No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question

    • Posted by Jitender Singh 1 year ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Kahkasha Kahkasha 1 year ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Janhavi Singh 1 year ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Pinky Pawanda 1 year ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Deepanshu Tiwari 1 year ago

    CBSE > Class 11 > Physics
    • 1 answers

    Varshni Kamal 1 year ago

    Because at that point , mass of the earth is equally distributed in all directions , so pulling equally in all directions for a net zero pull

    0Thank You

    ANSWER

    • Posted by Masira Khan Khan 1 year ago

    CBSE > Class 11 > Physics
    • 1 answers

    Achal Chaudhary Chaudhary 1 year ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    0Thank You

    ANSWER

    • Posted by Soban Kumar 1 year ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Soup S 1 year ago

    CBSE > Class 11 > Physics
    • 1 answers

    Gungun . 1 year ago

    For velocity differentiate the distance once w.r.t. time... After differentiation dx/dt = 0+12t = 12t V = 12×2 = 24unit/sec

    0Thank You

    ANSWER
    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    Posted by Lucky Uttam 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 1 month ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    0Thank You

    ANSWER

    • Posted by Lucky Uttam 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 2 answers

    Lucky Uttam 1 year, 1 month ago

    angle of friction is equal to angle of repose in the limiting friction

    1Thank You

    Lucky Uttam 1 year, 1 month ago

    Additional information:Angle of friction of a body is defined as the angle which is made between the resultant of normal reaction and the direction of force of friction or frictional force. The angle of repose is defined as that particular angle of an inclined plane at which a body place just begins to slide

    1Thank You

    ANSWER

    • Posted by Anurag Ray 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 1 month ago

    T=r(h+r3)ρg2cosθ

    1Thank You

    ANSWER

    • Posted by Muskan Suri 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 1 month ago

    When an object changes its shape (rotational inertia), its angular velocity will also change if there is no external torque

    0Thank You

    ANSWER

    • Posted by Harshit Malik ... 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Nasra Javed 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 1 month ago

    Well, we can't actually, because F = mv2/r is itself a derivative of the equation a = v2/r. But, we have another proof. According to law of conservation of energy, kinetic energy b/w two diametrically opposite points = potential across the points. So, we can write 1/2 m(2v) ^2 (since, vector v across two points are opposite in direction and relative velocity becomes v - (-v) = 2v) = ma (2r) . Therefore, m cancelled on both sides, we get 2v^2 = a (2r) . Therefore, v^2 = ar or, a = v^2/r.

    1Thank You

    ANSWER

    • Posted by Nasra Javed 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Nayan Tara Priyadarshini 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Bhavya Singla 1 year, 1 month ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    0Thank You

    ANSWER

    • Posted by Raja Kumar 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Raja Kumar 1 year, 1 month ago

    Give solve this question

    0Thank You

    ANSWER

    • Posted by Raja Kumar 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Dheebak.T Deepak 1 year, 1 month ago

    give solve this questions

    1Thank You

    ANSWER

    • Posted by Tushar Pathak 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lucky Uttam 1 year, 1 month ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    0Thank You

    ANSWER

    • Posted by Sukhmandeep Singh 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 2 answers

    Anisha Patel 1 year, 1 month ago

    9.8

    1Thank You

    Anjan Karthi 1 year, 1 month ago

    G = 6.673 × 10^-11 Nm2/kg2 = 6.673 × 10^-8 dyne cm2/g2

    0Thank You

    ANSWER

    • Posted by Pragadeesh Ramadoss 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year ago

    The ratio of output by input. You may see it at many places as in like transformers (output voltage / Input voltage), transistors, heat engines, refrigerators, and so many more.

    0Thank You

    ANSWER

    • Posted by Madan Mishra 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 3 answers

    Anjan Karthi 1 year, 1 month ago

    "S" has dimension [L]. "ut" has dimension [L/T] × [T] = [L]. "at^2" has dimension [LT^-2] × [T^2] = [L]. Thus, the equation is dimensionally correct.

    1Thank You

    Abhay Rana 1 year, 1 month ago

    Right

    0Thank You

    Kaushal Ray 1 year, 1 month ago

    S= ut + 1/2at²

    0Thank You

    ANSWER

    • Posted by Kartikey Gupta 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 2 answers

    Anjan Karthi 1 year, 1 month ago

    Wait, Range = 20 × 4 = 80m.//

    0Thank You

    Anjan Karthi 1 year, 1 month ago

    Now, in order to reac the ground after projection upwards from a tower, we have to calculate the time for it to reach back the same height level where it was earlier (T1) and the time taken to go from that level to the ground (T2). T = T1 + T2 = 2usinπ /g + √2h/g= 2 × 20 × sin 30°/ 10 + √2h/10 = 4 sec. 2 + √2h/10 = 4. √2h/10 = 2. (2h/10 = 2^2 = 4). 2h = 40. Therefore, h = 20m.// Range R = u√2h/g = 20 × 2 = 40m.//

    0Thank You

    ANSWER

    • Posted by Pooja Gupta 1 year, 1 month ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Rewati Raman 🤓🤓🤓 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 2 months ago

    s = ut + 0.5at^2 = (v × 4πr/v) + (0.5 × v^2/r × 16π^2r^2/v^2) = 4πr + 8π^2 r.//

    2Thank You

    ANSWER

    • Posted by Shambhu Raju 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Saurabh Dwivedi 1 year, 1 month ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    1Thank You

    ANSWER

    • Posted by Pukar Sharma 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 2 months ago

    R = √p^2 + q^2 + 2pq cosπ. p^2 = p^2 + p^2 + 2p^2 cosπ. -p^2 = 2p^2 cosπ. cosπ = -1/2. π = 120°.//

    0Thank You

    ANSWER

    • Posted by Shaikh Fatema 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Khushi Patel 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ritesh Singh 1 year, 1 month ago

    Newton's 2nd law of motion is the real law of motion is most important....

    1Thank You

    ANSWER

    • Posted by Vivek Prajapat 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Vidhika Singhal 1 year, 2 months ago

    A work is said to be done when there is displacement by the body on which the is applied

    0Thank You

    ANSWER

    myCBSEguide App

    myCBSEguide

    Trusted by 1 Crore+ Students

    Install Now

    Test Generator

    Test Generator

    Create papers online. It's FREE.

    Try Now

    CUET Mock Tests

    CUET Mock Tests

    75,000+ questions to practice only on myCBSEguide app

    Install Now
    Google Play

    Download myCBSEguide App

    All Courses

    Other Websites

    CBSE Courses

    Resources

    Corporate

    NCERT Solutions

    CBSE Sample Papers

    All Content and Intellectual Property is under Copyright Protection | myCBSEguide.com ©2007-2024