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  • 2 answers

Anjan Karthi 2 years, 3 months ago

Freon - 12 → CCl2F2.

Robert Haokip 2 years, 3 months ago

Chemical formula of freon
  • 1 answers

Y S 2 years, 3 months ago

Simple form of protein
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Karan Verma 2 years, 3 months ago

Transition elements
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  • 5 answers

Aseem Mahajan 2 years, 3 months ago

<font face ="Times New Roman">Subtraction is so wrong . Take 10²¹ common and than subtract. For accuracy use NA= 6.02×10²³

Account Deleted 2 years, 3 months ago

There is a mistake in division(line 2 ) 2/440 =220 but after doing this still I am not getting answer ...

Account Deleted 2 years, 3 months ago

Twenty three*

Account Deleted 2 years, 3 months ago

Yes because I had substrated 10 from 10 ^23 twenty three you see once again.....

Aseem Mahajan 2 years, 3 months ago

<font face ="Times New Roman">Line 20, denominator was 110
  • 1 answers

Anjan Karthi 2 years, 2 months ago

Haloalkanes have higher boiling points than their corresponding alkanes as haloalkane molecules are connected to each other by dipole interactions that are relatively stronger than the London forces between alkane molecules
  • 3 answers

Akshay Haldua 2 years, 2 months ago

It is E°cell

Anjan Karthi 2 years, 2 months ago

An instrument used to determine the standard reduction potentials of other elements and complexes. It is made up of a platinum metal rod (which adsorbs and thereby, holds H molecules on its surface) dipped in acidified water. For this hydrogen is assumed to be of Eo = 0. When connected to material whose Eo has to be found out. Then, the Eo is found out by equation Eo (cell) = Eo (cathode) - Eo (anode). Eo (cell) is found experimentally and if hydrogen electrode undergoes oxidation, it is anode and if it undergoes reduction, it is cathode.

Y S 2 years, 3 months ago

Represented by Eo
  • 1 answers

Aseem Mahajan 2 years, 3 months ago

<font face ="Times New Roman">What project?
  • 1 answers

Priyanshu Tiwari 2 years, 3 months ago

Gupta
  • 1 answers

Anjan Karthi 2 years, 2 months ago

Phenol, on reaction with chloroform and sodium hydroxide, gives Salycaldehyde.
  • 1 answers

Anjan Karthi 2 years, 2 months ago

Some times, the solute molecules, on dissolving in the solution, may undergo association or dissociation resulting in a net change in the quantity of solute particles in the solution. This can affect the value of colligative properties and thereby, the values of molar masses too. This is called ABNORMAL MOLAR MASS.
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Divya. Kumari 2 years, 3 months ago

Ya!! Asked
  • 1 answers

Y S 2 years, 3 months ago

Halogens are 17th group elements of periodic table that are cl f Br I ...
  • 1 answers

Anjan Karthi 2 years, 2 months ago

During resonance stabilisation, the ortho and para positions of the benzene ring with respect to the carboxy group attains momentary positive charges. Thus, the meta position is RELATIVELY favourable for incoming electrophilic substitutions in benzoic acid.
  • 1 answers

Ayush Singh 2 years, 3 months ago

1: It is used in the calculation of absolute ionic mobilities. 2: It is used in the Molar conductance of weak electrolyte at infinite dilution. 3: It is used in the calculation of degree of dissociation (alpha) of a weak electrolyte. Thank you 😊
  • 2 answers

Ayush Singh 2 years, 3 months ago

Or 7.23 × 10²³.

Ayush Singh 2 years, 3 months ago

Number of atoms in 0.4 mole of compound = 0.4 x 6.022 x 10²³ = 2.4088 x 10²³ Number of octahedral voids = Number of atoms in close packing = 2.4088 x 10²³ Number of terahedral voids = 2 x No. of atoms in close packing = 2 x 2.4088 x 10²³ = 4.8176 x 10²³ Total number of voids = 2.4088 x 10²³ + 4.8176 x 10²³ = 7.2264 x 10²³. Thank you 😊
  • 1 answers

Lakshmi Ramesh 2 years, 3 months ago

Single Nucleophile which have two nucleophlic centre are called ambident Nucleophile. NCS -AND SCN-. In this sulphur or nitrogen will be the nuclophilic centre
  • 1 answers

Wagisha Singh 2 years, 1 month ago

10.1 Write structures of the following compounds: (i) 2-Chloro-3-methylpentane (ii) 1-Chloro-4-ethylcydohexane (iii) 4-tert. Butyl-3-iodoheptane (iv) 1,4-Dibromobut-2-ene (v) 1-Bromo-4-sec. butyl-2-methylbenzene. Ans: 
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Ritumoni Borgohain 2 years, 4 months ago

Vapour pressure of water,P1​=23.8 m of hg The weight of water=850 g        The weight of Urea=50 g  The molecular weight of water(H_2O)=1×2+16=18 g mol−1 molecular weight of urea (NH2​CONH2​)=2N+4H+C+O=2×14+4×1+12+16=60 g mol−1 Use formula            number of moles=molar massmass​ number of moles of water   n1​=18850​=47.22 number of moles of urea   n2​=6050​=0.83 Now, we have to calculate the vapour pressure of water in the solution. we take vapour pressure as P1​.         Use the formula of Raoult's law       P10​P10​−P1​​=n1​+n2​n2​​ plug the values we get 23.823.8−P1​​=47.22+0.830.83​ 23.823.8−P1​​=0.0173 23.8−P1​=23.8×0.0173 P1​=23.4 m Hg Vapour Pressure of water in the given solution=23.4 mm of Hg Relative lowering=0.0173
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Ritumoni Borgohain 2 years, 4 months ago

The stability of coordination compounds in solution means the degree of association between the metal ion and the ligands involved in the state of equilibrium. Quantitatively, the stability is expressed by the equilibrium constant for the association. Factors affecting the stability of a complex ion: (a) The nature of the central metal atom (1) Charge on the central metal ion (2) Size of metal ion (3) Electronegativity or charge distribution of metal ion (4) Chelate effect (5) Macrocylic effect (b) The nature of the ligand (1) Basic strength (2) Size and charge of ligands

Ritumoni Borgohain 2 years, 4 months ago

  Use app Login Class 12 >>Chemistry >>Coordination Compounds >>Stability of Coordination Compounds >>What is meant by stability of a coordina Question  What is meant by stability of a coordination compound in solution? State the factors which govern stability of complexes. Hard Open in App Solution  Verified by Toppr The stability of coordination compounds in solution means the degree of association between the metal ion and the ligands involved in the state of equilibrium. Quantitatively, the stability is expressed by the equilibrium constant for the association. Factors affecting the stability of a complex ion: (a) The nature of the central metal atom (1) Charge on the central metal ion (2) Size of metal ion (3) Electronegativity or charge distribution of metal ion (4) Chelate effect (5) Macrocylic effect (b) The nature of the ligand (1) Basic strength (2) Size and charge of ligands
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