CBSE > Class 11 > Physics | CBSE Board | Homework Help

The Physical world around us is full of different complex natural phenomena so the world is in-comprehensible. But with the help of study and observations it has been found that all these phenomena are based on some basic physical laws and so it is comprehensible.

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Define angle of repose show that coefficient of friction is equal to the tangent of angle of repose

Posted by Anshika Rai 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Vivek Singh Bisht 4 years, 1 month ago

At angle of repose the angle of inclination Q is such that W sinQ=f (f =frictional force and of the body begins to slide with zero acceleration

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Resolution of vector in a unit vector

Posted by Grace Samte 4 years, 1 month ago

CBSE > Class 11 > Physics

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Physics wold

Posted by Sūjāl Mēhrā 4 years, 1 month ago

CBSE > Class 11 > Physics

4 answers

Nishtha Mishra 4 years, 1 month ago

Physics wallha

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Sūjāl Mēhrā 4 years, 1 month ago

Hallo

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Sūjāl Mēhrā 4 years, 1 month ago

4Thank You

Sūjāl Mēhrā 4 years, 1 month ago

Phisyes wald

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Hiii anyone here

Posted by Mohit Malviya 4 years, 1 month ago

CBSE > Class 11 > Physics

5 answers

Shreya Rajshree 4 years, 1 month ago

find the angle between vectors p=2i+3j-2k q=3i+2j+4k Please solve

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Shruti Kushwaha 4 years, 1 month ago

Yrr class 11 ki physics sucks!!!???

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Kirti Deshwal 4 years, 1 month ago

Good evening deae

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Himanshi Tyagi 4 years, 1 month ago

Hii

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Uma Pankajam 4 years, 1 month ago

Yes

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Intergation of x cosx

Posted by Priyanka Khatri 4 years, 1 month ago

CBSE > Class 11 > Physics

4 answers

Pragy Bohra 4 years, 1 month ago

X2/2+sinx

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Priyanka Khatri 4 years, 1 month ago

Aagar aap ko aata ha mara question so explain kar do

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Priyanka Khatri 4 years, 1 month ago

Yes

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Mohit Malviya 4 years, 1 month ago

Heyy can we talk

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What is the relative velocity of two bodies having equal velocities

Posted by Tanu Sri 4 years, 1 month ago

CBSE > Class 11 > Physics

3 answers

Sia ? 4 years, 1 month ago

If two bodies have equal velocities, the relative velocity will be 0.

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Vedit Agrawal 4 years, 1 month ago

0000

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Shashank Shukla 4 years, 1 month ago

Zero

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Name two dimensions less quantities

Posted by Kavya Kalal 4 years, 1 month ago

CBSE > Class 11 > Physics

3 answers

Anjan Karthi 4 years, 1 month ago

Density is the mass of a substance per unit volume of the substance. But, RELATIVE density is the RATIO of density of substance to density of H2O.

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Tarun Shakya 4 years, 1 month ago

What is density

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Anjan Karthi 4 years, 1 month ago

1) Relative density. 2) Strain. 3) Angle. (Any two)

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Two cars C¹ and C² moving in the same direction on a straight single lane road with velocities 12m/s and 10m/s respectively. When the separation between the two was 200m C² started accelerating to avoid collision. What is the minimum acceleration of car C² so that they don't collide.

Posted by Rahul Kumar 4 years, 1 month ago

CBSE > Class 11 > Physics

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A particle moving with uniform acceleration from A to B along a straight line has velocities v1 and v2 at A and B, then determine the velocity of particle C if C is the midpoint of the line

Posted by Abhinibesh Gupta 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Anjan Karthi 4 years, 1 month ago

V = 2V1V2/(V1 + V2).//

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A smooth sphere of radius R and mass M is placed on the smooth horizontal floor. Another smooth particle of mass m is placed on the sphere and a horizontal force F is applied on the sphere as shown. If the particle does not slip on the sphere then the value of force F is-. (A) F = mg * cot theta. (C) F = (m + M) * g * cot theta. (B) F = Mg cot 0 (D) F = (m + M) * g * tan theta

Posted by Evjot Kaur 4 years, 1 month ago

CBSE > Class 11 > Physics

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A bus is moving with the velocity 30 km h . On applying the brakes, it comes to rest after traveling a distance 10 m. Calculate the time taken by the bus in coming to rest

Posted by Amrita Mukesh 4 years, 1 month ago

CBSE > Class 11 > Physics

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x=6+3t+2t cube

Posted by Amrita Mukesh 4 years, 1 month ago

CBSE > Class 11 > Physics

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Displacement =( t^3 - 6t^2 - 15t + 20) meter. Find Initial displacement of the particle Displacement in 4th second What is the acceleration of the particle

Posted by Deepali Tripathi 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Mohit Yadav 4 years, 1 month ago

Pta nhi

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A car travels first half distance between two places with a speed of 40 Km/hr and the rest half with a speed of 60 Km/hr. Find the average speed of the car. And derive the equation of motion by using graph method.

Posted by Nikhil Chaudhary 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Anjan Karthi 4 years, 1 month ago

There is a formula which can be directly applied in such situations. V avg = 2 V1 V2 / V1 + V2 = 2 × 60 × 40 / 60 + 40 = 48 km/h.//

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Derive displacement and acceleration using uniform circulation motion

Posted by Grace Samte 4 years, 1 month ago

CBSE > Class 11 > Physics

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What is relation between physics and technology?

Posted by Shravani Dabhade 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Archita Pal 4 years, 1 month ago

In these times technology is observed to rise new physics and at others times physics generate new technology.

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X is equals to 5tsquare+ 9t plus 4 call to 1 second instantaneous t=2 to t=4sec average

Posted by Ravi Porwal 4 years, 1 month ago

CBSE > Class 11 > Physics

2 answers

Anjan Karthi 4 years, 1 month ago

Therefore, Vavg = 29 + 49 / 4 + 2 = 78/6 = 13 m/s.//

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Anjan Karthi 4 years, 1 month ago

X = 5t^2 + 9t + 4 = 5 (2t) + 9 = 10t + 9// Therefore, in 4 s, X = 49 m. In 2 s, X = 29 m.

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Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km h–1 in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 1 m s–2 . If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?

Posted by Lohitha Harish 4 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Sia ? 4 years, 1 month ago

Given that,
u_A = u_B =72 kmh⁻¹= 72 × 185 = 20 ms⁻¹
Using the relations, s = ut + 1/2 at², we get
S_B = u_Bt + 1/2 at²= 20 × 50 + 1/2 × 1 × (50)²
S_B = 1000 + 1250 = 2250m
Also, let S_A be the distance covered by the train A, then S_A = u_A × t
= 20 × 50 = 1000 m
Original distance between the two trains
= S_B− S_A
= 2250 − 1000 = 1250 m