbon (less -ve) it will act as E.W.G bcz oxygen is nt directly connected to ar.ring so it will try to attract electrons Hope it will help 2 clear your confusion and remembering E.W.G and E.D.G
  • 1 answers

Rohit Kushwaha 5 years ago

Induced emf is directly proportional to rate of change of flux But induced emf is always in opposite directions e = - d(flux)/dt
  • 2 answers
With NH3 benzoic acid is converted to benzamide.

Yogita Ingle 5 years ago

Benzoicacid  reacts with NH3​ to form ammoniumsalt which on heating decomposes to form benzamide
Ph−COOH+NH3​ ⇌ Ph−COONH4+​Δ​PhCONH2​+H2​O

  • 1 answers

Mr. Singh 5 years ago

Aniline to benzene through phenol has only two steps. First, Aniline reacts with nitrous acid in room temperature. It gives phenol. Then phenol is distilled with zinc powder to give benzene.
  • 1 answers

Yogita Ingle 5 years ago

Convert benzene to methyl benzene by reacting it with CH3Cl and anhydrous AlCl3. Oxidize methyl benzene with a powerful oxidizing agent like alkaline KMnO4 we will get benzoic acid.

  • 1 answers

Yogita Ingle 5 years ago

Aniline is treated with sodium nitrite in Hydro-chloric acid at temperature 423K to form benzene diazonium chloride followed by hydrolysis by weak acid benzene .

Benzene is treated with  aluminium chloride to form toulene.

  • 2 answers

Aditya Singh 5 years ago

By passing aq koh
treat ethyl bromide with KCN it will form propanenitrile. add H2O in acidic med. it will become propanoic acid and now u can simply reduce propanoic acid it will form propanol
  • 1 answers

Yogita Ingle 5 years ago

Chemisorption involves high activation energy. So, first, it increases and then decreases with increase in temperature. The initial increase is due to the heat supplied which act as activation energy required for chemisorption. But later it decreases due to the exothermic nature of adsorption at equilibrium.

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