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Sia ? 3 years, 10 months ago

The salt of carbonic acids are called carbonates and are characterized by the carbonate ion, CO32-. The carbonate ion is the simplest oxocarbon anion, consisting of one carbon atom surrounded by three oxygen atoms in a trigonal planar arrangement.

  • 3 answers

Harsh Madhesiya 3 years, 9 months ago

Question- (C)O2 - We have to find the oxidation no. Of (C) ???????? Answer- let the oxidation no. Of (C) be(x). Now, X + 2(-2) =0 X-4=0 (X=+4)Ans. So, the oxidation no. Of (C) is (+4).

Mannu Dahiya 3 years, 10 months ago

First u hace to leran or read the rules given in book

Suhana Naaz 3 years, 10 months ago

Please send answer later
  • 1 answers

Anjan Karthi 3 years, 11 months ago

12 g of carbon would contain 6.022 × 10^23 atoms. Therefore, no of carbon-12 atoms in 12 g of carbon = 98/100 × 6.022 × 10^23 = 590.156 × 10^21.//
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Sia ? 3 years, 11 months ago

The Bohr's energy of a stationary state of the hydrogen atom is given as En​=n2h2−2πme4​.

Dikshant Sharma 3 years, 11 months ago

-2π^4me^4/n^2h^2
  • 2 answers

Sia ? 3 years, 11 months ago

The Bohr's energy of a stationary state of the hydrogen atom is given as En​=n2h2−2πme4​.

Dikshant Sharma 3 years, 11 months ago

-2π^2me^4/n^2h^2
  • 1 answers

Sia ? 3 years, 11 months ago

Calculations:
Mass% of an element in a compound is calculated using the relation,
{tex}\frac{\text { Mass of that element in the compound }}{\text { Molar mass of the compound }} \times{/tex}100 
Now the molar mass of
Na2SO4 = 2(23.0) + 32.0 + 4 {tex}\times{/tex} 16.0
= 142 g mol-1
So, Mass per cent of sodium
{tex}\frac{46}{142} \times{/tex}100
= 32.39%
Similarly,
Mass per cent of sulphur
{tex}\frac{32}{142} \times{/tex}100
= 22.54%
Mass per cent of oxygen
{tex}\frac{64}{142} \times{/tex}100
= 45.07%

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Anjan Karthi 3 years, 11 months ago

Mass of solution W = 250 g. Density of solution D = 1.5 g/mol. Therefore, volume of solution = W / D = 250 / 1.5 = 166.6 cm^3. Hence, W / V% = 40 × 100 / 166.67 = 23.99 %. //

Yaswanth Varma 3 years, 11 months ago

Jjj
  • 2 answers

Utkarsh Anand 3 years, 11 months ago

Hay

Gunasekaran Duraisamy 3 years, 11 months ago

No2
  • 1 answers

Anjan Karthi 3 years, 11 months ago

1) Protium (H with A = 1 and Z = 1.) 2) Deuterium (H with A = 2 and Z = 1.) 3) Tritium ( H with A = 3 and Z = 1)
  • 1 answers

Ankit ............ 3 years, 11 months ago

Phenomenon in which more than one compound have same chemical formula but different chemical structure is different
  • 1 answers

Bhuvanesh Saraswat Pandit 3 years, 11 months ago

Same
  • 2 answers

Anjan Karthi 3 years, 11 months ago

Every atom combines with other atoms to lower it's inbuilt ionisation energy and thereby, attain stability. This is the BASIC need for all atoms (Noble gases from Kr)

G J 3 years, 11 months ago

Need of atom
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Harshit Meena 3 years, 11 months ago

Atomic number

Anjan Karthi 3 years, 11 months ago

1) Similar physical and Chemical properties of elements down the group. 2) Increasing order for atomic number by 1 unit across every period. 3) Similarity in electronic configuration of atoms down a group.
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Anjan Karthi 3 years, 11 months ago

Charge of protons = + 1.6 × 10 ^-19 C. Charge of electron = - 1.6 × 10^ -19 C. Charge of neutron = 0

Akash Malsa 3 years, 11 months ago

Fast
  • 1 answers

Umang Gupta 3 years, 11 months ago

Saline hydrides
  • 2 answers

Saurabh Kumar 3 years, 11 months ago

The electron configuration is the distribution of electron of an atom or molecule in atomic or molecular orbitals.

Jèôñ Āmbìkā 3 years, 11 months ago

The arrangement of electrons in energy levels around an atomic nucleus...is defined as electronic configuration...
  • 1 answers

Ankit ............ 3 years, 11 months ago

NaOH, KOH
  • 3 answers

Ashok Kumar 3 years, 10 months ago

i√5 ok.na

Anurag Singh 3 years, 11 months ago

change of iorta sign

Hemang Dubey 3 years, 11 months ago

Root 5 plus iorta
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Anjan Karthi 3 years, 11 months ago

Cr = 1s2 2s2 2p6 3s2 3p6 3d5 4s1. Therefore, last electron is in 3d orbital. Quantum numbers are :- n = 3. l = 2. ml = 2. ms = 1/2.
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Sameer Kumar Tagore 3 years, 11 months ago

First you go through concept of organic chemistry in NCERT Book. Then make question by itself and answer if fell confident ,then make exercise question and internal question also ,finally you fell something I know about what actually organic chemistry after that you go on goc side book.

Hemang Dubey 3 years, 11 months ago

Also be confident

Harsh Singh 3 years, 11 months ago

By revising again and again and by doing lots of question practice

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