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Ram Kushwah 7 years ago
{tex}\begin{array}{l}\frac d{dx}(\;(2x+3)(3x-5)=(3x-5)\frac{\displaystyle d}{\displaystyle dx}(2x+3)\;+(2x+3)\frac{\displaystyle d}{\displaystyle dx}(3x-5)\\(3x-5)(2)+(2x+3)(3)\\=6x-10+6x+9\\=12x-1\end{array}{/tex}
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Dadul Talukdar 7 years ago
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