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Ask QuestionPosted by Sanjay Vajpayee 6 years, 6 months ago
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Ďãřşháñăã Yadav ? ? ? 6 years, 6 months ago
Posted by Simmi Sharma 6 years, 6 months ago
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Ajit Sharma 6 years, 6 months ago
Volume of the solution = Mass of the solvent + Mass of the solute
= 200 g + 20 g = 220 g
Density of the solution = Mass of the solution/ Volume of the solution
1.25 g / mL = 220/ volume of the solution
Volume of the solution = 220 / 1.25 = 176 ml
Normality of the solution = no. of gram equivalent of solute /volume of the solution in L
= (20/49) / (176 x 10-3) N = 2.32 N
( Equivalent Mass of Sulfuric Acid is 49 g )
Posted by Muskan Birhman 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Propyne is CH3-C=-CH
CH3-C=CH + Hg2+ + H2O {tex}\rightarrow{/tex} CH3-CO-CH3
CH3-CO-CH3 + LiAlH4 {tex}\rightarrow{/tex} CH3-CH(OH)-CH3 (2-propanol)
CH3-CH(OH)-CH3 + H2SO4 + H2O {tex}\rightarrow{/tex} CH3-CH=CH2 (propene)
CH3-CH=CH2 + BH3 + H2O2/OH- {tex}\rightarrow{/tex} CH3-CH2-CH2OH
This is hydroboration oxidation
CH3-CH2-CH2OH + PCC {tex}\rightarrow{/tex} CH3-CH2-CHO (propanal)
Posted by Ramneet Sekhon 6 years, 6 months ago
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Amit Yadav 6 years, 6 months ago
Posted by Arman Arora 6 years, 6 months ago
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Hemant Tiwari 6 years, 6 months ago
Posted by Pandia Raj 6 years, 6 months ago
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Arjita Singh 6 years, 6 months ago
Posted by Ďãřşháñăã Yadav ? ? ? 6 years, 6 months ago
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Jasnoor Grewal 6 years, 6 months ago
Posted by Aman Kumar 6 years, 6 months ago
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Ďãřşháñăã Yadav ? ? ? 6 years, 6 months ago
Aman Kumar 6 years, 6 months ago
Ďãřşháñăã Yadav ? ? ? 6 years, 6 months ago
Ďãřşháñăã Yadav ? ? ? 6 years, 6 months ago
Posted by Saleheen Ali 6 years, 6 months ago
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Ajit Sharma 6 years, 6 months ago
Molal depression constant of water (Kf ) = 1.86 K kg mol-1
Density of water = 1 g / cc = 1 kg / L
Given ,Volume of water = 1 L
Therefore mass of water = 1 kg
Freezing point = -20oC = ( 273-20) K= 253 K
Freezing point of water = 273 K
Hence, depression in freezing point = Kf x m (m= molality )
(273-253) K = 1.86 K kg mol-1 x (moles of ethyl alcohol) /mass of solvent in kg
20 = 1.86 x ( moles of ethyl alcohol) / 1 Kg
moles of ethyl alcohol = 20/1.86 = 10.753 mol
Mass of 10. 753 mol of ethyl alcohol = 46 x 10.753 g = 494.638 g.
So , more than 494.638 g will be added to lower the freezing point.
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Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
fat is the dispersed phase and water is the dispersion medium.
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Aerosol
Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants and smoke.
Posted by Abhishek Pandey 6 years, 6 months ago
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Posted by Abhishek Pandey 6 years, 6 months ago
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Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
The stability of lyophilic sols is a result of two factors, the presence of a charge and the solvation of colloidal particles. On the other hand, the stability of lyophobic sols is only because of the presence of a charge. Thus, the lyophilic sol is more stable than lyophobic sol due to the extensive solvation.
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
The Brownian movement arises due to the unbalanced bombardment of particles by the molecules of the dispersion medium. The Brownian movement has a stirring effect which does not permit the particles to settle and thus, is responsible for stability of sols.
Aman Kumar 6 years, 6 months ago
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Gelatin is used in ice cream to give it a soft texture and fresh appearance. Only a little bit of gelatin is enough to make our ice creams soft and fresh. Gelatin absorbs free water in the ice cream and prevent the formation of large crystals. It also gives the less watery taste to an ice cream.
Ashish Singh 6 years, 6 months ago
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
As we know artificial rainfall occurs when oppositely charged clouds meets. Since, clouds are colloidal in nature and carry charge. Spray of silver iodide, an electrolyte from aeroplane results in coagulation of colloidal water particles leading to rain. Sometimes electrified sand is also used for this purpose.
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Gold sol is a solvent repelling sol i.e., a lyophobic sol and unstable in nature. Addition of gelatin stabilises the gold sol because gelatin forms lyophilic sol and act as a protective colloid.
Posted by Nidhi Brar 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Get last year papers here : <a href="https://mycbseguide.com/cbse-question-papers.html">https://mycbseguide.com/cbse-question-papers.html</a>
Posted by Honey Singh 6 years, 6 months ago
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Posted by Honey Singh 6 years, 6 months ago
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Abhishek Pandey 6 years, 6 months ago
#¥Uvi Rana Rajput 6 years, 6 months ago
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Posted by Solly Yadav 6 years, 7 months ago
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Sia ? 6 years, 6 months ago
Steps
- Separate the characteristic and the mantissa. Consider the number under observation.
- Use the antilog table to find a corresponding value for your mantissa.
- Find the value from the mean difference columns.
- Add the values obtained in the previous steps.
- Insert the decimal point
Posted by Sunidhi Yadav 6 years, 7 months ago
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Gursharn Kaur 6 years, 6 months ago
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Tarun Jakhar 6 years, 7 months ago
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Tarun Jakhar 6 years, 7 months ago
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Ďãřşháñăã Yadav ? ? ? 6 years, 7 months ago

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Sia ? 6 years, 6 months ago
Rate of a reaction depends upon the concentration of the reactant as the concentration of the reactant decreases , the rate also decreases. As a result, for the reactant, the rate is indicated by a negative sign .
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