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  • 2 answers

Sakshi Aggarwal 4 years, 3 months ago

By first principal F(x) h=0 =tan(x+h)-tan(x)upon h {tanA+B=1+tanAtanB upon tanA-tanB} =1+tanxtanh-tanx upontanx-tanh. h =

Raunak Chauhan 4 years, 3 months ago

Sec²x
  • 3 answers

Anurag Singh 4 years, 3 months ago

CLGQKBC

Sneha Goel 4 years, 3 months ago

CLGQKBC" The pattern followed is - I - skip one letter then the next one is used(K) N - the previous letter is used(M) D -skip one letter then the next one is used(F) I -the previous letter is used(H) A -skip one letter then the next one is used(C) Hope it helps you...

Tanisha Chawla 4 years, 3 months ago

Hello I think the answer would be - "CLGQKBC" The pattern followed is - I - skip one letter then the next one is used(K) N - the previous letter is used(M) D -skip one letter then the next one is used(F) I -the previous letter is used(H) A -skip one letter then the next one is used(C)
  • 1 answers

Neev Garg 4 years, 3 months ago

Cosx
  • 1 answers

Shailendra Dhukia 4 years, 3 months ago

d/dx(sinx)=cosx d/dx(cosx)=-sinx d/dx(tanx)= sec••x ••= square
  • 2 answers

Neelesh Shukla 4 years, 3 months ago

This answer is wrong

Lucky Sharma 4 years, 3 months ago

Tan60°
  • 1 answers

Shailendra Dhukia 4 years, 3 months ago

d/dx(secx )= secx.tanx
  • 1 answers

Mahima Pattanayak 4 years, 3 months ago

Answer: 5 degree 37 minute 30 second=0.098 Radians.
  • 1 answers

Jagdish 4 years, 3 months ago

Add 20/7 to 3 to get first number then add it again to obtain next number Common difference = (last term - first term)/no. of numbers to be inserted +1 = (23-3)/6+1 = 20/7
  • 3 answers

Nishant Dhakare 4 years, 3 months ago

Yes not for exams also for you intelligence improvement , in miscellaneous exercises question level os very suprb

Vivek Pandey 4 years, 3 months ago

Yes v imp

Sameer Tanwar 4 years, 3 months ago

Yes miscellaneous example and exercise both are important as it covers nice questions which improves your understanding the topic
  • 0 answers
  • 1 answers

Sameer Tanwar 4 years, 3 months ago

We know that i) sin 2A = 2sinAcosA ii) sin(90-A)= cosA iii) sin30=1/2 LHS = sin 10 sin30 sin50sin 70 =sin 10 × 1/2 × sin (90-40)× sin(90-20) =1/2[sin 10 ×cos 40×cos 20] We multiply with[2 cos 10/2cos 10] =(1/2×1/2cos10)[2sin10cos10×cos20×cos40] =(1/4cos10)[sin20cos20×cos40] =(1/8cos10)[2sin20cos20×cos40] =(1/8cos10)[sin40cos40] =(1/16cos10)[2sin40co40] =(1/16cos10)×sin80 =(1/16cos10)×sin(90-10) =(1/16cos10)×cos10 =1/16 = RHS
  • 2 answers

Vineeta . 4 years, 3 months ago

U may search on YouTube u will get better explanation

Manvi Gupta 4 years, 4 months ago

Of NCERT or any other reference book...
  • 0 answers
  • 3 answers

Rudransh Bhargava 4 years, 4 months ago

7568zc fyi

Deepanshu Tyagi 4 years, 4 months ago

d/dx(3√x)=3/2√x

Swastik . P 4 years, 4 months ago

d/dx(3x^1/2) It will be. 3/2 x^-1/2 It can further written as 3/2√x
  • 5 answers

Deepanshu Tyagi 4 years, 4 months ago

(3-x)=|x-3| Remove modulus- ±(3-x)=x-3 3-x=x-3 or -(3-x)=x-3 x=9/2 or -3+x=x-3 x=9/2 or 0=0 So,x=9/2

Swastik . P 4 years, 4 months ago

X=9/2

Malavika Manoj 4 years, 4 months ago

X= 3

Aditya Kumar 4 years, 4 months ago

The value of x will be 3

Raunak Chauhan 4 years, 4 months ago

The value o x is 3
  • 1 answers

Aditya Kumar 4 years, 4 months ago

Eccentricity of the question is 2/3
  • 0 answers
  • 1 answers

Raunak Chauhan 4 years, 4 months ago

First we have to find the mid point of b and c Mid point of b and c is (5/2,3/2) then length of altitude is √(2-5/2)²+(3-3/2)² √1/4+9/4 √5/2 is the length of altitude from vertex A on the side BC We can find equation by using formula two point form page number 214 ncert math
  • 1 answers

Deepanshu Tyagi 4 years, 4 months ago

{-2,-1,0,1,2,3,4,5,6}
  • 2 answers

Raunak Chauhan 4 years, 4 months ago

We can use any two point to find out the slope

Sakshi Verma 4 years, 4 months ago

A line have three points A,B,and C then first find the slope of AB and BC add of these is equal to AC Shorty AB+BC=AC AC is slope of the line

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