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# From the top of a tower … ## CBSE, JEE, NEET, CUET

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From the top of a tower a stone is thrown with velocity 20m/s at an angle of 30degree with the horizontal the stone is strike on the ground after 4 sec find the height of the tower and horizontal range of the stone

Wait, Range = 20 × 4 = 80m.//

Now, in order to reac the ground after projection upwards from a tower, we have to calculate the time for it to reach back the same height level where it was earlier (T1) and the time taken to go from that level to the ground (T2). T = T1 + T2 = 2usinπ /g + √2h/g= 2 × 20 × sin 30°/ 10 + √2h/10 = 4 sec. 2 + √2h/10 = 4. √2h/10 = 2. (2h/10 = 2^2 = 4). 2h = 40. Therefore, h = 20m.// Range R = u√2h/g = 20 × 2 = 40m.//

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