CBSE > Class 11 > Mathematics | CBSE Board | Homework Help

Set bulider form is basically written as the property of elements of a set... For e.g. let A={a,e,i,o,u} Which is the roster form... ...Now,in set builder form A={x:x is a Vowel from the english alphabet}.

0Thank You

Abhay Saxena 4 years, 7 months ago

Explain

0Thank You

ANSWER

What are the methods of presenting General Solution in Trigonometric Functions? Please Answer

Posted by Samarth Kapdi 4 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Gaurav Seth 4 years, 7 months ago

</header>

Definition:
An equation involving one or more trigonometrical ratio of an unknown angle is called a trigonometrical equation

A trigonometric equation is different from a trigonometrical identities. An identity is satisfied for every value of the unknown angle e.g., cos² x = 1 − sin² x is true ∀ x ∈ R, while a trigonometric equation is satisfied for some particular values of the unknown angle.

(1) Roots of trigonometrical equation: The value of unknown angle (a variable quantity) which satisfies the given equation is called the root of an equation, e.g., cos θ = ½, the root is θ = 60° or θ = 300° because the equation is satisfied if we put θ = 60° or θ = 300°.

(2) Solution of trigonometrical equations: A value of the unknown angle which satisfies the trigonometrical equation is called its solution.
Since all trigonometrical ratios are periodic in nature, generally a trigonometrical equation has more than one solution or an infinite number of solutions. There are basically three types of solutions:

Particular solution: A specific value of unknown angle satisfying the equation.
Principal solution: Smallest numerical value of the unknown angle satisfying the equation (Numerically smallest particular solution).
General solution: Complete set of values of the unknown angle satisfying the equation. It contains all particular solutions as well as principal solutions.

Trigonometrical equations with their general solution

Trigonometrical equation	General solution
sin θ = 0	θ = nπ
cos θ = 0	θ = nπ + π/2
tan θ = 0	θ = nπ
sin θ = 1	θ = 2nπ + π/2
cos θ = 1	θ = 2nπ
sin θ = sin α	θ = nπ + (−1)ⁿα
cos θ = cos α	θ = 2nπ ± α
tan θ = tan α	θ = nπ ± α
sin² θ = sin² α	θ = nπ ± α
tan² θ = tan² α	θ = nπ ± α
cos² θ = cos² α	θ = nπ ± α
sin θ = sin α cos θ = cos α	θ = nπ + α
sin θ = sin α tan θ = tan α	θ = nπ + α
tan θ = tan α cos θ = cos α	θ = nπ + α

General solution of the form a cos θ + b sin θ = c

1Thank You

ANSWER

If nth term of AP is n(n-2) then value of 10 term of a is

Posted by Arpit Yadav 4 years, 7 months ago

CBSE > Class 11 > Mathematics

3 answers

Aditya Raj 4 years, 7 months ago

0Thank You

Rohit Pandey 4 years, 7 months ago

10(10-2) =10(8) =10×8=80

1Thank You

Garima Pandey 4 years, 7 months ago

10(10-2)=10*8=80

5Thank You

ANSWER

convert it into complex number question is (8) no. i . ex 5.2 pls and me

Posted by Vaishu Sahu 4 years, 7 months ago

CBSE > Class 11 > Mathematics

2 answers

Gaurav Seth 4 years, 7 months ago

3Thank You

Gaurav Seth 4 years, 7 months ago

Given:

and

Squaring both sides and adding both the equations, we get

and

[ lies in first quadrant]

Therefore, Polar form of is

0Thank You

ANSWER

R.D Sharma chapter sets exercise 1.6 question no 2-4

Posted by Aarohi Singh 4 years, 7 months ago

CBSE > Class 11 > Mathematics

2 answers

Aarohi Singh 4 years, 7 months ago

Ise verify karna h

0Thank You

Atul Yadav 4 years, 7 months ago

Type answer

0Thank You

ANSWER

Write in set builder form x=(-3,0)

Posted by Deepti Sahu Pcm 4 years, 7 months ago

CBSE > Class 11 > Mathematics

2 answers

Ayush पाण्डेय 4 years, 7 months ago

X:X€Z X=-4 and x=0

0Thank You

Samarth Kapdi 4 years, 7 months ago

{x:x € N, x < -3 and > 0}

1Thank You

ANSWER

Rational number

Posted by Siddharth Singhaniya 4 years, 7 months ago

CBSE > Class 11 > Mathematics

3 answers

Aman Jha 4 years, 7 months ago

A number which can be written in the form of p/q , where q is not equal to 0.

0Thank You

Vaishu Sahu 4 years, 7 months ago

it is opposite of irrational number.

0Thank You

Sakshi Gupta Sakshi 4 years, 7 months ago

A number which is in the form of p/q and q≠0 is called rational number.

1Thank You

ANSWER

Prove that: Sin8a.cosa-cos3a.sin6a/cos2a.cosa-sina.sin4a= tan2a

Posted by Nidhi Yadav 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Ex.2.2.class.11

Posted by Karshan Kumar 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Find the derivative of sinxcosx

Posted by Yash Chaudhary 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

1+2=

Posted by Dhiraj G 4 years, 7 months ago

CBSE > Class 11 > Mathematics

5 answers

Komal Kaur 4 years, 7 months ago

1Thank You

Dev Kumar 4 years, 7 months ago

1Thank You

Pavan Kumar 4 years, 7 months ago

1Thank You

Sonami Barik 4 years, 7 months ago

How

2Thank You

Dhiraj G 4 years, 7 months ago

3Thank You

ANSWER

Let f(x)=x×x and g(x)=√,x ,then

Posted by Rahul Sheokand 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Let f(x)=x×x and g(x)=√,x ,then

Posted by Rahul Sheokand 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

I got 99 in maths

Posted by Akanksha Shrivastava 4 years, 7 months ago

CBSE > Class 11 > Mathematics

5 answers

Angel Biju 4 years, 7 months ago

Congratulations

2Thank You

Davender Kumar 4 years, 7 months ago

Yes

2Thank You

Davender Kumar 4 years, 7 months ago

I got 100

2Thank You

Davender Kumar 4 years, 7 months ago

Good

3Thank You

Akanksha Shrivastava 4 years, 7 months ago

In 10th board cbse

3Thank You

ANSWER

2cosa+ cos2a=??

Posted by Sheetal Sheetal 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

2cosa+ cos2a=??

Posted by Sheetal Sheetal 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Value of sin180

Posted by Deepak Singh 4 years, 7 months ago

CBSE > Class 11 > Mathematics

5 answers

Vaishnavi Joshi 4 years, 7 months ago

0Thank You

Dev Kumar 4 years, 7 months ago

0Thank You

Sonami Barik 4 years, 7 months ago

0Thank You

Davender Kumar 4 years, 7 months ago

0Thank You

Yogita Ingle 4 years, 7 months ago

From the value of sin 0, we will obtain the value of sin 180.

We know that the exact value of sin 0 degree is 0.

So, Sin 180 degree is +(sin 0) which is equal to +(0)

Therefore, the value of sin 180 degrees = 0.

The value of sin pi can be derived from some other trigonometric angles and functions like sine and cosine functions from the <a href="https://byjus.com/maths/trigonometry-table/">trigonometry table</a>.

It is known that,

180° – 0° = 180° ———– (1)

270° – 90° = 180°———— (2)

Sine 180 Degree Derivation: Method 1

Now we can use the above expression (1) in terms of sine functions

From the supplementary angle identity,

Sin A = Sin (180° – A )

Therefore,

Sin ( 180° – A ) = Sin A

Sin ( 180° – 0° ) = Sin 0°

Sin 180° = 0 [ Since the value Sin 0° is 0]

0Thank You

ANSWER

Sin^5 +cos^5=?

Posted by Gaurav Kumar 4 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Aarohi Singh 4 years, 7 months ago

2sin^5/2+cos^5/2 Yeh half angle formula se banega

0Thank You

ANSWER

Tan20°tan30°tan40° tan80°

Posted by Rippen Sidhu 4 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Gaurav Seth 4 years, 7 months ago

Step -by -step explanation:

tan20° tan40° tan80°

= 2sin20°sin40°sin80°/2cos20°cos40°cos80°

= {cos(20°-40°)-cos(20°+40°)}sin80°/{cos(20°+40°)+cos(20°-40°)}cos80°

= (cos20°-cos60°)sin80°/(cos60°+cos20°)cos80°

= {2cos20°sin80°-2(1/2)sin80°}/{2(1/2)cos80°+2cos20°cos80°} [∵,cos60°=1/2]

= {sin(20°+80°)-sin(20°-80°)-sin80°}/{cos80°+cos(20°+80°)+cos(20°-80°)}

= (sin100°+sin60°-sin80°)/(cos80°+cos100°+cos60°)

= {2cos(100°+80°)/2sin(100°-80°)/2 +√3/2}/{2cos(100°+80°)/2cos(100°-80°)/2+1/2} [∵, sin60°=√3/2 and cos60°=1/2]

= (2cos90°sin10°+√3/2)/(2cos90°cos10°+1/2)

= (√3/2)/(1/2) [∵, cos90°=0]

= √3

= tan60°

Now, tan30°tan60° = *= 1

2Thank You

ANSWER

Ch 2 ex 2.3 ques 2

Posted by Aditya Raj 4 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Vasu Rajput. 4 years, 7 months ago

X:x is atwo -digit natural number such that the sum of digit is i8

2Thank You

ANSWER

3 sinp + 4 cos theta equal to 6 and 4 sin theta + 3 cos b equal to 1 then find the value of angle or

Posted by Aryan Singh 4 years, 7 months ago

CBSE > Class 11 > Mathematics

1 answers

Gaurav Seth 4 years, 7 months ago

3sinP+4cosQ=6 -----(1)

4sinQ+3cosP=1 -----(2)

square and add both the equations,

so we get,

p+q=150

now apply theorem of sum of angles of triangle,

P+Q+R=180

we know that, P+Q=150

so,

R=180°-150°

R=30°

Therefore,

R=π/6

The correct answer is:

1Thank You

ANSWER

3 sinp +4cos

Posted by Aryan Singh 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

find mean and varience of natural number

Posted by Mohit Giri 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Find domain and range F(x)=)√(x-1)

Posted by Akshay S S 4 years, 7 months ago

CBSE > Class 11 > Mathematics

3 answers

Anami Sharma 4 years, 7 months ago

0Thank You

Atharv Rokade 4 years, 7 months ago

Domain = R-{1} Range - [-infinity to 1)

0Thank You

Yogita Ingle 4 years, 7 months ago

f(x) exist if (x-1)>equal to 0.now , x> equal to 1.Therefore domain is [1, infinity). range [0,infinity).? l hope this really help you. ?????

3Thank You

ANSWER

how to prove cot a - cot 2a=cosec2a

Posted by Rashi Hims 4 years, 7 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Converted into polar form:1-i

Posted by Prince Kumar Singh 4 years, 7 months ago

CBSE > Class 11 > Mathematics

2 answers

Yogita Ingle 4 years, 7 months ago

?if z lies in 1st quadrant then alpha = theta, 2nd quadrant then alpha =π-theta, 3rd quadrant then alpha = -(π-theta) and 4th quadrant then alpha = - theta. ? this will really help you?.

1Thank You

Yogita Ingle 4 years, 7 months ago

z=x+iy. =1+i. x=1, y= -1. consider, x=rcos theta and y=rsin theta.--------eq (1) now r=root over x²+y²= root over 1²+(-1)²= √2. [r = √2].from eq (1).√2cos theta =1and √2sin theta= -1.cos theta=1/√2 & sin theta = -1/√2. as theta lies in 4th quadrant .α = - theta. theta = -1/√2= - π/4.α= - theta= - π/4. z=r(cos theta+i sin theta) . z=√2[cos(-π/4)+ i sin(-π/4).

1Thank You

ANSWER

How many km in m

Posted by Gautam Gupta 4 years, 7 months ago

CBSE > Class 11 > Mathematics