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    • Posted by Pushpa Kumar 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Himanshu Mali 3 years, 2 months ago

    Hi

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    • Posted by Baisa Hkm ?? 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Baisa Hkm ?? 3 years, 2 months ago

    What is this

    0Thank You

    Amitesh Tiwari 3 years, 2 months ago

    Hdhdjsjvkvvieie

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    • Posted by Aman Kushwaha 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 2 months ago

    In case of big atoms like Sulphur and Potassium, the electrons in outer shells is not given a significant part of the effective nuclear charge of the atom due to the inner electrons. This is called SHIELDING EFFECT.

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    • Posted by Jissmol Jacob Varghese 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Diksha Thakur 3 years, 2 months ago

    Limitations : (1) Hydrogen with 1 electron attains stability by sharing, gaining or losing 1 valence electron. It does not need to complete octet to attain stability. Also, He has only 2 electrons and is stable. (2) Incomplete octet: In certain molecules such as BeH 2 ​ , BeCl 2 ​ , BH 3 ​ , BF 3 ​ , the central atom has less than 8 electrons in its valence shell, yet the molecule is stable. (3) Expanded octet: In certain molecules such as PF 5 ​ , SF 6 ​ , IF 7 ​ , H 2 ​ SO 4 ​ , the central atom has more than 8 valence electrons, yet the molecule is stable.

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    • Posted by Devi Devi 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Sameer Kumar Tagore 3 years, 2 months ago

    2.0×power of 10 is minus3

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    • Posted by Khushi Kundal 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Komal Bhanndari 3 years, 2 months ago

    106

    2Thank You

    Anjan Karthi 3 years, 2 months ago

    Na2CO3 = 2(23) + 12 + 3(16) = 46 + 12 + 48 = 106 amu.

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    • Posted by Darshan Jain 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Himanshu Yadav 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Krishna Baranwal 3 years, 2 months ago

    One object can't defined other object

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    • Posted by Jasmin Singh 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 2 months ago

    16 g = 4 H × 6.022 × 10^23. X g = 2.4 × 10^24. Therefore, X = 2.4 × 16 × 10^24 / 4 × 6.022 × 10^23 = 15.94 g. //

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    • Posted by Gaury Bhardwaj 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 3 answers

    Manorma Singh 3 years, 2 months ago

    Boron

    0Thank You

    Boss King 3 years, 2 months ago

    .Boron. Z M ⬇ ⬇ 5 10.118u

    0Thank You

    Komal Bhanndari 3 years, 2 months ago

    Boron

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    • Posted by 1621 H. Lalrosiami 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Ankit Gupta 3 years, 2 months ago

    Boyle law - V~1/P - (I) equation Charle's Law - V~T. -(ii) equation Avagardo law- V~n. -(iii) equation By usin1,2,3 equation: V~nT/P PV~nT PV=nRT

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    • Posted by Jatin Kumar 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Priyanshi Sharma 3 years, 2 months ago

    Volume of co2 at STP is 22.4 L Because molar mass of caco3 = 40 + 12 + 3 × 16 = 100 g. So, co2 = 12 + 2 × 16 = 44 g or 22.4 L

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    • Posted by Ujjawal Pandey 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Yanshu Kumar 3 years, 2 months ago

    No

    0Thank You

    Shabnam Singh 3 years, 2 months ago

    When multiplying two numbers, the important value is the number of significant figures. ... If the numbers being multiplied have three significant figures, then the product will have three significant figures.

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    • Posted by A Sh. 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 2 months ago

    -amine.

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    • Posted by Kavyashree G 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Kartikey Mishra 2 years, 11 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Sia ? 2 years, 11 months ago

    Amylose Amylopectin
    It is a straight-chain polymer of D-glucose units  It is a branched-chain polymer of D-glucose units
    Constitutes 20% of starch Constitutes 80% of starch
    Solubility in water is less More soluble in water
    Straight chain structure Branched structure
    Amylose stains blue with iodine Amylopectin stains reddish-brown with iodine
    Soluble in hot water without swelling Soluble in hot water with swelling
    Does not form a gel when hot water is added to it Forms a gel when hot water is added to it

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    • Posted by Anshu Singhmar 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Phiban Risha 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Phiban Risha 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Phiban Risha 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Aman Kushwaha 3 years, 2 months ago

    Suppose Out of 100g ,30g is NA Then, atomic mass = 23 Mole = 30/23 =1.3 mole (approx)

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    • Posted by Phiban Risha 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Phiban Risha 3 years, 2 months ago

    Thank you

    0Thank You

    Anjan Karthi 3 years, 2 months ago

    Molar mass of sodium = 23 g. Moles = 4.6 mol. Therefore, required mass = Molar mass × no of moles = 23 × 4.6 = 105.8 g. //

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    • Posted by Atharv Tamboli 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 3 months ago

    Molar mass of NH3 = 14 + 3(1) = 17 g. // Therefore, percentage composition of N in NH3 = (molar mass of N / Molar mass of NH3) × 100 = 1400/17 = 82.35%.//

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    • Posted by Alok Singh 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 3 answers

    Krishna Baranwal 3 years, 2 months ago

    Co2=12+2(16)=44u and ch4 =12+4(1)=16u and H2O=2(1)+16=18

    0Thank You

    Anjan Karthi 3 years, 3 months ago

    2) CO2 = 12 + 2(16) = 44 g. // 3) CH4 = 12 + 4(1) = 16 g. //

    0Thank You

    Narender Singh 3 years, 3 months ago

    1 . h ( 2 ) + O 2 + 16 = 18 amu

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    • Posted by Harsh Patel 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Avani Singh 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Komal Sharma 3 years, 3 months ago

    1

    0Thank You

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    • Posted by Avani Singh 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Avani Singh 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 0 answers
    ANSWER

    • Posted by Avani Singh 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 3 months ago

    n (Cu) = 80 / 63 = 1.26// n (S) = 20 / 32 = 0.625// Ratio = 1.26 : 0.625 = 2:1 (approx.) Therefore, empirical formula of compound is Cu2S.

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    • Posted by Jissmol Jacob Varghese 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 3 answers

    Anjan Karthi 3 years, 3 months ago

    Metal metal bond is called a CRYSTAL LATTICE bond.

    1Thank You

    Aadhisesan Venkatesh 3 years, 3 months ago

    But I don't know about metal to metal bond sorry

    1Thank You

    Aadhisesan Venkatesh 3 years, 3 months ago

    Metal to non metal = ionic bond Non metal to non metal = covalent bond

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    • Posted by Aaliya Hussainar 3 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 3 months ago

    No of moles (C) = 40/12 = 3.33 . No of moles (H) = 6.7/1 = 6.7 . No of moles (O) = 53.3/16 = 3.33. Therefore, Ratio = C:H:O = 1:2:1. Empirical formula = CH2O. Mass of Empirical formula = 12 + 2 + 16 = 30 g. // N = 175/30 = 6 (approx). Therefore, molecular formula is C6H12O6.

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