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    • Posted by Sanchanga Sangma 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Sid Xavier 7 years, 2 months ago

    The error in the measurement is equal to the difference between the true value and the measured value of the quantity. Error= true value - measured value

    0Thank You

    Mahesh Meel 7 years, 2 months ago

    2

    1Thank You

    ANSWER

    • Posted by Deepak Kumar 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lavanya ❤️? 7 years, 2 months ago

    Variation of g with height is g h=g(1-2h/R) Variation of g with depth is g d =g(1-d/R)

    2Thank You

    ANSWER

    • Posted by Someone ?? 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Asif Ansari 7 years, 2 months ago

    According to stokes law the backword viscous force acting on a small spherical body of radius r moving with uniform velocity v through fluid of viscosity eta n is given by.

    0Thank You

    Maunisha Mallan 7 years, 2 months ago

    according to stoke's law, when a sperical body moves through a fluid,it experiences a viscous force.An expression for the viscous for force experienced by the spherical object was derived by stokes..therefore the expression is called stoke's law... where F=6^nrv...^=pi nd n=coefficient of viscosity

    1Thank You

    Lavanya ❤️? 7 years, 2 months ago

    The magnitude of viscous force developed when a body is travelling through the viscous medium is said to depend on coefficient of viscosity, radius of the body and its terminal velocity given by F = 6 π a η v This equation is called Stokes' law.

    0Thank You

    ANSWER

    • Posted by Abhishek Yadav 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Akanksha Kumari? 7 years, 2 months ago

    If you want acceleration in this question then U =0 V=36 km/hr = 10 m/sec T = 10sec A=v-u /t A= 10-0/10 A=1m/sec^2

    1Thank You

    ANSWER

    • Posted by Maunisha Mallan 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Nitin Ahlawat 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Nitin Ahlawat 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Akanksha Kumari? 7 years, 2 months ago

    Yes it is

    1Thank You

    ANSWER

    • Posted by Adwitha Nair???‍??‍? 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Ankit Singh 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Ankit Singh 7 years, 2 months ago

    Thanks Lavanya

    1Thank You

    Lavanya ❤️? 7 years, 2 months ago

    As the vectors AB, BC, CD, DA form a quadrilateral, their resultant is zero. AB + BC + CD + DA = 0 Therefore the sum of vector is BC+CD+CA=BA. So BA+BC+CD+DA= BA+(BC+CD+DA) = BA +BA=2BA Therefore the value of n is 2

    2Thank You

    ANSWER

    • Posted by Ankit Singh 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ankit Singh 7 years, 2 months ago

    Thanku akanksha for the answer

    3Thank You

    Akanksha Kumari? 7 years, 2 months ago

    Ax= x component of A Ay = ycomponent of A Az = z component of A Therefore A= ( ax^2+ay^2+az^2)^1/2 It is for 3d For 2d only take x and y component Direction: Tan A = ax/ay

    2Thank You

    Ankit Singh 7 years, 2 months ago

    It's imp please answer

    1Thank You

    ANSWER

    • Posted by Ankit Singh 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 6 answers

    Prakhar Jadaun ? 7 years, 2 months ago

    Sliding vector is a vector having specified magnitude and lying on a given line.....?

    3Thank You

    Prakhar Jadaun ? 7 years, 2 months ago

    A vector with fixed initial and terminal point is called a bound vector.

    2Thank You

    Prakhar Jadaun ? 7 years, 2 months ago

    Free vector is a vector of which only the magnitude and direction are specified, not the position or line of action...

    2Thank You

    Ankit Singh 7 years, 2 months ago

    Please answer my question

    1Thank You

    Ankit Singh 7 years, 2 months ago

    Samaj me aagya

    1Thank You

    Ankit Singh 7 years, 2 months ago

    Please explain in detail ....?????

    1Thank You

    ANSWER

    • Posted by No No 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Komal Mehta 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 4 answers

    Akanksha Kumari? 7 years, 2 months ago

    Work done in engine is a example of cyclic process

    1Thank You

    Akanksha Kumari? 7 years, 2 months ago

    Work done in engine is also a example of circular motion and there is work done

    1Thank You

    Akanksha Kumari? 7 years, 2 months ago

    I think here some kind of work is done And w=nR (ti-tf) Where N= no of moles R= gas constant Ti -tf= change in temperature

    1Thank You

    Sugam Sharma 7 years, 2 months ago

    It must be equal to 0 as change in volume=0

    2Thank You

    ANSWER

    • Posted by Anjeet Singh 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Deepak Baghel 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Akanksha Kumari? 7 years, 2 months ago

    Moment of inertia is used in rotational motion just like mass is used in translational motion whereas law of inertia is tendency of a body to resist change in motion

    1Thank You

    Prakhar Jadaun ? 7 years, 2 months ago

    In a easy way we can say that Moment of inertia is the rotational analogues of mass whereas law of inertia is a common name of Newton's 1st law....

    3Thank You

    ANSWER

    • Posted by Shruti Kumari 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Akanksha Kumari? 7 years, 2 months ago

    M1 =1kg M2=4kg K.E 1= 1/2×m1×v1^2 V1=(2k.e)^1/2 K.e2 = 1/2×m2× v2^2 V2 = (k.e/2)^1/2 Monentum = p P1/p2 = m1v1/m2v2 =1×(2k.e)^1/2 ÷ 4×(k.e/2)^1/2 =on squaring = 2k.e/8 k.e =1:4 ans.

    1Thank You

    ANSWER

    • Posted by Jyoti Vishwakarma 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ɽøⱨł₮ ₲Ʉ₱₮₳ 7 years, 2 months ago

    P + pgh + 1/2PV^2= constant......(Here P= row (density)

    2Thank You

    Ankit Singh 7 years, 2 months ago

    Nice answer Lavanya

    2Thank You

    Lavanya ❤️? 7 years, 2 months ago

    The total energy of an incompressible, non viscous fluid in steady flow through a pipeline remains constant throughout, provides there t is no source or sink along the length of the pipe.

    5Thank You

    ANSWER

    • Posted by Mr. Rajput 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 5 answers

    Mr. Rajput 7 years, 2 months ago

    Thnx to all if u

    0Thank You

    Priya Dharshini ? 7 years, 2 months ago

    Best thing is ask ur teacher or refer this app notes. In any of the guide the explanation is quite big and u cant complete even half of the portion . 1 ch it takes maximum 5 days. In physics there are so many chapters.

    1Thank You

    Ankit Singh 7 years, 2 months ago

    U can get the notes in this app also

    2Thank You

    Nishita Tomar 7 years, 2 months ago

    supporting material which may be provided by your school..

    1Thank You

    Nancy Rajput 7 years, 2 months ago

    from were

    1Thank You

    ANSWER

    • Posted by Urvashi Verma 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ankit Aryan Shivan 7 years, 2 months ago

    Theorem of perpendicular axes-The moment of inertia of planer body about an axes perpendicular to the plane is equal to the sum of the moments of inertia(m.i) about two perpendicular axes concurrent with perpendicular axes and line in the plane of the body.(Izz'=Ixx'+ Iyy') about Z-axes.and now,Theorem of parallel axes -The m.i of a body about any axes is equal to the sum of the m.i of body about a parallel axis passing through it centre of mass and the product of its mass and square of the distance between two parallel axes.(Ic+mass of body*square of distance b/w axes).

    2Thank You

    Nancy Rajput 7 years, 2 months ago

    =>Theorem of Perpendicular Axis The moment of inertia of planar body about an axis perpendicular to its plane is equal to the sum of its moments of inertia about two perpendicular axes concurrent with perpendicular axis and lying in the plane of the body. Iz=Ix+Iy =>theorem of parallel axis The moment of inertia of a body about any axis is equal to the sum of the moments of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of distance between the two parallel axes. I=Ig+Md^2

    1Thank You

    Lavanya ❤️? 7 years, 2 months ago

    Parallel axes theorem : The moment of inertia of a rigid body about any axis is equal to the sum of its moment of inertia about a parallel axis through its centre of mass and the product of mass of the body and the square of distance between the two axes. Perpendicular axes theorem : Moment of interia of a rigid plane lamina about an axis perpendicular to its plane is equal to the sum of its moment of inertia about any two mutually perpendicular axes in iys plane and meeting in the point where the perpendicular axis cuts the lamina Hope this will help u ......

    1Thank You

    ANSWER

    • Posted by Vanshika Vanshika 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Deepak Sharma 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Ankita Kushwaha 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Kailash Ji 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Kailash Ji 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Kailash Ji 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Kailash Ji 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Rahul Singh? 7 years, 2 months ago

    W=R(t2-t1)/1-¥

    1Thank You

    Dhan Raj 7 years, 2 months ago

    For an adiabatic process of ideal gas equation we have PVγ = K (Constant) Where γ is the ratio of specific heat (ordinary or molar) at constant pressure and at constant voluume γ = Cp/Cv Suppose in an adiabatic process pressure and volume of a sample of gas changs from (P1, V1) to (P2, V2) then we have P1(V1)γ=P2(V2)γ=K Thus, P = K/Vγ Work done by gas in this process is W = ∫PdV where limits of integration goes from V1 to V2 Putting for P=K/Vγ, and integrating we get, W = (P1V1-P2V2)/(γ-1) In and adiabatic process if W>0 i.e., work is done by the gas then T2< T1 If work is done on the gas (W<0) then T2 > T1 i.e., temperature of gas rises

    1Thank You

    ANSWER

    • Posted by Kailash Ji 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Lavanya ❤️? 7 years, 2 months ago

    Surface tension of the liquid=Force/length multiply length to both numerator and the denominator =Force x length/length x length =work/area So, this show that the surface energy per unit area is equal to the surface tension of the liquid. Hope this will help u.....

    3Thank You

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    • Posted by Amita Sharma 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Shruti Kumari 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ankit Singh 7 years, 2 months ago

    Which question

    0Thank You

    ANSWER

    • Posted by Cute Princess 7 years, 2 months ago

    CBSE > Class 11 > Physics
    • 5 answers

    Cute Princess 7 years, 2 months ago

    ...............

    1Thank You

    Lavanya ❤️? 7 years, 2 months ago

    Your welcome ?

    0Thank You

    Cute Princess 7 years, 2 months ago

    Aman

    0Thank You

    Lavanya ❤️? 7 years, 2 months ago

    Elastic behaviour of solid is a force acting on a body instead of producing a change in its state of rest or of uniform motion, produces a change in the shape of the body. Such a force is called deforming force.

    1Thank You

    Aman Kumar 7 years, 2 months ago

    A solid which can easily regain its original shape and size after applying some force on it.....This behaviour of solid is called elastic behaviour..

    3Thank You

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