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Pk ⚔️ 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Pk ⚔️ 5 years, 2 months ago
Seraj Ali ?? 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Pk ⚔️ 5 years, 2 months ago
Seraj Ali ?? 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Seraj Ali ?? 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Seraj Ali ?? 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Pk ⚔️ 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Posted by Seraj Ali ?? 5 years, 2 months ago
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P Singh . 5 years, 2 months ago
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Posted by Nikita Kashinwar 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
1 watt hour is the unit of energy which is equivalent to 1 watt (W) of power used continuously for 1 hour of time.
It is not the SI unit of energy.
The SI unit of energy is Joule (J).
To convert energy from W h to J, we change the units as:
Energy = 1 watt hour
⇒ E = 1 × J/s × 60 × 60 × s
⇒ E = 3600 J
- So the equivalent of 1 watt hour in SI unit is 3600 J.
Posted by Sakshi Bangarwa 5 years, 2 months ago
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Posted by Aditi Rathore 5 years, 2 months ago
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Posted by Jeevan B. K 5 years, 2 months ago
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Posted by Kashna Siddique 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
Let the 2 vectors be A and B and their resultant be R.
To prove :- A=B=R.
.
For an easier way, Let us use this relation to find out theta when A=B=R.
.
R^2 = A^2 + B^2 + 2ABCostheta
.
Here A^2 = B^2 = R^2 ,
Hence, R^2 = R^2 + R^2 + 2R^2 (Costheta)
.
R^2 = 2R^2 + 2R^2 (Costheta)
Cos theta = (R^2 - 2R^2) / 2R^2 = (-R^2) / 2R^2
Cos theta = -1/2
Hence theta = 120 degrees.
.
Posted by Jeevan B. K 5 years, 2 months ago
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Posted by Abhishek Solanki 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
For A to be perpendicular to B, A.B should be zero
A.B=(2i + 3j- 6k).(3i-xj+6k)=0
6-3M-36=0
-30-3M=0
3M=-30
or M=-10
Posted by Annapoorna Madhu 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
To reach the peak of 10m the energy of spring must be
Mass = 50g = 50/1000kg = 0.05kg
acceleration due to gravity = g m/s^2 (take it as 10m/s^2 or 9.8 m/s^2 as directed in question)
Height = 10m
P = mgh
= 0.05 X g X 10 J
= 0.5g J
a) The potential energy of spring to throw it to height 10m is = 0.5g J
Taking g = 10; its 5j
b) To throw obhect to any height 'H' :
Let force coefficent of spring be = k
k X 0.03 = 5
k = 500/3
To throw it to any height H; compression c should be :
k( c) = mgH
500/3 X c = 0.05 X 10 X H
c = 0.05 X 10 X H X 3/500
Substitute the value of any H, to find out c (how much it needs to be compresssed. c is in metres.
Posted by Shiv Kachhela 5 years, 2 months ago
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Hariom Pandey 5 years, 2 months ago
Gaurav Seth 5 years, 2 months ago
Those physical quantities which require magnitude as well as direction for their complete representation and follows vector laws are called vectors.
Vector can be divided into two types
1. Polar Vectors
These are those vectors which have a starting point or a point of application as a displacement, force etc.
2. Axial Vectors
These are those vectors which represent rotational effect and act along the axis of rotation in accordance with right hand screw rule as angular velocity, torque, angular momentum etc.
Posted by Seraj Ali ?? 5 years, 2 months ago
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Aadya Singh 5 years, 2 months ago
Posted by Seraj Ali ?? 5 years, 2 months ago
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Seraj Ali ?? 5 years, 2 months ago
1Thank You