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  • 4 answers

Anushka Singh 7 months, 1 week ago

Yes But this chapter in only in 11 like you don't need it in 12 it's not in 12 My teacher told me

Sourabh Prajapati 7 months, 1 week ago

Yes

Gaurav Singh 7 months, 2 weeks ago

I think you should learn this chapter

Gaurav Singh 7 months, 2 weeks ago

Yes
  • 2 answers

Diya Rana 7 months, 2 weeks ago

He did not explain the multielectronic species He unable to explain zeeman or stark effect Only gave the flat model of atom Ok i will clarify you that stark effect is the splitting of main line in presence of electronic field or in the case of zeeman effect there will u includ presence of magnetic field I hope it will helps u🌼☘️

Nidhi Deshwal 7 months, 3 weeks ago

•Didn't tell about splitting of electron in magnetic and electric field . •Didn't tell about arrangement of electrons in an atom.
  • 1 answers

Adithya Dev 7 months, 3 weeks ago

Wavenumber = 1/Wavelength = Frequency/Speed of light.
  • 1 answers

Adithya Dev 7 months, 3 weeks ago

In Cr (Z = 24), expected configuration is [Ar] 3d4 4s2, but due to extra stability offered by half filled orbital configuration, obtained is [Ar] 3d5 4s1.
  • 4 answers

Sariful Miah 8 months ago

What is the atomic number of carbon

Tejas T. 8 months ago

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Tejas T. 8 months ago

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Tejas T. 8 months ago

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  • 2 answers

Sherif Gupta 8 months, 1 week ago

It can be explain through an example Na==no of p+=no of e– In Na+= no of p+ > no of e–, so more attraction takes place and hence size is reduced In Na-= no of p+ < no of e–, so less attraction takes place and hence size is increased Therefore, Na+ < Na < Na-

Tejas T. 8 months, 1 week ago

It's easy
  • 2 answers

Jatt Attri 7 months, 2 weeks ago

U

Tejas T. 8 months ago

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  • 2 answers

Tejas T. 8 months ago

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Ruchi . 8 months, 1 week ago

According to orbitals overlap concept the formation of a covalent bond between two atoms result by pairing of elements present in the valence shell having opposite spins.
  • 1 answers

Gayatri Pathade 8 months ago

The process of emission of e- from the metal surface when a light of suitable frequency strikes on certain metals. This is called Photoelectriceffect.
  • 1 answers

Nidhi Deshwal 7 months, 3 weeks ago

A chemical bond is a formation of bond due to the electrostatic forces of attraction due to sharing of electrons or donating electrons. The attractive force which holds up the constituent particles (atoms, ions or molecules) together in a chemical species is known as chemical bond.
  • 2 answers

Adithya Dev 8 months ago

No,not sp3. Here hybridisation h = 1/2 (Valence e + no of monovalent atoms + no of -ve charge - no of +ve chahe) = 1/2 (7+5) = 12/2 = 6 ~~ sp3d2 hybridisation. Hope you got what you wanted.

Udit Kumar Dhruw 8 months, 2 weeks ago

1/2(3+5)=8/2=4 sp³hybridisation
  • 2 answers

Diya Rana 7 months, 2 weeks ago

According to the plank quantum theory any particle like electrons not continuosly but discontinuosly in the form of small discrete packet known as quanta or in the case of light this discrete packet remember that energy of this quantas are directly proportional the the frequency ....and plank quantum denoted by h and h= 6.626×10*34 jsec

Adithya Dev 8 months ago

1) Matter emit radiation which constitute small packets of energy called quanta (For light, photon is the quanta). 2) The total energy of the radiation emitted is an integral multiple of the individual energies of each quanta, which is expressed as hv (where, h = Planck's constant = 6.626 × 10^-34 Jsec and v = frequency)
  • 1 answers

Aman Acharya 8 months, 2 weeks ago

Mole is a unit and it's concept is called mole concept and it's simply means a avogrado no as example 1 mole means 6.023×10²³ no
  • 1 answers

Aman Acharya 8 months, 2 weeks ago

The Formula Of Average Atomic mass = Atomic Mass 1 × % Abudance + Atomic mass 2 × % abundance/ 100 10.8 = 11(x) + 10( 100-x ) / 100 1080 = 11x + 1000 -- 10x 1080 - 1000 = x x = 80 So boron having Atomic mass 11 have 80% abundance in nature and 10 has 20%
  • 1 answers

Abhrangshu Chakraborty 8 months, 3 weeks ago

22.7L (0°C, 1bar) 22.4L (0°C, 1 atm) 《From Avogadro's hypothesis》
  • 1 answers

Adithya Dev 8 months ago

Q = ±ne. ///// n = Q/e = 2.5 × 10^-16 /1.6 × 10^-19 = 25 × 10^3 / 16 = 1.5625 × 10^3 = 1563 electrons.
  • 1 answers

Adithya Dev 8 months ago

No of moles = 9.5 / 95 = 0.1 mol. No of ions = 0.1 × 6.022 × 10^23 = 6.022 × 10^22 ions. (NOW, 1 (PO4)3- HAS 15 + 32 + 3 = 50e) Therefore, no of el = 50 × 6.022 × 10^23 = 3.011 × 10^25 electrons //
  • 1 answers
BeCl2 ka Sp hybridization
  • 0 answers
  • 1 answers

Tejas T. 8 months ago

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  • 1 answers

Adithya Dev 9 months ago

When no of electrons in the valence shell is less than 4, then, these electrons have a tendency to be lost from the atom so that the atom can attain the nearest (penultimate shell) octet. When no of electrons is greater than 4, there is a tendency that the atoms gain electrons in their neighborhood to attain nearest (valence shell) octet. But, when no of valence electrons is equal to 4, gaining 4 electrons is a matter outside the control of the nucleus and losing 4 electrons causes huge energy loss to the molecule, disturbing it's thermodynamic stability. So, here electrons are just shared, and not completely transferred as in the previous cases.
  • 1 answers

Adithya Dev 9 months ago

M = Wb/Mb V(L) = 5 ×1000/40×450 = 0.27 M. //
  • 1 answers

Adithya Dev 9 months ago

n(Fe) = 69.9/56 = 1.24. n(O2) = 30.1/32 = 0.94. Therefore, n(Fe) / n(O2) = 1.3 : 1. Therefore, Empirical formula = FeO (nearly).
  • 4 answers

Anshika Gupta 9 months ago

Nitric oxide

Bhavya Garg 9 months, 1 week ago

Hello

Rishita Saw 9 months, 1 week ago

Nitric oxide

Pranshu Patel Patel 9 months, 1 week ago

Sir

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