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Ask QuestionPosted by Vansh Mann 7 years, 3 months ago
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Posted by Nikitha Ch 7 years, 3 months ago
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Posted by Sathish G 7 years, 3 months ago
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Kajal Kumari 7 years, 3 months ago
1st 5 even no. =0, 2,4,6,8
L.C.M. of these no. = 24
So the least no. that is divisible by 1st 5 even no. = 24
Posted by Amrita Choudhary 7 years, 3 months ago
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Deva Priya 7 years, 3 months ago
Posted by Anand Kashyap 7 years, 3 months ago
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Posted by Bhushan Nikhade 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
{tex}{S_1} = \frac{n}{2}\left[ {2a + (n - 1)d} \right]{/tex}
{tex}{S_2} = \frac{{2n}}{2}\left[ {2a + (2n - 1)d} \right]{/tex}
{tex}{S_3} = \frac{{3n}}{2}\left[ {2a + (3n - 1)d} \right]{/tex}
R.H.S = 3(S2 - S1)
{tex} = 3\left[ {\frac{{2n}}{2}(2a + (2n - 1)d - \frac{n}{2}(2a + (n - 1)d)} \right]{/tex}
{tex} = 3\left[ {\frac{n}{2}\left[ {4a + 4nd - 2d - 2a - nd + d} \right]} \right]{/tex}
{tex} = 3\left[ {\frac{n}{2}(2a + 3nd - d)} \right]{/tex}
{tex} = \frac{{3n}}{2}\left[ {2a + (3n - 1)d} \right] = {S_3}{/tex}
Posted by Rohan Yadav 7 years, 3 months ago
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Taiyab Hussain. 7 years, 3 months ago
Sham Kargwal Kargwal 7 years, 3 months ago
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Taiyab Hussain. 7 years, 3 months ago
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Sumit Sharma 7 years, 3 months ago
1Thank You