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Paidi Gowtham 8 years, 3 months ago
*cos1740=cos(180*9+120)=sin(120) it is changed to sin due to odd multiple. therefore sin(120)=sin(90+30)=cos(30)=root3/2
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Ilu Ahirwar 8 years, 3 months ago
{tex}(x-x^3)^{1\over 3}\over (x^3){1\over 3}{/tex}
Taking cube of both numerator and denominator, we get
{tex}(x-x^3)^3*{1\over 3} \over (x^3)^3*{1\over 3}{/tex} = {tex}(x-x^3)\over x^3{/tex}
{tex}x(1-x^2)\over x^3{/tex} = {tex}(1-x^2)\over x^2{/tex}.
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