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Aarish Adhitya 3 years ago

The unknown take as x if the complex is neutral form an algebraic sum of all metal and ligands change find the x value
  • 1 answers

Anjan Karthi 3 years ago

Λm = Λ°m - A√C
  • 1 answers

Y S 3 years, 1 month ago

We have to learn 1st Afbau Rule
  • 5 answers

Renu Pandey 3 years ago

Shei is reading book since 2'0 clock.

Anushka Kumari 3 years ago

She has been reading the book since 2 o'clock

Y S 3 years, 1 month ago

SHE GAS BEEN READING THE BOOK SINCE TWO'O CLOCK

M. Ajay 3 years, 1 month ago

She has been reading the book since 2 a clock

Account Deleted 3 years, 1 month ago

she has been reading the book since two o'clock...
  • 1 answers

Aarish Adhitya 3 years ago

They weak electrolyte
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  • 2 answers

Anjan Karthi 3 years, 1 month ago

Freon - 12 → CCl2F2.

Robert Haokip 3 years, 1 month ago

Chemical formula of freon
  • 1 answers

Y S 3 years ago

Simple form of protein
  • 1 answers

Karan Verma 3 years ago

Transition elements
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Aseem Mahajan 3 years, 1 month ago

<font face ="Times New Roman">Subtraction is so wrong . Take 10²¹ common and than subtract. For accuracy use NA= 6.02×10²³

Account Deleted 3 years, 1 month ago

There is a mistake in division(line 2 ) 2/440 =220 but after doing this still I am not getting answer ...

Account Deleted 3 years, 1 month ago

Twenty three*

Account Deleted 3 years, 1 month ago

Yes because I had substrated 10 from 10 ^23 twenty three you see once again.....

Aseem Mahajan 3 years, 1 month ago

<font face ="Times New Roman">Line 20, denominator was 110
  • 1 answers

Anjan Karthi 3 years ago

Haloalkanes have higher boiling points than their corresponding alkanes as haloalkane molecules are connected to each other by dipole interactions that are relatively stronger than the London forces between alkane molecules
  • 3 answers

Akshay Haldua 3 years ago

It is E°cell

Anjan Karthi 3 years ago

An instrument used to determine the standard reduction potentials of other elements and complexes. It is made up of a platinum metal rod (which adsorbs and thereby, holds H molecules on its surface) dipped in acidified water. For this hydrogen is assumed to be of Eo = 0. When connected to material whose Eo has to be found out. Then, the Eo is found out by equation Eo (cell) = Eo (cathode) - Eo (anode). Eo (cell) is found experimentally and if hydrogen electrode undergoes oxidation, it is anode and if it undergoes reduction, it is cathode.

Y S 3 years, 1 month ago

Represented by Eo
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Aseem Mahajan 3 years, 1 month ago

<font face ="Times New Roman">What project?
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Priyanshu Tiwari 3 years, 1 month ago

Gupta
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Anjan Karthi 3 years ago

Phenol, on reaction with chloroform and sodium hydroxide, gives Salycaldehyde.
  • 1 answers

Anjan Karthi 3 years ago

Some times, the solute molecules, on dissolving in the solution, may undergo association or dissociation resulting in a net change in the quantity of solute particles in the solution. This can affect the value of colligative properties and thereby, the values of molar masses too. This is called ABNORMAL MOLAR MASS.
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Divya. Kumari 3 years, 1 month ago

Ya!! Asked
  • 1 answers

Y S 3 years, 1 month ago

Halogens are 17th group elements of periodic table that are cl f Br I ...
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Anjan Karthi 3 years ago

During resonance stabilisation, the ortho and para positions of the benzene ring with respect to the carboxy group attains momentary positive charges. Thus, the meta position is RELATIVELY favourable for incoming electrophilic substitutions in benzoic acid.
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Ayush Singh 3 years, 1 month ago

1: It is used in the calculation of absolute ionic mobilities. 2: It is used in the Molar conductance of weak electrolyte at infinite dilution. 3: It is used in the calculation of degree of dissociation (alpha) of a weak electrolyte. Thank you 😊
  • 2 answers

Ayush Singh 3 years, 1 month ago

Or 7.23 × 10²³.

Ayush Singh 3 years, 1 month ago

Number of atoms in 0.4 mole of compound = 0.4 x 6.022 x 10²³ = 2.4088 x 10²³ Number of octahedral voids = Number of atoms in close packing = 2.4088 x 10²³ Number of terahedral voids = 2 x No. of atoms in close packing = 2 x 2.4088 x 10²³ = 4.8176 x 10²³ Total number of voids = 2.4088 x 10²³ + 4.8176 x 10²³ = 7.2264 x 10²³. Thank you 😊
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Lakshmi Ramesh 3 years, 1 month ago

Single Nucleophile which have two nucleophlic centre are called ambident Nucleophile. NCS -AND SCN-. In this sulphur or nitrogen will be the nuclophilic centre

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