CBSE > Class 11 > Mathematics | CBSE Board | Homework Help

Example if you want to make set of all staff students and clerks group of your school so you can put by making set of teachers students and clerks in a one set and that set is called universal set

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What is power set????

Posted by Sumit Kumar 6 years, 6 months ago

CBSE > Class 11 > Mathematics

3 answers

Urvi Sharma 6 years, 6 months ago

Power set is the only set which elements are again in set form

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Jignesh Patel 6 years, 6 months ago

The collection of all subsets of a set A is called the power set of A.

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Vaghesh Jadav 6 years, 6 months ago

All subset of set A is called power set

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How to prove demorgan's law

Posted by Pallavi Patel 6 years, 6 months ago

CBSE > Class 11 > Mathematics

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Find the domain and range of the function f(x) is equal to square -9 upon x-3

Posted by Rahul Dalal 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Here {tex}f(x) = \frac{{{x^2} - 9}}{{x - 3}}{/tex}
f (x) assume real values for all real values of x except for x - 3 = 0 i.e .x = 3
Thus domain of f (x) = R - {3}
Let f (x) = y
{tex}\therefore y = \frac{{{x^2} - 9}}{{x - 3}} = \frac{{(x + 3)(x - 3)}}{{(x - 3)}}{/tex}
{tex} \Rightarrow {/tex} y = x + 3
y takes all real values except 6 as domain =R-{3}
Thus range of f (x) = R - {6}.

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In a group of 400 people! 250 can speak English only and 70 can speak hindi only. 1.How many can speak English? 1.How many can speak hindi only?

Posted by Rohit Choudhary 6 years, 6 months ago

CBSE > Class 11 > Mathematics

2 answers

Aman Jha 6 years, 6 months ago

Wrong Question

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Ayush Vishwakarma?? 6 years, 6 months ago

Question galat hai

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Which book is best for maths guide?

Posted by The Lyrer 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

RD Sharma

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Prove that sec^2 a +cosec^2 a greater than equal to 4

Posted by Bhagwati Vashisth 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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xpower4 - 125x

Posted by All Topic Aryan 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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Find the value of (1+cos pi/8)(1+cos 3pi/8)(1+cos 5pi/8)(1+cos 7pi/8)

Posted by Mewa Singh 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}cos^4{/tex} {tex}\frac { \pi } { 8 }{/tex} {tex}+ cos^4{/tex} {tex}\frac { 3 \pi } { 8 }{/tex}{tex} + cos^4{/tex} {tex}\frac { 5 \pi } { 8 }{/tex} {tex}+ cos^4{/tex} {tex}\frac { 7 \pi } { 8 }{/tex}
{tex}= cos^4{/tex} {tex}\frac { \pi } { 8 }{/tex} {tex}+ cos^4{/tex} {tex}\frac { 3 \pi } { 8 }{/tex} {tex}+ cos^4{/tex}{tex}\left( \frac { \pi } { 2 } + \frac { \pi } { 8 } \right){/tex} {tex}+ cos^4{/tex}{tex}\left( \frac { \pi } { 2 } + \frac { 3 \pi } { 8 } \right){/tex}
{tex}= cos^4{/tex} {tex}\frac { \pi } { 8 }{/tex} {tex}+ cos^4{/tex} {tex}\frac { 3 \pi } { 8 }{/tex} {tex}+ sin^4{/tex} {tex}\frac { \pi } { 8 }{/tex} {tex}+ sin^4{/tex} {tex}\frac { 3 \pi } { 8 }{/tex} [{tex}\because{/tex} cos {tex}\left( \frac { \pi } { 2 } + \theta \right){/tex} = - sin {tex}\theta{/tex}]
= (cos⁴ {tex}\frac { \pi } { 8 }{/tex} + sin⁴ {tex}\frac { \pi } { 8 }{/tex}) + (cos⁴ {tex}\frac { 3 \pi } { 8 }{/tex} + sin⁴ {tex}\frac { 3 \pi } { 8 }{/tex})
= (cos⁴ {tex}\frac { \pi } { 8 }{/tex} + sin⁴ {tex}\frac { \pi } { 8 }{/tex} + 2 sin² {tex}\frac { \pi } { 8 }{/tex} cos² {tex}\frac { \pi } { 8 }{/tex} - 2 sin² {tex}\frac { \pi } { 8 }{/tex} cos² {tex}\frac { \pi } { 8 }{/tex}) + (cos⁴{tex}\frac { 3 \pi } { 8 }{/tex} + sin⁴ {tex}\frac { 3 \pi } { 8 }{/tex} + 2 sin²{tex}\frac { 3 \pi } { 8 }{/tex} cos² {tex}\frac { 3 \pi } { 8 }{/tex} - 2 sin²{tex}\frac { 3 \pi } { 8 }{/tex} cos²{tex}\frac { 3 \pi } { 8 }{/tex})
= (cos²{tex}\frac { \pi } { 8 }{/tex} + sin²{tex}\frac { \pi } { 8 }{/tex})²- 2 sin²{tex}\frac { \pi } { 8 }{/tex} cos²{tex}\frac { \pi } { 8 }{/tex} + (cos²{tex}\frac { 3 \pi } { 8 }{/tex} + sin²{tex}\frac { 3 \pi } { 8 }{/tex})² - 2 sin²{tex}\frac { 3 \pi } { 8 }{/tex} cos²{tex}\frac { 3 \pi } { 8 }{/tex}
[{tex}\because{/tex} {tex}a^4 + b^4 = (a^2 + b^2) - 2a^2 b^2{/tex}]
= 1 - {tex}\frac { 1 } { 2 }{/tex} (2 sin {tex}\frac { \pi } { 8 }{/tex} cos {tex}\frac { \pi } { 8 }{/tex})²+ 1 - {tex}\frac { 1 } { 2 }{/tex} (2 sin {tex}\frac { 3 \pi } { 8 }{/tex}cos {tex}\frac { 3 \pi } { 8 }{/tex})²
[{tex}\because{/tex} {tex}sin^2\theta + cos^2\theta = 1{/tex}]
= 2 - {tex}\frac { 1 } { 2 }{/tex} (sin 2 {tex}\times \frac { \pi } { 8 } ) ^ { 2 }{/tex} - {tex}\frac { 1 } { 2 }{/tex} (sin 2 {tex}\times \frac { 3 \pi } { 8 }{/tex})² [{tex}\because{/tex} sin 2x = 2 sinx cosx]
= 2 - {tex}\frac { 1 } { 2 }{/tex} sin² {tex}\frac { \pi } { 4 }{/tex} - {tex}\frac { 1 } { 2 }{/tex} sin² {tex}\frac { 3 \pi } { 4 }{/tex}
= 2 - {tex}\frac { 1 } { 2 }{/tex} {tex}\times \left( \frac { 1 } { \sqrt { 2 } } \right) ^ { 2 } - \frac { 1 } { 2 } \times \left( \frac { 1 } { \sqrt { 2 } } \right) ^ { 2 }{/tex}
[{tex}\because{/tex} sin {tex}\frac { 3 \pi } { 4 }{/tex} = sin {tex}\left( \pi - \frac { \pi } { 4 } \right){/tex} = sin {tex}\frac { \pi } { 4 }{/tex}= {tex}\frac1{\sqrt2}{/tex}]
= 2 - {tex}\frac { 1 } { 2 } \times \frac { 1 } { 2 } - \frac { 1 } { 2 } \times \frac { 1 } { 2 }{/tex}
= 2 - {tex}\frac { 1 } { 4 } - \frac { 1 } { 4 }{/tex} = 2 - {tex}\frac { 1 } { 2 } = \frac { 3 } { 2 }{/tex}

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if A intersection Bcompliment = phi then prove that A intersection B is A hence prove A is equal to or a subset of B

Posted by Md Meraj Alam 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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Are the set formula in syllabus? Of class 11th.

Posted by Devashish Kumar 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Yes, it is present in the syllabus.

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What is co domain

Posted by Devesh Sharma 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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The function of f from R to R is defined by fx=modulus of x+1 show the graph of modulus function

Posted by Veena Nagaraj 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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Show that the sum of(m+n)th and (m-n)th term of an A.P is equal to twice the (m)th term

Posted by M Kubendran 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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Ch5 ex5.3 question no.6

Posted by M Kubendran 6 years, 6 months ago

CBSE > Class 11 > Mathematics

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Sin10.sin50.sin60.sin70=√3/16 Prove it

Posted by Shivam Kumar Jha 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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Solve the inequations x+1/x+2>1

Posted by Vivek Kumar 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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{x:x is an integer,x²≤4

Posted by Krishna Gupta 6 years, 6 months ago

CBSE > Class 11 > Mathematics

2 answers

Devendra Singh 6 years, 6 months ago

A={-2,-1,0,1,2}

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Ashutosh Saini 6 years, 6 months ago

A={1,2}

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Sin power 4 x - sec square x is equal to 10 4 x + tan squared x

Posted by Nirmala Devi 6 years, 6 months ago

CBSE > Class 11 > Mathematics

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Universal sets

Posted by Neha Singh 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Ashutosh Saini 6 years, 6 months ago

The Universal set is a set which contains all elements including itself.

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Two fini two finite sets A and B have M and K its elements respectively if the ratio of Cardinal number of power set of a to the Cardinal number of power set of B is 64 ratio 1 then n(A) + n(B) equal to 12 then find the values of M and K

Posted by Preeti Kaler 6 years, 6 months ago

CBSE > Class 11 > Mathematics

0 answers

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What is the minimum value of sinA

Posted by Nh Gabru Prajapati 6 years, 6 months ago

CBSE > Class 11 > Mathematics

6 answers

Aman Shree 6 years, 6 months ago

-1

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Naman Khetawat 6 years, 6 months ago

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Nikhil Singh 6 years, 6 months ago

2Thank You

Sunny Kewat 6 years, 6 months ago

-1

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Manas Bhutada 6 years, 6 months ago

-1

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Nh Gabru Prajapati 6 years, 6 months ago

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R={(a,b)€z ,a+b =even } prove that R is in equivalence with z

Posted by Sk Dh 6 years, 6 months ago

CBSE > Class 11 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

R is reflexive , as 2 divides a-a = 0
Now (a,b){tex}\in {/tex}R implies (a-b) is divided by 2{tex}\Rightarrow{/tex} (b-a) is also divided by 2
Hence, (b,a){tex}\in {/tex}R
Hence, R is symmetric.
Now ,Let a,b,c {tex}\in{/tex}Z
If (a,b) {tex}\in {/tex}R
And (b,c) {tex}\in {/tex}R
Then a-b and b-c divided by 2

Therefore a-b is even and b-c is even

{tex}\Rightarrow{/tex}a-b +b-c is even, as sum of two even numbers is even
{tex}\Rightarrow{/tex}(a-c) is even

So a-c is divided by 2
{tex}\Rightarrow{/tex}(a,c) {tex}\in {/tex}R
Hence it is transitive.

Therefore R is reflexive,symmetric and transitive

So R is an equivalence relation

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Graphing

Posted by P S Murugan 6 years, 6 months ago

CBSE > Class 11 > Mathematics