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Yogita Ingle 6 years, 1 month ago
Let the mass of given solute be W.
Let the volume of the solution be V.
Let the molality be m.
Let the molar mass of solute be M’.
Let the Molarity be M.
Let the weight of the solvent be W’.
Therefore the Molarity, M = W/M′∗1000/V ………(1)
Therefore the molality, m = W/M′∗1000/W′ …….(2)
Density, d = M/V
= (W+W′)/V
From (1)
V = W∗1000MM′ …………. (3)
From (2)
W’ = W∗1000/mM′
Therefore,
W+W’ = W+W∗1000/mM′ 1000M′[mM′1000m+1m]W′ …………(4)
By dividing equation (4) by (3) we get,
dM=1/m+M′1000 1/m=d/M−M′1000 m=M∗1000/(d∗1000)−M(M′)
Hence the relation between molality and Molarity proved.
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| GLUCOSE | FRUCTOSE |
| Also known as grape sugar | Also known as fruit sugar |
| Six-membered ring | Five-membered ring |
| The preferred energy source for the body | Not the preferred energy source for brain and muscles |
| Less lipogenic | More lipogenic |
| Less fat producing | More fat producing |
| Relies on hexokinase/ glucokinase for
initiating metabolism |
Relies on fructokinase for initiating metabolism |
| It is an aldohexose | It is a ketohexose |
| Forms a pyranose ring structure | Forms a furan ring structure |
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