No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question

    • Posted by Mohd Danish 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Hritik Gupta 7 years ago

    Oscillation is a definite distance covered by the movement about its equilibrium position, vibration is referred to the physical change brought about due to movement of the body. Oscillation can be seen in the swinging of a pendulum clock and vibration in the plucking of guitar string.

    1Thank You

    ANSWER

    • Posted by Priyanka Sugandh 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Xxxx X 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Xxxx X 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by ???. Pragati 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ayushi Ayushi 7 years ago

    The four laws of thermodynamics define fundamental physical quantities (temperature, energy, and entropy) that characterize thermodynamic systems at thermal equilibrium. The laws describe how these quantities behave under various circumstances, and preclude the possibility of certain phenomena (such as perpetual motion). The four laws of thermodynamics are:[1][2][3][4][5] Zeroth law of thermodynamics: If two systems are each in thermal equilibrium with a third system, they are in thermal equilibrium with each other. This law helps define the concept of temperature. First law of thermodynamics: When energy passes, as work, as heat, or with matter, into or out from a system, the system's internal energy changes in accord with the law of conservation of energy. Equivalently, perpetual motion machines of the first kind (machines that produce work with no energy input) are impossible. Second law of thermodynamics: In a natural thermodynamic process, the sum of the entropies of the interacting thermodynamic systems increases. Equivalently, perpetual motion machines of the second kind (machines that spontaneously convert thermal energy into mechanical work) are impossible. Third law of thermodynamics: The entropy of a system approaches a constant value as the temperature approaches absolute zero.[2] With the exception of non-crystalline solids (glasses) the entropy of a system at absolute zero is typically close to zero.

    2Thank You

    ANSWER

    • Posted by Sivan Karthick 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Tanmay Singh Rana 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Yogita Ingle 7 years ago

    Spin gives angular momentum to the bullet, which gives more stability against local air flow and pressure fluctuation, like gyroscope. It also helps bullet to penetrates more to the targets because of the same spin angular momentum.

    4Thank You

    ANSWER

    • Posted by Nirupama Singh 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Shivam Mishra 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Rashi 7Th 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Vineet Rana 5 years, 8 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Muskan ???? 7 years ago

    Soo??

    0Thank You

    ANSWER

    • Posted by Ayushi Ayushi 7 years ago

    CBSE > Class 11 > Physics
    • 6 answers

    Ayushi Ayushi 7 years ago

    Thanks

    2Thank You

    Ankit Singh 7 years ago

    Triple point. ... In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium. For example, the triple point of mercury occurs at a temperature of −38.83440 °C and a pressure of 0.2 mPa.

    1Thank You

    Sejal Sharma 7 years ago

    No it is not constant for evry matter

    0Thank You

    Sejal Sharma 7 years ago

    In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium.for example, the triple point of mercury occurs at a temperature of −38.83440 °C and a pressure of 0.2 mPa. In addition to the triple point for solid, liquid, and gas phases, a triple point may involve more than one solid phase, for substances with multiple polymorphs. Helium-4 is a special case that presents a triple point involving two different fluid phases (lambda point).

    1Thank You

    Ayushi Ayushi 7 years ago

    I am trying to say ," is the triple point constant for every matter or different?

    0Thank You

    Nancy Rajput 7 years ago

    i dont understsnd your question

    0Thank You

    ANSWER

    • Posted by Muhammad Altaf Raja 7 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Sheetal Singh 7 years ago

    Center of mass depends upon many physical quantity like velocity , acceleration , mass , position , lenght

    2Thank You

    Raghav Patidar 7 years ago

    mass ,position

    1Thank You

    ANSWER

    • Posted by Muhammad Altaf Raja 7 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ankit Singh 7 years ago

    Nice suggestions

    2Thank You

    Priya Dharshini ☺☺ 7 years ago

    Understand the concepts dont mug up the derivation.try to prove it ur self after understanding it. If a question of physics is given try to find out all the given things and what all u need to find from that.read ncert whole u will uderstand everything

    1Thank You

    Nancy Rajput 7 years ago

    by understanding their concepts and do more practise of numerical

    2Thank You

    ANSWER

    • Posted by Ayushi Ayushi 7 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Ayushi Ayushi 7 years ago

    Thanks

    2Thank You

    Nancy Rajput 7 years ago

    Triple point is the intersection on a phase diagram where three phases coexist in equilibrium. Triple point of water is the stage where solid liquid and vapour all exists. The triple point of water, 273.16 K ( 00C) at a pressure of 611.2 Pa

    1Thank You

    ANSWER

    • Posted by Ayushi Ayushi 7 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ankit Singh 7 years ago

    Yours welcome

    1Thank You

    Ayushi Ayushi 7 years ago

    Thanks

    1Thank You

    Ankit Singh 7 years ago

    In case of gases, when balloon is partially inflated in a cool room it expands to full size when put in warm water. This all is due to thermal expansion. So, increase in dimension of a body due to increase in temperature is thermal expansion. The expansion in is called linear expansion.A gas expands when heated and condenses when cooled. Charles' Law predicts a four-fold decrease in the volume of a gas that is cooled from room temperature to the temperature of liquid nitrogen (77 K). ... Removing the balloon exposes the cold balloon to higher temperatures.

    1Thank You

    ANSWER

    • Posted by Tabish Rehan 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Sivan Karthick 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Shrey Rajput 7 years ago

    It is based on the law of conservation of energy and applied to ideal fluids.It states that the sum of presence energy per unit volume, kinetic energy per unit volume and potential energy per unit volume of an incompressible, non-viscous fluid in a stremlined irrotational flow remains constant at every cross-section throughout the liquid flow. P+ 1/2 (rho)V^2+(rho)gh = constant Application of Bernoulli theorm 1. Speed of Efflux 2. Atomizer or sprayer 3. Blood flow and heart attack 4. Dynamic lift (A). Ball moving without spin (B). Ball moving with spin (C). Aerofoil, lift of an airlift wing

    1Thank You

    ANSWER

    • Posted by Sivan Karthick 7 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Nancy Rajput 7 years ago

    the ratio lateral strain to longitudinal strain is known as poison ratio.poison ratio = delta d×l/ delta l ×d

    1Thank You

    Říý@ ?? 7 years ago

    Poisson's ratio is the ratio of transverse contraction strain to longitudinal extension strain in the direction of stretching force.

    3Thank You

    ANSWER

    • Posted by Nitesh Agrawal 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Vishwas Yadav 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Říý@ ?? 7 years ago

    Stefan Boltzmann Law states that , the total radiant heat energy that is emitted by a surface is proportional to fourth power of its absolute temperature.

    1Thank You

    ANSWER

    • Posted by Himanshu Tangar 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Shrey Rajput 7 years ago

    It is defined as the acceleration produced in the body under gravity or falls freely under the effect of gravity. So, F = GMem/Re^2 = mg g=GMe/Re^2 This is also known as relation between G & g.

    2Thank You

    ANSWER

    • Posted by Suraj Singh 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Yogita Ingle 7 years ago

    Let the lamina ( ΔLMN)  is subdivided into narrow strips each parallel to the base (MN)
    By symmetry, each and every strip has its centre of mass at its mid-point.
    On joining the mid-points of all strips we get the median LP. Therefore the centre of mass of the triangle as a whole lie on the median LP.   
    Similarly, we can say that it lies on the median MQ and NR. It means that centre of mass lies on the point of concurrence of the median, which is on the centroid G of the triangle.

    6Thank You

    ANSWER

    • Posted by Tushar Prajapati 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Zaid Khan 7 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Avi Singh 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ayushi Ayushi 7 years ago

    Newton's Law of Cooling states that the temperature of a body changes at a rate proportional to the difference in temperature between its own temperature and the temperature of its surroundings. We can therefore write dTdt=−k(T−Ts)dTdt=−k(T−Ts) where, T = temperature of the body at any time, t Ts = temperature of the surroundings (also called ambient temperature) To = initial temperature of the body k = constant of proportionality dTdt=−k(T−Ts)dTdt=−k(T−Ts) dTT−Ts=−kdtdTT−Ts=−kdt ln(T−Ts)=−kt+lnCln⁡(T−Ts)=−kt+ln⁡C ln(T−Ts)=lne−kt+lnCln⁡(T−Ts)=ln⁡e−kt+ln⁡C ln(T−To)=lnCe−ktln⁡(T−To)=ln⁡Ce−kt T−Ts=Ce−ktT−Ts=Ce−kt when t = 0, T = To C=To−TsC=To−Ts Thus, T−Ts=(To−Ts)e−ktT−Ts=(To−Ts)e−kt T=Ts+(To−Ts)e−ktT=Ts+(To−Ts)e−kt The formula above need not be memorized, it is more useful if you understand how we arrive to the formula.

    0Thank You

    ANSWER

    • Posted by Prince Mehta 7 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Hemant Ritesh Sourashtriya 7 years ago

    Given our definition of work as W = Fs , can we generate an expression for work done on a rotational system? To derive our expression we begin by taking the simplest case: when the force applied to a particle in rotational motion is perpendicular to the radius of the particle. In this orientation, the force applied is parallel to the displacement of the particle, and would exert the maximum work. Given this situation the work done is simply W = Fs , where s is the arc length that the force acts through in a given period of time. Recall, however, that arc length can also be expressed in terms of the angle swept out by the arc: s = rμ . Our expression for work in this simple case becomes: W = Frθ = τμ    Since Fr gives us our torque, we can simplify our expression in terms of only τ and μ . What if the force is not perpendicular to the radius of the particle? Let the angle between the force vector and the radius vector be θ , as shown below. Figure %: A force acting at angle θ to the radius of rotation of point PTo compute the work we calculate the component of the force acting in the direction of the particle's displacement. In this case, this quantity is simply F sinθ . Again, this force acts over an arc length given by rμ . Thus the work is given by: W = (F sinθ)(rμ) = (Fr sinθ)μ Recall that τ = Fr sinθ Thus W = τμ Surprisingly enough, this equation is exactly the same as our special case when the force acted perpendicular to the radius! In any case, the work done by a given force is equal to the torque it exerts multiplied by the angular displacement. For you calculus types, there is also an equation for work done by variable torques. Instead of deriving it, we can just state it, as it is quite similar to the equation in the linear case: W =  τdμ    Thus we have quickly gone through deriving our expression for work. The next thing after work we studied in linear motion was kinetic energy, and it is to this topic that we turn. Rotational Kinetic Energy Consider a wheel spinning in place. Clearly the wheel is moving, and has a kinetic energy attached to it. But the wheel is not engaged in translational motion. How do we calculate the kinetic energy of the wheel? Our answer is similar to how we calculated the result of a net torque on a body: by summing over each particle.

    1Thank You

    ANSWER

    • Posted by Jatin Govila 7 years ago

    CBSE > Class 11 > Physics
    • 4 answers

    Ankit Singh 7 years ago

    Hope this answer is helpful to u

    1Thank You

    Ankit Singh 7 years ago

    The electrical resistance of an object is a measure of its opposition to the flow of electric current. The inverse quantity is electrical conductance, and is the ease with which an electric current passes. Electrical resistance shares some conceptual parallels with the notion of mechanical friction. Resistance is measure by ohms

    1Thank You

    Ayushi Ayushi 7 years ago

    Resistance is a measure of the opposition to current flow in an electrical current . Resistance is measured in ohms,symbolised by the Greek letter omega .

    2Thank You

    Prince Neeraj 7 years ago

    Opposition faced by the current.

    2Thank You

    ANSWER

    • Posted by Ayushi Ayushi 7 years ago

    CBSE > Class 11 > Physics
    • 7 answers

    Ankit Singh 7 years ago

    Most welcome

    0Thank You

    Ayushi Ayushi 7 years ago

    Thanks

    1Thank You

    Ankit Singh 7 years ago

    Hope this answer will help u

    1Thank You

    Ankit Singh 7 years ago

    The critical temperature of a substance is the temperature at and above which vapor of the substance cannot be liquefied, no matter how much pressure is applied. It is where the liquid directly gets transformed in to vapor without undergoing the progressive change from saturated liquid to saturated vapor (i.e. no phase boundary).

    1Thank You

    Prince Neeraj 7 years ago

    A/c to chemistry book, Critical temp. Is the temp. above which there will be no more change in the temp whatever the pressure may be.

    2Thank You

    Ayushi Ayushi 7 years ago

    I don't understand that velocity intermediate to streamline ND turbulent flow .

    0Thank You

    Avi Dixit 7 years ago

    Velocity intermediate to streamline ND turbulent flow

    0Thank You

    ANSWER

    • Posted by Ayushi Ayushi 7 years ago

    CBSE > Class 11 > Physics
    • 4 answers

    Ayushi Ayushi 7 years ago

    But why is the lava coming out of the volcano flows very fast even when it is very thick? because the viscosity of the lava is maximum so why is the lava coming out of the volcano flows very fast?

    2Thank You

    Avi Dixit 7 years ago

    It's viscosity didn't increases miss..... Only the formation of cream takes place ND if u ll remove the cream u ll observe the less viscous glow of milk

    0Thank You

    Ayushi Ayushi 7 years ago

    But the viscosity of fluid decrease when we gave temperature to it

    4Thank You

    Sivan Karthick 7 years ago

    when we heat milk it started to become hard due to its nature so viscosity increases

    1Thank You

    ANSWER

    myCBSEguide App

    myCBSEguide

    Trusted by 1 Crore+ Students

    Install Now

    Test Generator

    Test Generator

    Create papers online. It's FREE.

    Try Now

    CUET Mock Tests

    CUET Mock Tests

    75,000+ questions to practice only on myCBSEguide app

    Install Now
    Google Play

    Download myCBSEguide App

    All Courses

    Other Websites

    CBSE Courses

    Resources

    Corporate

    NCERT Solutions

    CBSE Sample Papers

    All Content and Intellectual Property is under Copyright Protection | myCBSEguide.com ©2007-2025