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    • Posted by Suresh Kumar 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Mayank Sahu 6 years ago

    .

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    • Posted by Mahesh Mahi 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Shreeya Agrawal 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Aditya Vishwakarma 6 years ago

    Directrix : x + 5 = 0 Latus Rectum ; 20 Step-by-step explanation: Hi, Given equation of circle is x² + y² - 10x + 9 = 0 Center of circle = (-1/2*coefficient of x, -1/2*coefficient of y) Center of the above circle is ( 5, 0). For the given parabola, Vertex is at Origin O (0, 0) Focus is at the center of the circle , S ( 5, 0) Axis of the parabola is the line joining the vertex and focus of parabola, Since both the vertex and focus have their y-coordinate as 0 Equation of Axis is x-axis which is y = 0. Distance between the Vertex and Focus is 'a' which is 1/4 th of Latus Rectum ⇒1/4 * Latus Rectum = 5 ⇒ Latus Rectum = 20. Directrix is the line perpendicular to the axis and passing through the point Z on the axis such that midpoint of SZ is the vertex of the parabola. Hence , coordinates of Z will be ( -5, 0). Any equal perpendicular to x-axis will be of the form x = k , but this passes through Z( -5, 0),hence Equation of directrix is x = -5. Read more on Brainly.in - https://brainly.in/question/7512302#readmore

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    • Posted by Piyush Saini 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Ipman Akhter 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Ritik Yadav 6 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Ritik Yadav 6 years ago

    yeah Pls send me right answer

    1Thank You

    Ipman Akhter 6 years ago

    Babu Wronge Question hai 90 ki zagah 9 hoga

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    • Posted by Parmeshwar Sande 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Rajeev Hosamani 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Ummed Hussain 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Tannu Rao 6 years ago

    5^^2=125 (5 raised to the power 2)

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    • Posted by Happey Kumar 6 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Mahesh Kumar Yadav 6 years ago

    As we know that the value of x is 0 and then putting the value of x in the equation x+3=0+3=3

    1Thank You

    Ummed Hussain 6 years ago

    Lim/x=0 x+3 Putting the value of x=0 0+3 =3

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    • Posted by Deepak Aasiwal 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Garima Mehra 6 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Garima Mehra 6 years ago

    Sorry but where is anwser

    0Thank You

    Pravas Adak 6 years ago

    Please ask your doubt.

    1Thank You

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    • Posted by Vineet Kumar 6 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Ummed Hussain 6 years ago

    12!/4!3!2! 1663200

    0Thank You

    Garima Mehra 6 years ago

    There are 12 letters ,of which n appears 3 times, e appears 4 times and d appears 2 times and the rest are all different. Therefore the required number of arrangements =12!÷3! 4! 2! = 1663200

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    • Posted by Abhishek Prajapati 6 years ago

    CBSE > Class 11 > Mathematics
    • 5 answers

    Bharat Bhatt 6 years ago

    No, not have to explain but you are capable to do sum easily in short time

    0Thank You

    Shweta Yadav 6 years ago

    No only write your answer

    0Thank You

    Jai Singh 6 years ago

    how to sovle big calculations easily

    0Thank You

    Himanshi Sagar 6 years ago

    No

    0Thank You

    Garvit Jain 6 years ago

    No

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    • Posted by Durga Appa 6 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Ipman Akhter 6 years ago

    12r²+25r+12=0 12r²+9r+16r+12=0 3r(4r+3)+4(4r+3)=0 (3r+4) (4r+3) 3r=-4. 4r=-3 r=-4/3. r=-3/4

    0Thank You

    Maheshwari Mansi 6 years ago

    R=-4/3 or r=-3/4

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    • Posted by Ashish Ah 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Saleem Kumar Lodhawanshi 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Swarnim Singh 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Yuvraj Singh 6 years ago

    Taking LHS cos4x= cos2 (2x) = 1- 2sin^2x = 1- 2 ( 2sinxcosx)^2 = 1-2 (4sin^2xcos^2x) = 1-8sin&2xcos^2x

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    • Posted by Komal Sharma 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Yogi Bhai 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Yuvraj Singh 6 years ago

    [3,5]

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    • Posted by Yash Jain 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Samiksha Sharma 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Sachin Yadav 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Yogita Ingle 6 years ago

    For the first AP, a =3, d = 4
    Hence, any nth term would be given by 3+(n-1)4 = 4n-1
    Also, since 407 is the last term, so, 407 = 4n-1 i.e. maximum value of n can be 102
    For the second AP, a = 2, d = 7
    Hence any mth term would be given by 2+(m-1)7 = 7m - 5
    Also, since 709 is the last terms, so, 709 = 7m-5 i.e. maximum value of m can be 102
    To find the terms common to both the APs, we can equate the nth term of first AP to the mth term of the second AP
    4n -1 = 7m-5
    4n = 7m-4
    Now, since n is a whole number, so 7m-4 needs to be divisible by 4.
    So, then, m can be equal to all multiples of 4 till 102 i.e. 4, 8, 12, 16, 20, 24, ......100
    So, the number of terms common to the 2 APs would be 25. >

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    • Posted by Hariom Pandey 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Kreetika Verma 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Nitin Dadhich 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Rachit Dwivedi 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Aryan Upadhayay 6 years ago

    n(n+1)/2

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    • Posted by Rachit Dwivedi 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Shivam Singh 6 years ago

    Hi

    0Thank You

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    • Posted by Mohamed Fareedh 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Nikita Sagar 6 years ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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