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    • Posted by Jitender Singh 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Kahkasha Kahkasha 1 year, 5 months ago

    CBSE > Class 11 > Physics
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    • Posted by Janhavi Singh 1 year, 5 months ago

    CBSE > Class 11 > Physics
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    • Posted by Pinky Pawanda 1 year, 5 months ago

    CBSE > Class 11 > Physics
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    • Posted by Deepanshu Tiwari 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Varshni Kamal 1 year, 5 months ago

    Because at that point , mass of the earth is equally distributed in all directions , so pulling equally in all directions for a net zero pull

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    • Posted by Masira Khan Khan 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Achal Chaudhary Chaudhary 1 year, 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Soban Kumar 1 year, 5 months ago

    CBSE > Class 11 > Physics
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    • Posted by Soup S 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Gungun . 1 year, 5 months ago

    For velocity differentiate the distance once w.r.t. time... After differentiation dx/dt = 0+12t = 12t V = 12×2 = 24unit/sec

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    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Posted by Lucky Uttam 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Lucky Uttam 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Lucky Uttam 1 year, 5 months ago

    angle of friction is equal to angle of repose in the limiting friction

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    Lucky Uttam 1 year, 5 months ago

    Additional information:Angle of friction of a body is defined as the angle which is made between the resultant of normal reaction and the direction of force of friction or frictional force. The angle of repose is defined as that particular angle of an inclined plane at which a body place just begins to slide

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    • Posted by Anurag Ray 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 5 months ago

    T=r(h+r3)ρg2cosθ

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    • Posted by Muskan Suri 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 5 months ago

    When an object changes its shape (rotational inertia), its angular velocity will also change if there is no external torque

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    • Posted by Harshit Malik ... 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Nasra Javed 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 6 months ago

    Well, we can't actually, because F = mv2/r is itself a derivative of the equation a = v2/r. But, we have another proof. According to law of conservation of energy, kinetic energy b/w two diametrically opposite points = potential across the points. So, we can write 1/2 m(2v) ^2 (since, vector v across two points are opposite in direction and relative velocity becomes v - (-v) = 2v) = ma (2r) . Therefore, m cancelled on both sides, we get 2v^2 = a (2r) . Therefore, v^2 = ar or, a = v^2/r.

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    • Posted by Nasra Javed 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Nayan Tara Priyadarshini 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Bhavya Singla 1 year, 6 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Raja Kumar 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Raja Kumar 1 year, 6 months ago

    Give solve this question

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    • Posted by Raja Kumar 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Dheebak.T Deepak 1 year, 6 months ago

    give solve this questions

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    • Posted by Tushar Pathak 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Sukhmandeep Singh 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Anisha Patel 1 year, 6 months ago

    9.8

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    Anjan Karthi 1 year, 6 months ago

    G = 6.673 × 10^-11 Nm2/kg2 = 6.673 × 10^-8 dyne cm2/g2

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    • Posted by Pragadeesh Ramadoss 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 4 months ago

    The ratio of output by input. You may see it at many places as in like transformers (output voltage / Input voltage), transistors, heat engines, refrigerators, and so many more.

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    • Posted by Madan Mishra 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Anjan Karthi 1 year, 6 months ago

    "S" has dimension [L]. "ut" has dimension [L/T] × [T] = [L]. "at^2" has dimension [LT^-2] × [T^2] = [L]. Thus, the equation is dimensionally correct.

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    Abhay Rana 1 year, 6 months ago

    Right

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    Kaushal Ray 1 year, 6 months ago

    S= ut + 1/2at²

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    • Posted by Kartikey Gupta 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Anjan Karthi 1 year, 6 months ago

    Wait, Range = 20 × 4 = 80m.//

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    Anjan Karthi 1 year, 6 months ago

    Now, in order to reac the ground after projection upwards from a tower, we have to calculate the time for it to reach back the same height level where it was earlier (T1) and the time taken to go from that level to the ground (T2). T = T1 + T2 = 2usinπ /g + √2h/g= 2 × 20 × sin 30°/ 10 + √2h/10 = 4 sec. 2 + √2h/10 = 4. √2h/10 = 2. (2h/10 = 2^2 = 4). 2h = 40. Therefore, h = 20m.// Range R = u√2h/g = 20 × 2 = 40m.//

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    • Posted by Pooja Gupta 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Rewati Raman 🤓🤓🤓 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 6 months ago

    s = ut + 0.5at^2 = (v × 4πr/v) + (0.5 × v^2/r × 16π^2r^2/v^2) = 4πr + 8π^2 r.//

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    • Posted by Shambhu Raju 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Saurabh Dwivedi 1 year, 6 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Pukar Sharma 1 year, 6 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 6 months ago

    R = √p^2 + q^2 + 2pq cosπ. p^2 = p^2 + p^2 + 2p^2 cosπ. -p^2 = 2p^2 cosπ. cosπ = -1/2. π = 120°.//

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    • Posted by Shaikh Fatema 1 year, 7 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Khushi Patel 1 year, 7 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ritesh Singh 1 year, 6 months ago

    Newton's 2nd law of motion is the real law of motion is most important....

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    • Posted by Vivek Prajapat 1 year, 7 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Vidhika Singhal 1 year, 7 months ago

    A work is said to be done when there is displacement by the body on which the is applied

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