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  • 1 answers

Lata Kumari 3 years, 5 months ago

A power set is a set of collection of all the subsets of a set
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  • 1 answers

Ishita Gupta 3 years, 5 months ago

By rationalising.. (√3-1/√3+1)×(√3-1/√3-1) = (√3-1)²/(√3)²-(1)²[(a+b)(a-b)=a²-b²] = (3+1-2√3)/2 [(a-b)²=a²+b²-2ab] = (4-2√3)/2 = 2(2-√3)/2 = 2-√3= RHS
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  • 2 answers

❤️Ritesh Gupta? 3 years, 5 months ago

Jjddkd

Gurleen Singh 3 years, 5 months ago

Let x be any element of A - (B ∩ C). Then, x ∈ A - (B ∩ C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ (A - B) or x ∈ (A - C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ (A - B) or x ∈ (A - C) ⇒ x ∈ (A - B) ∪ x ∈ (A - C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ (A - B) or x ∈ (A - C) ⇒ x ∈ (A - B) ∪ x ∈ (A - C) ∴ A - (B ∩ C) ⊆ (A - B) ∪ (A - C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ (A - B) or x ∈ (A - C) ⇒ x ∈ (A - B) ∪ x ∈ (A - C) ∴ A - (B ∩ C) ⊆ (A - B) ∪ (A - C) Similarly, (A - B) ∪ (A - C) ⊆ A - (B ∩ C) ⇒ x ∈ A and x ∉ (B ∩ C) ⇒ x ∈ A and (x ∉ B or x ∉ C) ⇒ (x ∈ A and x ∉ B) or (x ∈ A and x ∉ C) ⇒ x ∈ (A - B) or x ∈ (A - C) ⇒ x ∈ (A - B) ∪ x ∈ (A - C) ∴ A - (B ∩ C) ⊆ (A - B) ∪ (A - C) Similarly, (A - B) ∪ (A - C) ⊆ A - (B ∩ C) Hence, A - (B ∩ C) = (A - B) ∪ (A - C) Step-by-step explanation: HOPE THIS WILL HELP YOU THANKS?
  • 2 answers

Vishal Verma 3 years, 5 months ago

Subsets - (phi), (1), (phi,1)

Rakesh Kumar 3 years, 5 months ago

Subsets--- A (phi) and A (1)
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  • 2 answers

Bhaduram Hembra 3 years, 5 months ago

18

Chandana Bc 3 years, 6 months ago

Root -3×-6=root (18)²=18
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  • 1 answers

Dharmendra Gupta 3 years, 5 months ago

1
  • 1 answers

Khushi Kim 3 years, 6 months ago

Trigonometry function
  • 1 answers

Gokul Joshi 3 years, 6 months ago

(-,+,-)
  • 1 answers

Sia ? 3 years, 6 months ago

Given,  It should be n(A∪B)

n(A)=200   n(B)=300    n(A∩B)=100

Then n(A∪B)=n(A)+n(B)−n(A∩B)

n(A∩B)=200+300−100

= 500−100

= 400 

  • 2 answers

Poonam Mittewad 3 years, 5 months ago

It is used

Mohammad Anas 3 years, 6 months ago

Nothing
  • 1 answers

Yug Patel 3 years, 6 months ago

x=8
  • 2 answers

Sachin Kumar 3 years, 5 months ago

(-1, infinite)

Jyotsana Arora 3 years, 6 months ago

[-1, ♾️)
  • 1 answers

Gaurav Kumar 3 years, 6 months ago

Is alway 7 because they are not contain any variable only constant they contain so Answer is 7
  • 5 answers

Dharmendra Gupta 3 years, 5 months ago

Range (-ve infinity,0) union 1 to infinity

Sanvi Gupta 3 years, 6 months ago

Thanks for the answer but Could u please tell that how to calculate the range of this question.

Jyotsana Arora 3 years, 6 months ago

Domain = R- {-1,1} Range = (0,1]

Sanvi Gupta 3 years, 6 months ago

But I have asked the range

Gaurav Kumar 3 years, 6 months ago

Domain of this question is R - {1,-1}.

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