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Ask QuestionPosted by Madhur Taneja 8 years, 4 months ago
- 0 answers
Posted by Saundarya Saundarya 8 years, 4 months ago
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Posted by Mayank Raj 8 years, 4 months ago
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Posted by Shivam Gupta 8 years, 4 months ago
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Posted by Tanveee Alam 8 years, 4 months ago
- 1 answers
Jagdish Padaliya 8 years, 4 months ago
Posted by Rohit Rattan 8 years, 4 months ago
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Posted by Akhil Ganapathy 8 years, 4 months ago
- 1 answers
Soumya Ghoshal 8 years, 4 months ago
In trigonometry,
31π/3
=31×180°÷3
=31×60°
=1860°
Or, in mensuration,
31π/3
=31×22/7÷3
=32.49
Posted by Vaibhav Bhootra 8 years, 4 months ago
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Posted by Rekha Pandey 8 years, 4 months ago
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Posted by Desaraju Sandhya 8 years, 4 months ago
- 1 answers
Sahdev Sharma 8 years, 4 months ago
The letters have to be arranged in such a way that there are always 4 letters between P and S.
Therefore, in a way, the places of P and S are fixed. The remaining 10 letters in which there are 2 Ts can be arranged in {tex}10!\over 2 !{/tex} ways
Also, the letters P and S can be placed such that there are 4 letters between them in {tex} 2 \times 7 = 14{/tex} ways.
Therefore, by multiplication principle, required number of arrangements in this case = {tex}{10!\over 2!}\times 14 = {/tex}
25401600
Posted by Gaurav Kumar 8 years, 4 months ago
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Posted by Vydehi Ajith 8 years, 4 months ago
- 2 answers
Bhavesh Batra 8 years, 4 months ago
H S 8 years, 4 months ago
Posted by Anuradha Yadav 8 years, 4 months ago
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Ishant Sehrawat 8 years, 4 months ago
Posted by Anuradha Yadav 8 years, 4 months ago
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Posted by Ajay Kumar 8 years, 4 months ago
- 1 answers
Dharmendra Kumar 8 years, 4 months ago
A set B is said to be a subset of set A if every elements of B are in set A.
for example:- let A={1,2,3}
then B= {1,2} is subset of set A as every element of B i.e.1 and 2 is also element of set A.
Similarly C={1} is also a subset of set A as element of C i.e.1 is in set A.
Posted by Nagaraj Vasanad 8 years, 4 months ago
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Posted by Sharad Thakur 8 years, 4 months ago
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Ajith Selva 8 years, 4 months ago
Posted by Shivam Tyagi 8 years, 4 months ago
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Posted by Manish Sahu 8 years, 4 months ago
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Posted by Arnav Singh 8 years, 4 months ago
- 1 answers
Rahul Kumar 8 years, 4 months ago
Area is a scalar quantiti..because there ia no need of dimension to define area..
Posted by Abhishek Kumar 8 years, 4 months ago
- 1 answers
Dharmendra Kumar 8 years, 4 months ago
Set builder form of {1,-1,i,-i} is
A={x: x is the solution of eqaution (x2 -1)(x2 +1)=0}
={x: x is the solution of equation x4 - 1=0} [by using identity (a-b)(a+b)=a2 - b2]
Posted by Shaanj Sha 8 years, 4 months ago
- 1 answers
Dharmendra Kumar 8 years, 4 months ago
A={-1,1}
A×A={-1,1}×{-1,1}
= {(-1,-1),(-1,1),(1,-1),(1,1)}
Now A×A×A={(-1,-1),(-1,1),(1,-1),(1,1)}×{-1,1}
= {(-1,-1,-1),(-1,-1,1),(-1,1,-1),(-1,1,1),(1,-1,-1),(1,-1,1),(1,1,-1),(1,1,1)}
Posted by Kailash Goswami 4 years, 8 months ago
- 1 answers
Posted by Manbeer Singh 8 years, 4 months ago
- 1 answers
Dharmendra Kumar 8 years, 4 months ago
No, its not necessary.
For example:- let z1= 3+4i and z2= 4+3i
Then |z1| ={tex}{\sqrt {3^2 +4^2}}={\sqrt {9+16}}={\sqrt {25}}=5{/tex}
Also |z2| ={tex}{\sqrt {4^2+3^2}}={\sqrt {16+9}}={\sqrt {25}}=5{/tex}
So clearly |z1| = |z2| =5
But z1 done not equal to z2 as real part and imaginary part of z1 is not equal to real part and imaginary part of z2
Posted by Dhruvrajsinh Jadeja 8 years, 4 months ago
- 1 answers
Dharmendra Kumar 8 years, 4 months ago
tan1°tan2°tan3°.........tan89°=tan(90°-89°)tan(90°-88°)tan(90°-87°)...............tan(90°-46°)tan45°tan46°.....tan89°
= cot89°cot88°cot87°..........cot46°tan45°tan46°......tan89° [by using identity tan(90°-A)= cotA]
={tex}1\over tan89°{/tex}×{tex}1\over tan88°{/tex}×.........{tex}1\over tan46°{/tex}×tan45°×tan46°×......tan88°×tan89°
= tan45° =1
Posted by Satyam Kumar 8 years, 4 months ago
- 1 answers
Rishu Mathematician 8 years, 4 months ago
Solve:
{tex} √i+√(-i){/tex}
{tex}=√(e^(i π/2) )+√(〖-e〗^(i π/2) ){/tex}
{tex}=〖e〗^(i π/4)+ie^(i π/4){/tex}
{tex}=〖e〗^(i π/4) (1+i){/tex}
{tex}=〖e〗^(i π/4) (√2 e^(i π/4)){/tex}
{tex}=√2 e^(i π/2){/tex}
{tex}=i√2{/tex}
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