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    • Posted by Ayush Kumar Singh 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Susmita Das 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Ayush Kumar Singh 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Sia ? 6 years, 7 months ago

    Alcohols are versatile compounds. They react both as nucleophiles and electrophiles. The bond between O–H is broken when alcohol react as nucleophiles. The adjacent element or ion is the factor on which the property of alcohol depends .

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    • Posted by Ritika Yadav 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Ajit Sharma 6 years, 6 months ago

    Step I: Quantity of electricity Q= I x t

    I=1.5 A, t=1 hr = 60 x 60 s =3600 s

    Current efficiency 90 %, Q = (90/100) x 1.5 x 3600 s = 4860 C

    Zn2+ + 2e- ---------------> Zn

    Therefore, by applying Faraday law of electrolysis

    2F= 2 x 96500 C of electricity deposits = 1 mol of Zinc

    4860 C deposits                                 =  4860/(2 x 96500) mol of Zinc= 0.0252 mol of Zinc

    Step 2: Molarity = no.of moles of solute/ volume of solution in L

    0.25 = no.of moles of solute/500 x 10-3

    Therefore no. of moles of solute = 0.25 x 500 x 10-3 = 0.125 moles

    Therefore no. of moles Zn+ left = (0.125-0.0252) moles= 0.0998 moles

    Hence req. molarity = 0.0998 /(500 x 10-3) = 0.1996 M

     

    Alternatively

    equivalent of .of Zn2+ lost  = 4860/96500=0.0504 eq

    Therefore meq of Zn2+ lost = 0.0504 x 103=50.3

    Initial meq of Zn2+ = 500 x 0.25x 2= 250 meq (500 mL of 0.25 M solution)

    Hence meq of Zn2+ remains in the solution = (250 - 50.3) meq =199.7 meq

    Therefore molarity of the remaining solution = 199.7/(2 x500) M= 0.1997 M

     

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    • Posted by William Basumatary 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Shubham Garg 6 years, 7 months ago

    Catalyst act as intermediate and help to decrease lower activation energy so that no. Of reacting molecules increase to change the product

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    • Posted by Honey Singh 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    ꧁≪Mämƭå ℭℏ۝ᑌĎℎàℜÿ? 6 years, 7 months ago

    This is because a catalyst speeds up the forward and backward reaction to the same extent and adding a catalyst does not affect the relative rates of two reactions, it cannot affect the position of equilibrium.

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    • Posted by William Basumatary 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    ꧁≪Mämƭå ℭℏ۝ᑌĎℎàℜÿ? 6 years, 7 months ago

    Where is the reaction ?

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    • Posted by Arman Sidhu 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 5 answers

    Arman Sidhu 6 years, 6 months ago

    Yeah mere schl mein bhe padhaya geya he ...ye

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    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    no it's not in the syllabus.... but shayeed meri terh tumhare schl mein bhe ye padhaya jayega vo bhe forcefully.... ? ? ?

    3Thank You

    ꧁≪Mämƭå ℭℏ۝ᑌĎℎàℜÿ? 6 years, 7 months ago

    Nahi he, check the official cbse website, both the solid state and group 15 from p block has been deleted.

    1Thank You

    Deepak Jindal 6 years, 7 months ago

    Yess.............any doubt??????

    2Thank You

    Sachin Yadav 6 years, 7 months ago

    Yes h

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    • Posted by Ravi Kant Shahi 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Siya Jain 6 years, 7 months ago

    Methanoic acid

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    Sia ? 6 years, 7 months ago

    IUPAC name of the HCOOH is methanoic acid.

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    • Posted by Manu Gahlot 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Ravi Kant Shahi 6 years, 7 months ago

    No

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    • Posted by Sachin Pandey 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Ravi Kant Shahi 6 years, 7 months ago

    By making hydrogen bonding

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    • Posted by Abhyash Kumar 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Sia ? 6 years, 7 months ago

    There are mainly four types of ores such as Oxides; Carbonate Ores; Sulphide; Halides Ores.

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    • Posted by Ankita Pant 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Saleheen Ali 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Sia ? 6 years, 7 months ago

    Given, Molarity of solution, M = 2 mol L-1
    Mass of NaCl in 1 L solution = 2 {tex}\times{/tex} 58.5 = 119.0 g
    Mass of 1 L solution = Volume x density of solution = 1000 mL {tex}\times{/tex} 1.2 g/mL = 1200 g      (since density = 1.2 g mL-1 )
    Mass of water solution = 1200 -119.0 = 1081 g = 1.081 kg.
    Now, Molality of solution = {tex}\frac { \text { number of moles of solute } } { \text { mass of solvent in } \mathrm { kg } }{/tex}  = {tex}\frac { 2 \mathrm { mol } } { 1.081\mathrm { kg } } = 1.85\mathrm { m }{/tex}.

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    • Posted by Gracie Lauren 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Gracie Lauren 6 years, 7 months ago

    Thanks a lot to u

    0Thank You

    Sia ? 6 years, 7 months ago

    Initial amount = 5 g
    Final amount = 3 g
    Rate constant = 1.15 × 10-3 s-1
    For a 1st order reaction:

    {tex}t = \frac{{2.303}}{k}\log \frac{{{{\left[ R \right]}_0}}}{{\left[ R \right]}}{/tex}
    {tex} = \frac{{2.303}}{{1.15 \times {{10}^{ - 3}}}}\log \frac{5}{3} = \frac{{2.303}}{{1.15 \times {{10}^{ - 3}}}} \times 0.2219{/tex}

    = 444.38 s or 444 s (approx).

    1Thank You

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    • Posted by Meghna Shrivastav? 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    ꧁≪Mämƭå ℭℏ۝ᑌĎℎàℜÿ? 6 years, 7 months ago

    AlCl3---- Al + 3Cl here @= alpha ---degree of dissociation @= 0.5 since. Vant hoff factor = observed number of moles divvided by normal number of moles Initial number ofmoles---- 1,0,0. Final number of moles ----alcl3 = 1-@. Al= @. 3cl= 3@. i=[1-@+@+3@]. i=[1+3@]. i= 1+(3*0.5). i= 2.5

    1Thank You

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    • Posted by Utpal Nath 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Sia ? 6 years, 7 months ago

    In [CO(NH3)6]3+ oxidation state of CO = +3
    Configuration = 3d6
    In presence of NH3, 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital complex.
    In [Ni(NH3)6]2+
    Oxidation state = +2. Electronic configuration = 3d8. In presence of NH3, 3d electrons do not pair up. The hybridization involved is sp3d2and forming an outer orbital complex.

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    • Posted by Ashu Baghel 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Aman Kumar 6 years, 7 months ago

    Hmm...nicely explained...thanks?? Darshanaaa....

    1Thank You

    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    so here we go we have toluene so to obtain our final product which is chlorobenzene we have to obtain benzene first to obtain benzene from toluene we will react toluene with acidic KMNO4 ➡️we will get Benzoic acid. now treat it with Sodium we will get sodium benzoate  and benzene will get as a by product. ✴️ now treat benzene with Chlorine gas in the presence of anhydrous AlCl3 we will successfully get chlorobenzene and HCL as a by product.

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    • Posted by Riya Soni 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 10 answers

    Aman Kumar 6 years, 7 months ago

    Sahi kha...?...but 3-4 days k baad hamara ek aur account hai...jo wapas unblock ho jaega...so we can again come back here......but I'll try not talk faltu things here....?

    0Thank You

    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    Hahaha we both gonna block soon be ready... ? ? ?

    1Thank You

    Aman Kumar 6 years, 7 months ago

    So nice of u darshu??

    1Thank You

    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    tumhe Jo bolna hai bol lo..... BTW comprehensive books are also gud... but I didn't use them yet. ? ?

    1Thank You

    Aman Kumar 6 years, 7 months ago

    Sorry, ager tumhe bura laga ho...?..then mai nhi bolunga??

    1Thank You

    Aman Kumar 6 years, 7 months ago

    Hey, darshu....what about comprehensive book.....ooh kya mai tumhe darshu..bol sakta hu...

    0Thank You

    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    dekho were zarrort hogi ni download Kerne ki apke pass ager pradeep ya modern hai unke extra questions mein sare aaye hue question he hote hai question ke saath vaha question kis year mein aaya tha kis region mein aaya tha konse set mein aaya tha puri details hoti hai....

    2Thank You

    Aman Kumar 6 years, 7 months ago

    Ya u can download from there...aur check it to some other website

    1Thank You

    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    ya from vedantu website u can download

    2Thank You

    Aman Kumar 6 years, 7 months ago

    U can better search in google....becz...this aap does not contain chapterwise 5 years queations...

    1Thank You

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    • Posted by Femina Raj 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Gracie Lauren 6 years, 7 months ago

    A mercury battery (also called mercuric oxide battery or mercury cell ).is non rechargeable electrochemical cell , primary cell. Or u can say it as a new type of dry cell.. Anode : zinc - mercury Cathode : paste of Hgo and carbon Electrolytes : paste of Zno in KOH

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    • Posted by Ude Gill 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Anisha Anaya 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Sia ? 6 years, 7 months ago

    Antacids such as sodium hydrogen carbonate, magnesium hydroxide, and aluminium hydroxide work by neutralising the excess hydrochloric acid present in the stomach. However, the root cause for the release of excess acid remains untreated.

    Cimetidine and rantidine are better antacids as they control the root cause of acidity. These drugs prevent the interaction of histamine with the receptors present in the stomach walls. Consequently, there is a decrease in the amount of acid released by the stomach. This is why cimetidine and rantidine are better antacids than sodium hydrogen carbonate, magnesium hydroxide, and aluminium hydroxide.

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    • Posted by Ritika Raj 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Vaibhav Kaushik 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Tapan Pandey?? 6 years, 7 months ago

    Rate of reaction depends only on rate constant of that reaction R=k

    2Thank You

    Yogita Ingle 6 years, 7 months ago

    A reaction is said to be of zero order if its rate is independent of the concentration of the reactants, i.e., the rate is proportional to the zeroth power of the concentration of the reactants.

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    • Posted by Nitish Rathor 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Ashish Kumar 6 years, 7 months ago

    If any point work in against to electric field that carries the potential. And that point compared and point and these difference is "potential difference " .

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    Tripti Rawat 6 years, 7 months ago

    The difference of electrical potential between two points.

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    • Posted by Arinjay Aggarwal 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
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    • Posted by Deepanshu Rajput 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 0 answers
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    • Posted by Meghan Bhangale 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Sia ? 6 years, 7 months ago

    Thionyl chloride is preferred for preparing alkyl chlorides from alcohols because the by-products formed in the reaction are SO2 and HCl which are in gaseous form and escape into the atmosphere leaving behind pure alkyl chlorides.

    1Thank You

    Yogita Ingle 6 years, 7 months ago

    Alcohols on tratment with Sulphonyl Chloride[SOCl2](most preferrable) gives haloalkanes !

    CH3CH2OH + SOCl2 →  CH3CH2Cl + SO2 + HCl

    The Separation of the Haloalkane & Hydrogen chloride & Sulpher di-oxide are easier because SOCl2 & HCl are volaitle !!

    Thus this is the generally eaier way to prepare Haloalkanes

    1Thank You

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    • Posted by Shashikala Singh 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Ashish Kumar 6 years, 7 months ago

    If you calculate standards cell potential any metal So make a cell madeup of these metal at anode side ande H2 a located at cathode side at presences of Pt and calculate the cell potential (let H2 potential is zero ) . these cell potential is the standards cell potential of metal . OK

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    • Posted by Ashutosh Kumar 6 years, 7 months ago

    CBSE > Class 12 > Chemistry
    • 2 answers

    Yogita Ingle 6 years, 7 months ago

    The movement of water from a region of high concentration to a region of low concentration through a semi permeable membrane is known as osmosis.

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    Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

    The phenomenon of flow of solvent molecules through a semi permeable membrane from pure solvent to solution is called osmosis.

    2Thank You

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