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Sia ? 4 years, 5 months ago
Given, It should be n(A∪B)
n(A)=200 n(B)=300 n(A∩B)=100
Then n(A∪B)=n(A)+n(B)−n(A∩B)
n(A∩B)=200+300−100
= 500−100
= 400
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Sia ? 4 years, 6 months ago
An open interval does not include its endpoints and is indicated with parentheses. For example, (0,1) describes an interval greater than 0 and less than 1. A closed interval includes its endpoints and is denoted with square brackets rather than parentheses.
Gokul Joshi 4 years, 5 months ago
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Abhishek Kumar Sharma 4 years, 6 months ago
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Account Deleted 4 years, 6 months ago
Write it as cos (45-30) - sin(45-30)
Now open both the functions as
= cos 45 cos 30 + sin 45 sin 30 - sin 45 cos 30 + sin 30 cos 45
Putting the values as learned in class X
{tex}{1\over \sqrt2} *{\sqrt3\over2} +{1\over \sqrt2} *{1\over2} - {1\over \sqrt2} *{\sqrt3\over2} +{1\over2} *{1\over \sqrt2} {/tex}
Solving we get
= {tex}1\over\sqrt2{/tex}
Answer.
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Sia ? 4 years, 6 months ago
cos 765
= cos (765 - 360)
= cos (405)
= cos (405 - 360)
= cos (45)
= (sqrt2)/2
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