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Posted by Mahnoor Kaur 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
The elastic collision formula comprises two parts, namely elastic collision formula for kinetic energy and elastic collision for momentum.
However, Follow the Table Below to Understand What each Component in the Equation Signifies –
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|
Mass of body 1 |
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Mass of body 2 |
|
Initial velocity of body 1 |
|
Initial velocity of body 2 |
|
Final velocity of body 1 |
|
Final velocity of body 2 |
Therefore, the formula for elastic collision kinetic energy is –
On the other hand, the elastic collision derivation for momentum is –
m1 u1 + m2 u2 = m1 v1 + m2 v2
A fundamental way to make sure whether a collision is elastic or inelastic is by equating their total kinetic energy. In case it remains the same as before and after the said collision, you can label it as elastic collision. Contrarily, a shift in the total kinetic energy suggests that the category of collision is inelastic.
However, the energy loss for inelastic collision usually dissipates into sound and heat energy. It helps in maintaining the balance of energy before and after.
Posted by Harman Singh 4 years, 1 month ago
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?? 4 years, 1 month ago
Posted by Naira(奈拉)..... ?️⚡?️⚡ ??? 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
Definition
Torque is when a force is applied to a particular object that results in the object moving by rotating around an axis. A force is some type of action that results in a body changing in motion or altering the path of motion.
Type of acceleration
The type of acceleration involved with torque is always angular, while the type of acceleration of force is mostly linear.
Equation
The mathematical equation that is often used to calculate torque is T = F x r x sin (theta). The mathematical equation that is often used to determine force is F = ma.
Metric unit of measurement
The Newton-meter is the metric unit of measurement that is used when calculating torque. The Newton is the metric unit used when measuring force.
English unit of measurement
The English unit of measurement which is used for torque is the foot-pound. The English unit of measurement which is used for force is the pound.
Posted by ᴘʀɪɴᴄᴇ { The Love Guru ✌️} 4 years, 1 month ago
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Tec Om 4 years, 1 month ago
bhai aap css codes(style sheet) ko head tag ke ander rakthe o sahi raheta within style tag
ᴘʀɪɴᴄᴇ { The Love Guru ✌️} 4 years, 1 month ago
Posted by Fear Fighter 4 years, 1 month ago
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Posted by Akhifa Sheik 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
strong nuclear force= in such force the particle are kept close to each other and has short range... hence are not easy to separate easily. Its main job is to hold together the subatomic particles of the nucleus.
weak nuclear force= in such type of force the particles r kept at a large distance and has a large range... hence easy to separate them.it is the interaction that interacts on subatomic particle.
Posted by Payal Suryawanshi 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
Work energy theorem states that the change in kinetic energy of an object is equal to the net work done on it by the net force.
Let us suppose that a body is initially at rest and a force 
is applied on the body to displace it through 
along the direction of the force. Then, small amount of work done is given by
Also, according to Newton's second law of motion, we have
where a is acceleration produced (in the direction of force) on applying the force. Therefore,
Now, work done by the force in order to increase its velocity from u (initial velocity) to v (final velocity) is given by
Hence, work done on a body by a force is equal to the change in its kinetic energy.
Posted by Anish Mukherjee 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
Linear Magnification = Height of the image / Height of the object = -v/u
Areal Magnification = v2 / u2
Other imp formulas:
Snells law sin i / sin r = constant = Refractive index between two given medium
Refractive index of a medium, μ = c/v where c is the speed of light in vacuum and v is the speed in light in the medium
Lens Formula 1/f = 1/v – 1/u where, f = focal length of the lens, u = distance of object, v = distance of image.
Lens Maker’s formula 1/f=(μ – 1) (1/R1 – 1/R2) where, μ = refractive index of the material of the lens and R1 and R2 are radii of curvature of the lens
Two lenses are in contact with each other, then P = P1 + P2 where P, P1, P2 are the power of combination, power of lens 1 and power of lens 2 respectively.
Two lenses are separated by a distance d, then P = P1 + P2 –d P1 P2
Posted by Anoop Kumar 4 years, 1 month ago
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Yogita Ingle 4 years, 1 month ago
The units which can neither be derived from other units nor they can be further resolved into simpler units are called fundamental units. Examples: Mass, length etc.
Those units which can be expressed in terms of the fundamental units are called derived units. Example: speed, velocity, acceleration etc.
Posted by Harsha C.D 4 years, 1 month ago
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Ruhi Rao 4 years, 1 month ago
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Dεερακ Ȿιηɠꜧ 4 years, 1 month ago
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Posted by Rohit Yadav 4 years, 1 month ago
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Aadya Singh 4 years, 1 month ago
Disha Shetty 4 years, 1 month ago
Gaurav Seth 4 years, 1 month ago
JEE toppers recommend studying the basics from NCERT books. With the help of NCERT solutions, the foundation of each subject in JEE can be strengthened. Also, it is easier to quickly revise basic concepts with the chapter summaries given in NCERT textbooks.
Whether NCERT books are sufficient for JEE or not has been an ongoing argument for IIT aspirants. NCERT books for JEE is just like what ingredients are to cooking. If you don’t understand the ingredients and basic cooking techniques, you cannot learn advanced cooking or solve problems.
Also, NCERT solutions for Class 11 and 12 can actually help you to earn the minimum cut-off in JEE Main. Study Inorganic Chemistry, practise Maths numerical problems or revise Physics concepts with NCERT books. NCERT solutions will help you grasp the basics of all JEE subjects.
<figure id="17/21"> </figure>The bottom line is that NCERT books are among the best books for JEE Main, but they are not enough as they don’t include revision of complex JEE questions. With NCERT books, you can build your foundation of the basic knowledge required for tackling advanced level problems in JEE.
Posted by Royal Thakur ? 4 years, 1 month ago
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Gaurav Seth 4 years, 1 month ago
“No”.
NCERT books are enough to qualify the examination but to get a good score/ rank one must refer to other books as well. Since both AIIMS MBBS and JIPMER MBBS have merged with NEET, NTA is expected to raise the bar for NEET this year. Both these examinations required extra effort and could not be cleared basis NCERT only.
Each one of the 15 lakh NEET aspirants has read NCERT books because it is the basic requirement to qualify the examination. Then how can you score enough marks to secure a position in the top 100? This is where reference books play a major role. Reference books and practice tests will give you an edge over the others.
It is important that one starts his/ her preparation with NCERT books and moves towards the reference books in the advanced stages of preparation. NEET preparation must be NCERT-focused and it must always be treated with utmost importance, but it is difficult to get great results if one relies solely on these books.
Posted by ⭐White Wolf⭐ 4 years, 1 month ago
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Posted by सत्य सनातन? 4 years, 1 month ago
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Yogita Ingle 4 years, 1 month ago
Van der Waals equation is an equation relating the relationship between the pressure, volume, temperature, and amount of real gases. For a real gas containing ‘n’ moles, the equation is written as;
{tex}\left( P+\frac{a{{n}^{2}}}{{{V}^{2}}} \right)\left( V-nb \right)=n\,R\,T\,(P+V2an2)(V−nb)=nRT{/tex}
Where, P, V, T, n are the pressure, volume, temperature and moles of the gas. ‘a’ and ‘b’ constants specific to each gas.
The equation can further be written as;
- Cube power of volume: {tex}{{V}^{3}}-\left( b+\frac{RT}{P} \right){{V}^{2}}+\frac{a}{P}V-\frac{ab}{P}=0V3−(b+PRT)V2+PaV−Pab=0{/tex}
- Reduced equation (Law of corresponding states) in terms of critical constants:
{tex}\left( \pi +\frac{3}{{{\varphi }^{2}}} \right)\left( 3\varphi -1 \right)=8\tau :\,\,where\,\,\pi =\frac{P}{Pc},\varphi =\frac{V}{Vc}\,\,\,and\,\,\tau =\frac{T}{Tc}(π+φ23)(3φ−1)=8τ:whereπ=PcP,φ=VcVandτ=TcT{/tex}
Posted by Harsha C.D 4 years, 1 month ago
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Posted by Harsha C.D 4 years, 1 month ago
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Yogita Ingle 4 years, 1 month ago
When the satellite is revolving around the earth, it is because of the gravitational force towards the earth that acts as a centripetal force. Since the initial speed is less than the escape speed, earth’s gravity pulls the satellite towards the centre of the earth. So the satellite is always accelerating around the earth.
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Vidhi Omar 4 years, 1 month ago
0Thank You