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  • 1 answers

Aman Dahiya 4 years ago

1 N = 1 kg ms-² = 1000 g ×100 m ×1 s-²= 100000 gcms-² =100000 dyne 100 N = 100 ×100000 dyne = 10000000 dyne
  • 2 answers
π/60×180 = π/ 10800

Yogita Ingle 4 years ago

We know that,

                        360° = 2π radians

Hence, 1° = 2 π/ 360 → (1)

             10° = [2 π/ 360° ] x 10 = π/ 18 radians

60 minutes = 1°

Substituting (1),

              60 minutes = 2 π/ 360

             One minute = 2 π/ (360 x 60)

             One minute = π/ 10800 radians → (2)

  • 1 answers

Class 12 4 years ago

Every timetable is best timetable, Its up to you that ,are u gonna follow it up in a best way... Thats all what i can say
  • 3 answers
Practice numericals, learn concept .

Pk ⚔️ 4 years ago

Ham sab yek hi kasti me sawar hai???

4 years ago

Physicsafter 10 has become so dimag ghumau. In theory its ok , but in numericals it creates a problem
  • 2 answers
1J= 10⁷erg
10J = 10×10⁷ erg = 10⁸erg

Yogita Ingle 4 years ago

we know, 1 Joule = 1 Kg m²/s²
1 erg = 1 g cm²/s²
so, 1 Joule = 1Kg m²/s²
= {1000 g} {100cm}²/s². [ 1kg = 1000g and 1m = 100cm]
= 1000 × 10000 g cm²/s²
= 10000000 erg
hence, 1 Joule = 107 erg
so, 10 Joule = 10 × 107 erg = 108 erg

  • 1 answers

Yash Rawat 4 years ago

True, But not always, because magnitude of any vector or vectors taken separately is always greater than that of which are taken together, But this idea becomes wrong when vectors which are taken together have same sign because in this case there is effective addition of magnitude of both vectors and then there result is equal to that which are taken seperately.
  • 1 answers

Yogita Ingle 4 years ago

Considering two waves, travelling simultaneously along the same stretched string in opposite directions as shown in the figure above. We can see images of <a href="https://byjus.com/physics/wave-theory-of-light/">waveforms</a> in the string at each instant of time. It is observed that the net displacement of any element of the string at a given time is the algebraic sum of the displacements due to each wave.

Let us say two waves are travelling alone and the displacements of any element of these two waves can be represented by y1(x, t) and y2(x, t). When these two waves overlap, the resultant displacement can be given as y(x,t).

Mathematically, y (x, t) = y1(x, t) + y2(x, t)

As per the principle of superposition, we can add the overlapped waves algebraically to produce a resultant wave. Let us say the wave functions of the moving waves are

y1 = f1(x–vt),

y2 = f2(x–vt) 

yn = fn (x–vt)

then the wave function describing the disturbance in the medium can be described as

y = f1(x – vt)+ f2(x – vt)+ …+ fn(x – vt)

or, y=∑ i=1 to n = fi (x−vt)

  • 4 answers
NEET Champion for med. JEE Champion for non med.
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Dc pandey

Kalki Kalki 4 years ago

Arihant
  • 1 answers

Aakash Kumar 4 years ago

School will be open after 1 month.
  • 1 answers

Sachi Chauhan 4 years ago

Significant figures of a number written in positional notation are the digits that carry meaningful contribution in measurnments.it is used to get an accurate and precise answer
  • 0 answers
  • 1 answers

Parush Kumar 4 years ago

s is displacement hear so the dimensions formula of s is [L] We know that we can add and subtract only those quantity which have same unit so dimensions formula of ut and 1/2at² is same Now u is initnial velocity it's dimensions formula is =[LT^-1] And t is time so =[T] ut dimensions formula is [L] The formula s=ut+1/2at² is dimensionally correct
  • 5 answers

?Ritesh Gupta? 4 years ago

Druv mera Facebook id- Ritesh Raj(ritt)
Oswal or evergreen

Dhruv .. 4 years ago

Welcome siso✌️

Muskan Singh 4 years ago

Thanks for your suggestion bro

Dhruv .. 4 years ago

Go for oswal and evergreen.....
  • 5 answers
Let y=3x dy/dx=3×1x^1-1=3×1=3 therefore answer is 3
3

Karan Jangir 4 years ago

Hi ridhima

Namit K 4 years ago

Let y = 3x dy/ dx = d(3x)/dx = 3×1x^ 1-1 = 3× 1= 3 Answer is 3

Maninder Singh 4 years ago

3
  • 2 answers

Saipreet . 4 years ago

Shall I help?

Muskan Singh 4 years ago

Just focus on ncert.... Firstly clear every topic and then solve 5-10 numericles related to each topic...
  • 2 answers
1N = 10^5 dyne Dyne is the cgs unit of force Newton is the SI unit of force

Jesika .. 4 years ago

we can convert it into dyne .
  • 5 answers

4 years ago

Leave him ss he is a bad abuer and he can be anything

? S. S. ? 4 years ago

U already know what I mean..then why are u behaving like u don't know anything!!...#Dhruv or #cheater or #fake one.....

Dhruv .. 4 years ago

#?s.s.?....what do you mean???

? S. S. ? 4 years ago

LiVe eXaMpLe....JuSt sEE YoUrSeLf....I know v. well you're expert in that!!

Yogita Ingle 4 years ago

Academic cheating is defined as representing someone else's work as your own. It can take many forms: from sharing another's work to purchasing a term paper or test questions in advance, to paying another to take a test or do the work for you.

  • 1 answers

Yogita Ingle 4 years ago

1 kg = 103 g

1 m2 = 104 cm2

1 kg m2 s–2 = 1 kg × 1 m2 × 1 s–2

=10g × 104 cm2 × 1 s–2 = 107 g cm2 s–2

1 kg m2s–2 = 107 g cm2 s–2

  • 1 answers

Yogita Ingle 4 years ago

Joule is the unit for energy
Dimension Formula for Joule is [M¹L²T⁻²]
Let n1(joule)=n2(erg)
n1(M₁¹L₁²T₁⁻²]=n2[M₂¹L₂²T₂⁻²]
n2=n1(M₁¹L₁²T₁⁻²] /M₂¹L₂²T₂⁻²]
=n1x(M1/M2)¹x(L1/L2)²x(T1/T2)⁻²
=1x(1kg/gm)¹x(1m/1cm)²x(1s/1s)⁻²
=1x(1000g/gm)x(100cm/1cm)²x(1s/1s)⁻²
=10⁷ 
Therefore n1(joule)=n2(erg)
∴1 Joule=10⁷erg

  • 1 answers

Yogita Ingle 4 years ago

Principle of Homogeneity states that dimensions of each of the terms of a dimensional equation on both sides should be the same. This principle is helpful because it helps us convert the units from one form to another

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