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Yogita Ingle 4 years, 4 months ago
LHS = tanO/(1-cotO) + cotO/(1-tanO)
=
= [1 +(1/cosecOsecO)]/[1/cosecOsecO]
=[(cosecOsecO+1)/cosecOsecO]*[cosecOsecO]
=cosecOsecO+1
=RHS
Hence proved
Posted by Saloni ? 4 years, 4 months ago
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Posted by Saloni ? 4 years, 4 months ago
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Yogita Ingle 4 years, 4 months ago
A={1,2,3,4,5,6,7,8,9,10} B={2,3,5,7}
(A ∩B) = {1,2,3,4,5,6,7,8,9,10} ∩ {2,3,5,7}
= {2,3,5,7}
= B
Posted by Saloni ? 4 years, 4 months ago
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Yogita Ingle 4 years, 4 months ago
Let A={1,3,5,9,18} implies O(A)=5
Now, number of proper subsets of
A=2O(A)−1=25−1= 32 - 1 = 31
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Aditya Singh 4 years, 4 months ago
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Gaurav Seth 4 years, 4 months ago
A three digit number is to be formed from given 9 digits 1,2,3,4,5,6,7,8,9.
□□□HTO
⇒Now, there are 9 ways to fill Ones place.
⇒Since repetition is not allowed, so Tens place can be filled by the remaining 8 digits.
So, tens place can be filled in 8 ways.
⇒Similarly, to fill Hundreds of places, we have 7 digits remaining.
So, hundreds can be filled by 7 ways.
⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504
Yogita Ingle 4 years, 4 months ago
A three digit number is to be formed from given 9 digits 1,2,3,4,5,6,7,8,9.
⇒Now, there are 9 ways to fill Ones place.
⇒Since repetition is not allowed, so Tens place can be filled by the remaining 8 digits.
So, tens place can be filled in 8 ways.
⇒Similarly, to fill Hundreds of places, we have 7 digits remaining.
So, hundreds can be filled by 7 ways.
⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504
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Legendary 4 years, 4 months ago
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