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i^537+i^539+i^541 =i.i^536+i.i^538+i.i^540 =i.(i^2)^268+i.(i^2)^269+i.(i^2)^270 =i.1+i.(-1)+i.1 [because (i^2)^even no.=1 and (i^2)^odd no.=-1] =i-i+i =i

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i^537 +i^539 + i^541 ___________________ = i^534 + i^536+ i^538 Please someone send the steps of the answer.

Posted by Athmapriya P 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Gargi Aggarwal 5 years, 4 months ago

i^537+i^539+i^541 =i.i^536+i.i^538+i.i^540 =i.(i^2)^268+i.(i^2)^269+i.(i^2)^270 =i.1+i.(-1)+i.1 [because (i^2)^even no.=1 and (i^2)^odd no.=-1] =i-i+i =i

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Deepak bhai ye anwer nahi hai . Koi mujhe sahi answer de do What is the value of pie /8 . Ye 3rd lesson ka example hai

Posted by Unique #Seraj Ali ??? 5 years, 4 months ago

CBSE > Class 11 > Mathematics

4 answers

Manisha Dhibar 5 years, 4 months ago

π=180°;π/8=22.5°

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Harsh Singh 5 years, 4 months ago

22.5

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Abhinandan Uday Mangla 5 years, 4 months ago

π = 180° So, π/8 = 22.5°

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Gaurav Seth 5 years, 4 months ago

Solution:

Let Ф = π/8
2Ф = π/4
tan 2Ф = 1 = 2 tan Ф / [ 1 - tan² Ф ]
1 - tan² Ф = 2 tan Ф
tan² Ф + 2 tan Ф - 1 = 0
tan Ф = 1/2 [ -2 +- √(4 +4) ] = -1 +- √2
tan π/8 is > 0

Therefore, tan π/8 = √2 - 1

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Find the value of tan pie/8 please

Posted by Unique #Seraj Ali ??? 5 years, 4 months ago

CBSE > Class 11 > Mathematics

4 answers

Vanshika Goyal 5 years, 3 months ago

Let Ф = π/8 2Ф = π/4 tan 2Ф = 1 = 2 tan Ф / [ 1 - tan² Ф ] 1 - tan² Ф = 2 tan Ф tan² Ф + 2 tan Ф - 1 = 0 tan Ф = 1/2 [ -2 +- √(4 +4) ] = -1 +- √2 tan π/8 is > 0 Therefore, tan π/8 = √2 - 1

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Unique #Seraj Ali ??? 5 years, 4 months ago

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Dεερακ Ȿιηɠꜧ 5 years, 4 months ago

Tan180/8 = tan 22.5 = tan 45/2

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Unique #Seraj Ali ??? 5 years, 4 months ago

With full explanation

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1-i in polar form

Posted by Mansi Verma 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Abhinandan Uday Mangla 5 years, 4 months ago

In polar form, z= 1(Cos π/2 + i Sin π/2) Where r = 1 and ∅ = π/2(90°)

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Write the dimensions of a/b in the relation f=a√x +bt²

Posted by Aryan Kumar 5 years, 4 months ago

CBSE > Class 11 > Mathematics

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What is the answer of i•35

Posted by Krish Joshi Joshi 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Anshu Singh 5 years, 4 months ago

i=√-1 So √-1*35= 35√-1 or 35i

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????What is Co-domein? ????

Posted by Shakti Singh Rajput 5 years, 4 months ago

CBSE > Class 11 > Mathematics

5 answers

S Thakur 5 years, 4 months ago

Set b

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Aryan Kumar 5 years, 4 months ago

Co Domein is the 2nd Part

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Sujal Kadam 5 years, 4 months ago

Co-domein

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Vaishali ..... 5 years, 4 months ago

set B

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Aarohi Singh 5 years, 4 months ago

Set B ko hi co-domain kehte h

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|lx-2l -3|>1

Posted by Gauri Kumari 5 years, 4 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

?what is complex numbers? pls ans me ???

Posted by Vaishali ..... 5 years, 4 months ago

CBSE > Class 11 > Mathematics

4 answers

Abhinandan Uday Mangla 5 years, 4 months ago

A complex number is a combination of a real and an imaginary number. Z=a+bi Here, z is the complex number, a is the real part of the number and b is the imaginary part where i (iota) = -1

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Jothi Prasath 5 years, 4 months ago

A combination of real and imaginary parts is known as complex number

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Yogita Ingle 5 years, 4 months ago

Complex Numbers Class 11 – A number that can be represented in form p + iq is defined as a complex number. [Where, p and q are real numbers and i=−1−−−√]. For a complex number z = p + iq, p is known as the real part, represented by Re z and q is known as the imaginary part represented by Im z of complex number z.

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Santan Kumar Singh 5 years, 4 months ago

Having more than two factors

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What is ser

Posted by Debasis Panda 5 years, 4 months ago

CBSE > Class 11 > Mathematics

3 answers

Dεερακ Ȿιηɠꜧ 5 years, 4 months ago

Set is combination of different elements, variable etc.

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Abhinandan Uday Mangla 5 years, 4 months ago

A set is a combination of various distinct elements

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Abhijeet Kharche 5 years, 4 months ago

Smooth endoplasmic reticulum In the nucleus of a cell

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evaluate under root 4+3 under root -20

Posted by Fardeen Malik 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Aditya Raj 5 years, 4 months ago

√(4+6√5iota)

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Let A{1,2,3} B{2,3,4,5}

Posted by Puja Mohan 5 years, 4 months ago

CBSE > Class 11 > Mathematics

3 answers

Manisha Dhibar 5 years, 4 months ago

Complete the question

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Aksh Deep 5 years, 4 months ago

Hi plz ask full question

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Aarohi Singh 5 years, 4 months ago

This is not a complete question

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For all sets A, B & C show that (A-B) intersection with (C-B)=A-(B union with C)

Posted by Vivek Mishra 5 years, 4 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Find the domain and range of the function f(x)=1/(√9-x^2).

Posted by Shreya Dubey 5 years, 4 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

What is set builder form

Posted by Mahima Choubey 5 years, 4 months ago

CBSE > Class 11 > Mathematics

3 answers

Vivek Mishra 5 years, 4 months ago

In Set bulider form we search for an suitable identity of an element of set. As given in example

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Shreya Dubey 5 years, 4 months ago

Set bulider form is basically written as the property of elements of a set... For e.g. let A={a,e,i,o,u} Which is the roster form... ...Now,in set builder form A={x:x is a Vowel from the english alphabet}.

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Abhay Saxena 5 years, 4 months ago

Explain

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What are the methods of presenting General Solution in Trigonometric Functions? Please Answer

Posted by Samarth Kapdi 5 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

</header>

Definition:
An equation involving one or more trigonometrical ratio of an unknown angle is called a trigonometrical equation

A trigonometric equation is different from a trigonometrical identities. An identity is satisfied for every value of the unknown angle e.g., cos² x = 1 − sin² x is true ∀ x ∈ R, while a trigonometric equation is satisfied for some particular values of the unknown angle.

(1) Roots of trigonometrical equation: The value of unknown angle (a variable quantity) which satisfies the given equation is called the root of an equation, e.g., cos θ = ½, the root is θ = 60° or θ = 300° because the equation is satisfied if we put θ = 60° or θ = 300°.

(2) Solution of trigonometrical equations: A value of the unknown angle which satisfies the trigonometrical equation is called its solution.
Since all trigonometrical ratios are periodic in nature, generally a trigonometrical equation has more than one solution or an infinite number of solutions. There are basically three types of solutions:

Particular solution: A specific value of unknown angle satisfying the equation.
Principal solution: Smallest numerical value of the unknown angle satisfying the equation (Numerically smallest particular solution).
General solution: Complete set of values of the unknown angle satisfying the equation. It contains all particular solutions as well as principal solutions.

Trigonometrical equations with their general solution

Trigonometrical equation	General solution
sin θ = 0	θ = nπ
cos θ = 0	θ = nπ + π/2
tan θ = 0	θ = nπ
sin θ = 1	θ = 2nπ + π/2
cos θ = 1	θ = 2nπ
sin θ = sin α	θ = nπ + (−1)ⁿα
cos θ = cos α	θ = 2nπ ± α
tan θ = tan α	θ = nπ ± α
sin² θ = sin² α	θ = nπ ± α
tan² θ = tan² α	θ = nπ ± α
cos² θ = cos² α	θ = nπ ± α
sin θ = sin α cos θ = cos α	θ = nπ + α
sin θ = sin α tan θ = tan α	θ = nπ + α
tan θ = tan α cos θ = cos α	θ = nπ + α