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  • 1 answers

Sia ? 3 years, 9 months ago

Amylose Amylopectin
It is a straight-chain polymer of D-glucose units  It is a branched-chain polymer of D-glucose units
Constitutes 20% of starch Constitutes 80% of starch
Solubility in water is less More soluble in water
Straight chain structure Branched structure
Amylose stains blue with iodine Amylopectin stains reddish-brown with iodine
Soluble in hot water without swelling Soluble in hot water with swelling
Does not form a gel when hot water is added to it Forms a gel when hot water is added to it
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Aman Kushwaha 4 years ago

Suppose Out of 100g ,30g is NA Then, atomic mass = 23 Mole = 30/23 =1.3 mole (approx)
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Phiban Risha 4 years ago

Thank you

Anjan Karthi 4 years ago

Molar mass of sodium = 23 g. Moles = 4.6 mol. Therefore, required mass = Molar mass × no of moles = 23 × 4.6 = 105.8 g. //
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Anjan Karthi 4 years ago

Molar mass of NH3 = 14 + 3(1) = 17 g. // Therefore, percentage composition of N in NH3 = (molar mass of N / Molar mass of NH3) × 100 = 1400/17 = 82.35%.//
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Co2=12+2(16)=44u and ch4 =12+4(1)=16u and H2O=2(1)+16=18

Anjan Karthi 4 years ago

2) CO2 = 12 + 2(16) = 44 g. // 3) CH4 = 12 + 4(1) = 16 g. //

Narender Singh 4 years ago

1 . h ( 2 ) + O 2 + 16 = 18 amu
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Anjan Karthi 4 years ago

n (Cu) = 80 / 63 = 1.26// n (S) = 20 / 32 = 0.625// Ratio = 1.26 : 0.625 = 2:1 (approx.) Therefore, empirical formula of compound is Cu2S.
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Anjan Karthi 4 years ago

Metal metal bond is called a CRYSTAL LATTICE bond.
But I don't know about metal to metal bond sorry
Metal to non metal = ionic bond Non metal to non metal = covalent bond
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Anjan Karthi 4 years ago

No of moles (C) = 40/12 = 3.33 . No of moles (H) = 6.7/1 = 6.7 . No of moles (O) = 53.3/16 = 3.33. Therefore, Ratio = C:H:O = 1:2:1. Empirical formula = CH2O. Mass of Empirical formula = 12 + 2 + 16 = 30 g. // N = 175/30 = 6 (approx). Therefore, molecular formula is C6H12O6.
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Anjan Karthi 4 years ago

Though both fluorine and chlorine have same number of valence electrons, due to smaller valence orbital size of fluorine, the electron density in valence orbital is greater in fluorine than in chlorine. So, more effort would be required to insert a new electron in fluorine than in chlorine. So, chlorine has more negative electron gain enthalpy than in fluorine.
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1 mole CH4 weighs 16g according to reaction 1mole of methane is required to produce 1 mole CO2 hence amount of CO2 produced is 12+32=44g
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Anjan Karthi 4 years ago

Wavelength = 6000 Å = 6 × 10^-7 m. V = 3 × 10^8 m/s. Therefore, frequency = v/wavelength = 3 × 10^8 / 6 × 10^-7 = 0.5 × 10^15 Hz. // Energy = hv/wavelength = 6.626 × 10^-34 × 0.5 × 10^15 = 3.313 × 10^-19 J. //
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Anjan Karthi 4 years, 1 month ago

Molar mass of C12H22O11 = 342 g. Given mass = 3.42 g. No. of atoms of C = 12 × 6.022 × 10^23 × 3.42/342 = 12 × 6.022 × 10^23 × 10^-2 = 72.264 × 10^21 atoms. // Similarly, find H and O atoms also.
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Sia ? 4 years, 1 month ago

(a) s-block elements:

All of the s-block elements are unified by the fact that their valence electrons (outermost electrons) are in an s orbital. The s orbital is spherical and can be occupied by a maximum of two electrons. All of the s-block elements are metals. In general, they are shiny, silvery, good conductors of heat and electricity and lose their valence electrons easily. In fact, they lose their trademark s orbital valence electrons so easily that the s-block elements are the most reactive elements.

(b) p- block elements:

Following are the properties of p-block elements.

  • They are solids/liquids/gases at room temperature (Br is liquid) 
  • They have variable oxidation states 
  • They form acidic oxides 
  • Generally, they form covalent compounds 
  • Halogens form salts with alkali metals 
  • They have high ionization potentials 
  • They have very large electron gain enthalpies 
  • The aqueous solutions their oxides are acidic in nature.

(c) d-block elements:

  • Form stable complexes
  • Have high melting and boiling points
  • Contain large charge/radius ratio
  • Form compounds which are often paramagnetic
  • Are hard and possess high densities
  • Form compounds with profound catalytic activity
  • Show variable oxidation states
  • Form coloured ions and compounds.

(d) f-block elements:

  • They are usually heavy metals
  • These elements have a generally higher melting and boiling point
  • They display a variety of oxidisation states
  • These elements tend to form coloured ions
  • They form complex compounds
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Priyanka Khatri 4 years, 1 month ago

Kay aap muja chemistry ka chapter 2 nd ka notes send kar da ga plz

Anjan Karthi 4 years, 1 month ago

MOLARITY = 0.15 M. Volume = 100 cubic cm = 0.1 L. Therefore, number of moles of NaOH = M × V = 0.15 × 0.1 = 0.015 moles. // Amount of NaOH = number of moles × Molar mass = 0.015 × 40 = 0.15 × 4 = 0.60 g. //

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