CBSE > Class 11 > Chemistry | CBSE Board | Homework Help

Ask questions which are clear, concise and easy to understand.

Ask Question

Explain isomerism.

Posted by Revanshi Grewal 3 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Ankit ............ 3 years, 1 month ago

Phenomenon in which more than one compound have same chemical formula but different chemical structure is different

0Thank You

ANSWER

All masses of atom

Posted by Sid Gohiya 3 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Bhuvanesh Saraswat Pandit 3 years, 1 month ago

Same

1Thank You

ANSWER

Need of atom

Posted by Sid Gohiya 3 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Anjan Karthi 3 years, 1 month ago

Every atom combines with other atoms to lower it's inbuilt ionisation energy and thereby, attain stability. This is the BASIC need for all atoms (Noble gases from Kr)

1Thank You

G J 3 years, 1 month ago

Need of atom

1Thank You

ANSWER

Which is the basic theme of organisations in the periodic table

Posted by Fiddusur Rahman 3 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Harshit Meena 3 years, 1 month ago

Atomic number

0Thank You

Anjan Karthi 3 years, 1 month ago

1) Similar physical and Chemical properties of elements down the group. 2) Increasing order for atomic number by 1 unit across every period. 3) Similarity in electronic configuration of atoms down a group.

0Thank You

ANSWER

Change of protons Charge of neutrons Charge of electrons

Posted by Akash Malsa 3 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Anjan Karthi 3 years, 1 month ago

Charge of protons = + 1.6 × 10 ^-19 C. Charge of electron = - 1.6 × 10^ -19 C. Charge of neutron = 0

0Thank You

Akash Malsa 3 years, 1 month ago

Fast

1Thank You

ANSWER

Which of the following hydrides are generally nonstochiometric in nature?

Posted by Ajitesh Kanojia 3 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Umang Gupta 3 years, 1 month ago

Saline hydrides

0Thank You

ANSWER

How every elements of 1 mol(6.022×10^23 particles) have same volume,irrespective of their different masses?

Posted by Ritiya Kumari 3 years, 1 month ago

CBSE > Class 11 > Chemistry

0 answers

ANSWER

How to define electronic configuration

Posted by Uday Kumar Giri 3 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Saurabh Kumar 3 years, 1 month ago

The electron configuration is the distribution of electron of an atom or molecule in atomic or molecular orbitals.

1Thank You

Jèôñ Āmbìkā 3 years, 1 month ago

The arrangement of electrons in energy levels around an atomic nucleus...is defined as electronic configuration...

4Thank You

ANSWER

Find the orbital or electron for the given quantum number:- 1.n=2 , l=0 2.n=3 , l=2 , m=0 , s=1/2 3.n=4 , l=0 , m=0 , s=-1/2 4.n=6 , l=3 , m=-3 , s=-1/2

Posted by Paro ... 3 years, 2 months ago

CBSE > Class 11 > Chemistry

2 answers

Ashok Kumar 3 years, 1 month ago

1.2s 2. 3d³ 3.4s² 4.6f^8 I hope it helps u...

2Thank You

Sanchita Meena 3 years, 2 months ago

2Thank You

ANSWER

Name the alkines

Posted by Kisan Salunke 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Ankit ............ 3 years, 1 month ago

NaOH, KOH

0Thank You

ANSWER

Find the conjugate of the complex numbers (i) -i√5

Posted by Anubhuti Chhetri 3 years, 2 months ago

CBSE > Class 11 > Chemistry

3 answers

Ashok Kumar 3 years, 1 month ago

i√5 ok.na

0Thank You

Anurag Singh 3 years, 1 month ago

change of iorta sign

1Thank You

Hemang Dubey 3 years, 2 months ago

Root 5 plus iorta

2Thank You

ANSWER

Calculate all the four quantum no. Of last electron of Cr

Posted by Anjali Vasistha 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

Cr = 1s2 2s2 2p6 3s2 3p6 3d5 4s1. Therefore, last electron is in 3d orbital. Quantum numbers are :- n = 3. l = 2. ml = 2. ms = 1/2.

1Thank You

ANSWER

How to learn chemistry?? Especially GOC..

Posted by Mukul Kumar 3 years, 2 months ago

CBSE > Class 11 > Chemistry

3 answers

Sameer Kumar Tagore 3 years, 2 months ago

First you go through concept of organic chemistry in NCERT Book. Then make question by itself and answer if fell confident ,then make exercise question and internal question also ,finally you fell something I know about what actually organic chemistry after that you go on goc side book.

1Thank You

Hemang Dubey 3 years, 2 months ago

Also be confident

1Thank You

Harsh Singh 3 years, 2 months ago

By revising again and again and by doing lots of question practice

1Thank You

ANSWER

How many Sigma and Pi bonds are present in Pentene

Posted by Hemang Dubey 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

Pentene structure is CH2=CHCH2CH2CH3. Therefore, number of σ bonds = 8. And total number of π bonds = 1.

2Thank You

ANSWER

The length of h bonding in solid state of water is

Posted by Hemang Dubey 3 years, 2 months ago

CBSE > Class 11 > Chemistry

0 answers

ANSWER

FeCl3 + H2 S  FeCl2 + 5 + HCl

Posted by Hemang Dubey 3 years, 2 months ago

CBSE > Class 11 > Chemistry

0 answers

ANSWER

unit of length.

Posted by Abhash Tiwari 3 years, 2 months ago

CBSE > Class 11 > Chemistry

4 answers

Mukul Kumar 3 years, 2 months ago

Here you have three units. 1st is meter. 2nd is foot. 3rd is centimetres.

1Thank You

Kiran Sambharwal 3 years, 2 months ago

Meter

1Thank You

Dhruvi Chauhan 3 years, 2 months ago

Meter

0Thank You

Abhash Tiwari 3 years, 2 months ago

metere

1Thank You

ANSWER

The first ionization enthalpy of O is less than N. Why ?

Posted by Shivani Kumari 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

Electronic configuration of O = 1s2 2s2 2p4 and that for N = 1s2 2s2 2p5. Here, in N, the 2p subshell already has a HALF FILLED electronic arrangement unlike in O. This ensures greater stability for N atom than for O atom and thus, ionisation enthalpy (energy required to remove outermost electron) for O becomes lesser in magnitude than that for N.

0Thank You

ANSWER

The first ionization enthalpy of B is less than first ionization enthalpy of Be . Why?

Posted by Shivani Kumari 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

Be has an Electronic configuration of 1s2 2s2 and B has an electronic configuration of 1s2 2s2 2p1. The p 2p orbital, causing lesser shielding effect than 2s orbital, would be able to loose an electron much more easily than 2s orbital. Hence, Be has greater ionization enthalpy than B.

0Thank You

ANSWER

Types of chemical reaction in chapter 12

Posted by Dharni Rathor 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Shravani Tambe 3 years, 2 months ago

0Thank You

ANSWER

SIMILARITIES AND DISIMILARITIES BETWEEN HYDROGEN,HALOGEN AND ALKALI METALS

Posted by Apurva J Patil 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Prabhjot Kaur 3 years, 2 months ago

Similarities between hydrogen and alkali metals : Electronic configuration Electropositive character Valency and oxidation state Reducing agents Dissimilarities between alkali metals: Ionisation enthlapy Non metallic in nature Atomicity Similarities between hydrogen and halogen Electronic configuration Ionisation enthlapy Electronegative character Oxidation state Diatomic nature Nature of compounds Dissimilarities between hydrogen and halogen Less tendency for hydride formation Absence of unshared pair of electron Oxides of halogens are acidic

0Thank You

ANSWER

For hydrogen atom the energy is expressed as En=-13.6/n ev/atom. The value of 2nd Ionisation energy of helium atom will be

Posted by Kiran Mandal 3 years, 2 months ago

CBSE > Class 11 > Chemistry

0 answers

ANSWER

Calculate the volume of 0.015M HCL solution required to prepare 250ml of a 5.25×1/1000M HCL solution

Posted by Pinki Borah 3 years, 2 months ago

CBSE > Class 11 > Chemistry

2 answers

Kaushik Ka 3 years, 2 months ago

M1*V1 = M2*V2 (0.015×250)÷(5.25÷1,000) = V2 V2 = 714.285 ml

0Thank You

Kaushik Ka 3 years, 2 months ago

M1*V1 = M2*V2

0Thank You

ANSWER

Calculate the number of molecules in 20 g aluminum sulphate

Posted by Baazigha Sultana Siddiqui 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

Molar mass of Al2(SO4) 3 = 2(27) + (32 + 64) 3 = 54 + 288 = 342 g. // No of molecules = (20/342) × 6.02 × 10^23 = 0.352 × 10^23 molecules//

0Thank You

ANSWER

How many moles of methane required to produce 88g of CO2 after combustion

Posted by Akash Malsa 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Anjan Karthi 3 years, 2 months ago

According to balanced equation, CH4 + 2O2 → CO2 + 2H2O. No of moles of CO2 produced = W2/M2 = 88/44 = 2 mol// Therefore, no. of moles of Methane required = 2 mol. //

1Thank You

ANSWER

Electronic configuration of florine

Posted by Kanak Sahu 3 years, 2 months ago

CBSE > Class 11 > Chemistry

3 answers

Khushi Rani 3 years, 2 months ago

1s*2 2s*2p*5

0Thank You

Jatin Jatin 3 years, 2 months ago

2Thank You

Jatin Jatin 3 years, 2 months ago

1s² 2s² 2p⁵

3Thank You

ANSWER

Which out of the following contain least number of atoms? A. 1gm of H2O B. 1gm of CH4 C. 1gm of N2

Posted by Anoubam Victor 3 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Ningmi Chon 3 years, 2 months ago

1×4×6•023×1023

1Thank You

ANSWER

Which out of the following contain least number of atoms?

Posted by Anoubam Victor 3 years, 2 months ago

CBSE > Class 11 > Chemistry

0 answers

ANSWER

Calculate the percent ionic character of HCl. Given that the observed dipole moment is 1.03D and length of HCl is 1.275 Å.

Posted by Priyanka Khatri 3 years, 2 months ago

CBSE > Class 11 > Chemistry

2 answers

Priyanka Khatri 3 years, 2 months ago

Thanks

0Thank You

Roopam Almadi 3 years, 2 months ago

Fraction of charge = 1.03 × 10^-18 esu. cm / 4.8 × 10 ^-10 esu × 1.275 × 10 ^-8 cm Fraction of charge = 0.1683 % Ionic character = Fraction of charge × 100 So% ionic character = 16.83 % So % covalent character = 100 - 16.83 = 83.17 % ....

1Thank You

ANSWER

If 2.36grm of sodium sulphate is added to berium chloride the residue is formed to be 3.88grm of barium sulphate and 1.98grm of sodium chloride.What is the mass of barium chloride?

Posted by Deiba Pariong 3 years, 2 months ago

CBSE > Class 11 > Chemistry