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    • Posted by Aatif K 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yathath Yadav 7 years, 3 months ago

    Hey I think all but if you have to score the marks then firstly do all easy chapters first and then start with trigonometry as it comes of 12 marks and then mensuration part it's my advice best of luck

    7Thank You

    ANSWER

    • Posted by Sumit Raj 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Sneha Misra 7 years, 3 months ago

    ★Tan30° => 1/√3★ Hope this will help u my frnd!!!??

    2Thank You

    Shruti Tripathi 7 years, 3 months ago

    1/✓3

    2Thank You

    Harish Nagar 7 years, 3 months ago

    1/underroot 3

    3Thank You

    ANSWER

    • Posted by Goldy Singh 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Shruti Tripathi 7 years, 3 months ago

    Ans.9/8 only ans. All solution right

    0Thank You

    Shruti Tripathi 7 years, 3 months ago

    Solution 3tan(90°-65°).tan(90°-50°).1/cot50°.1/cot65°.1/2.tan square60° /4(cos square (90°-61°)+cos square 61°) 3×1/2×✓3 square /4(sin square 61°+cos square 61°) 3/2×3 /4(1) 9/2 /4 9/2×4 18 ans.

    0Thank You

    ANSWER

    • Posted by Akshaya G 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Aachal Singh 7 years, 3 months ago

    Speed of boat = 10m/s speed of stream = 4m/s

    3Thank You

    ANSWER

    • Posted by Richa Kumari 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Goldy Singh 7 years, 3 months ago

    By consistence practice

    1Thank You

    Ananya Raje 7 years, 3 months ago

    By studying properly and following a regular time table, in which you have to give a specific timeline for all subjects and follow them regularly. And do not refer to any guide or help book ? just refer your textbooks.

    2Thank You

    Swati Khatri 7 years, 3 months ago

    By Hardwork

    2Thank You

    Rakesh Kumar Tiwari 7 years, 3 months ago

    by answring correctly

    2Thank You

    Sara Likitha 7 years, 3 months ago

    By referring the textbook

    1Thank You

    ANSWER

    • Posted by Shalu Gupta 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Rakesh Kumar Tiwari 7 years, 3 months ago

    AC² = AB² + BC² ,,,,,,, =›AC²=(AC-2)²+64,,,,,,, =›AC²=AC²+4-4AC+64,,,,,,, =›AC= 17

    0Thank You

    Shivang Singh 7 years, 3 months ago

    first of all let ac be x and AB be 2-x and solve by pythagoreans theorem

    1Thank You

    Cbse Client 7 years, 3 months ago

    Put bpt theorem and put the values

    0Thank You

    Anurag Maurya 5 years, 8 months ago

    Oo bahan copy le aa

    2Thank You

    ANSWER

    • Posted by Animesh Kumar 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Swati Khatri 7 years, 3 months ago

    Let root 3 is a rational no. Therefore root 3 = P/q (where q# 0) Squaring both side 3 =p^2/ q^2 3q^2 = p^2 Because p^2 divided by 3 Therefore P also divided by 3 Now, P = 3m Squaring both side (p)^2 = (3m)^2 3q^2 = 9m^2 q^2 =9/3 =3 q^2= 3m^2 Because q^2 divided by 3 Therefore q also divided by 3 Therefore p and q have at least 3 as a common factor. So our assumption root 3 is a rational no. is incorrect.

    1Thank You

    Krishna Priya Vijayan 7 years, 3 months ago

    We have assume √3 is rational Therefore √3 =p/q and p and q are co primes p not equal to 0 Therefore p = √3q Squaring on both sides p^2 = 3q^2 Theorem : let p be a prime number ,it divides a^2 than p divides a, where a is a positive integer 3 divides q ^2 . 3 divides q Let p = 3x (3x)^2 =3q ^2 9x^2 = 3 q ^2 3x^2 = q ^2 Theorem : let p be a prime number ,it p divides a^2 than p divides a where a is a positive integer 3 divides q^2 3 divides q That mean p and q has 2 common factor Which is a contradicts the fact a and b Therefore √3 is irrational

    0Thank You

    Gur Maan 7 years, 3 months ago

    Root 3 is a rational number Where a and b are positive integer and has on common number (Root 3) =a÷b 3a=b 3 divodes a Put a= 3m in eq 1 3.b2 =9m b2= 3m 3divides b So root3 has common number Which is contradication So root3 is an irrational number

    1Thank You

    ANSWER
    K

    • Posted by Abhishek Kumar 5 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Paarth Pathak 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Harish Nagar 7 years, 3 months ago

    it is possible but practise and practies

    0Thank You

    Sara Likitha 7 years, 3 months ago

    First u stop thinking that math is hard and do sums with peace of mind and keep self confidence in u and all the best

    0Thank You

    Swati Khatri 7 years, 3 months ago

    ??? Impossible yarr

    1Thank You

    Sanjivani Gawade 7 years, 3 months ago

    Are u crazy?????? It is not possible to clear maths in just 1 night

    0Thank You

    Mohsin Mulla 7 years, 3 months ago

    Study only

    1Thank You

    ANSWER

    • Posted by Ammu Ammu 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Ammu Ammu 7 years, 3 months ago

    No!

    1Thank You

    Meghanath R 7 years, 3 months ago

    If I am not wrong a shopkeeper who sold 45 lemons is an American who sold india where as sold lemons of 24 is an indian who in america

    1Thank You

    ANSWER

    • Posted by Mohit Kashyap 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Harsh Naik 7 years, 3 months ago

    And theorem 6.5 is most most imp.....

    1Thank You

    Mohsin Mulla 7 years, 3 months ago

    Pythagoras and BPT and converse of both

    1Thank You

    Vaibhav Parmar 7 years, 3 months ago

    Pythagoras theorem

    1Thank You

    Tapanjeet Kaur Saini 7 years, 3 months ago

    Pythogrous theorm and BPT both are very important.

    2Thank You

    Ravi Rawat 7 years, 3 months ago

    Basic proposnality theoram

    5Thank You

    ANSWER

    • Posted by Mohit Nandan 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Dabas Jaat 7 years, 3 months ago

    bruh! recheck your question

    1Thank You

    Dabas Jaat 7 years, 3 months ago

    what haha

    1Thank You

    Simranjit Singh 7 years, 3 months ago

    Haha

    4Thank You

    ANSWER

    • Posted by Nazia Khan 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    Let {tex} \alpha{/tex} and {tex} \frac { 1 } { \alpha }{/tex} be the zeros of (a2 + 9)x2 + 13x + 6a.
    Then, we have
    {tex} \alpha \times \frac { 1 } { \alpha } = \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
    ⇒ 1 = {tex} \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
    ⇒ a2 + 9 = 6a
    ⇒ a2 - 6a + 9 = 0
    ⇒ a2 - 3a - 3a + 9 = 0
    ⇒ a(a - 3)  - 3(a - 3) = 0
    ⇒ (a - 3) (a - 3) = 0
    ⇒ (a - 3)2 = 0
    ⇒ a - 3 = 0
    ⇒ a = 3
    So, the value of a in given polynomial is 3.

    0Thank You

    ANSWER

    • Posted by Dev Batra 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Heramb Chaudhari 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Ruchi Arya 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Mohit Kashyap 7 years, 3 months ago

    40km

    0Thank You

    Naira Singhania 7 years, 3 months ago

    40 KM

    0Thank You

    Dabas Jaat 7 years, 3 months ago

    40 KM

    0Thank You

    Ankit Raj 7 years, 3 months ago

    40

    0Thank You

    Badiur Rahman 7 years, 3 months ago

    40

    0Thank You

    ANSWER

    • Posted by Aman Singh 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Sheenu Yadav 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Fjdigih Gjgkhk 7 years, 3 months ago

    xy

    0Thank You

    Harleen Kaur 7 years, 3 months ago

    It will just be xy.

    0Thank You

    Sheenu Yadav 7 years, 3 months ago

    Not solve able

    4Thank You

    ANSWER

    • Posted by Akash Choudhary 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Swati Khatri 7 years, 3 months ago

    Ncert

    0Thank You

    Vinit Kumar 7 years, 3 months ago

    Ncert

    2Thank You

    Swapna Biswas 7 years, 3 months ago

    Oswal

    0Thank You

    Aman Bhatt 7 years, 3 months ago

    S chand nahi sahi kya

    0Thank You

    Harleen Kaur 7 years, 3 months ago

    Xam idea

    0Thank You

    ANSWER

    • Posted by Hrishikesh Drave 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Kush Malhotra 7 years, 3 months ago

    Dont follow time table bcz it wastage of time nthelse but u can follow a scheduled

    2Thank You

    ANSWER

    • Posted by Yathath Yadav 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    p(x) = 5x2 + 8x - 4 = 0
    = 5x2 + 10x - 2x - 4 = 0
    = 5x(x + 2) - 2(x + 2) = 0
    = (x + 2)(5x - 2) = 0
    Hence, zeroes are -2 and {tex}\frac 25{/tex}
    Verification:
    Sum of zeroes = {tex}- 2 + \frac { 2 } { 5 } = \frac { - 8 } { 5 }{/tex}
    Product of zeroes = {tex}( - 2 ) \times \left( \frac { 2 } { 5 } \right) = \frac { - 4 } { 5 }{/tex}
    Again sum of zeroes = {tex}- \frac { \text { Coeff. of } x } { \text { Coeff. of } x ^ { 2 } } = \frac { - 8 } { 5 }{/tex}
    Product of zeroes = {tex}\frac { \text { Constant term } } { \text { Coeff. of } x ^ { 2 } }{/tex} = {tex}\frac{-4}{5}{/tex}
    Verified.

    0Thank You

    ANSWER

    • Posted by Vivek Sankpal 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Kanika Verma 5 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Bharath.G Bharath.G 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Benudhar Mohanty 7 years, 3 months ago

    First we have to put the value of area of triangle 1/2[ x1 ( y2 -y3) + x2( y3 - y1) +x3 (y1 - y2) ] So, now we have put the values =1/2[8(-4+5)+k(-5-1) +2(1+4)] =1/2(8-6k+10) =1/2(18-6k) =1/2*2(9-3k) => -3k = -9 => k =3 Hence the value of k is 3

    1Thank You

    ANSWER

    • Posted by Tushar Tomer 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 7 answers

    Kuljeet Singh Solanki 7 years, 3 months ago

    Volue of sin60= √3/2

    0Thank You

    Nishant Pal 7 years, 3 months ago

    √3/2

    1Thank You

    Vivek Sankpal 7 years, 3 months ago

    See in textbook all values are given

    1Thank You

    Mitali Sabale 7 years, 3 months ago

    √3/2

    2Thank You

    Ankur Y 7 years, 3 months ago

    √3/2

    3Thank You

    Aman Singhal 7 years, 3 months ago

    √3/2

    5Thank You

    Riya Pal 7 years, 3 months ago

    √3\2

    3Thank You

    ANSWER

    • Posted by Ashish Kumar 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Vivek Sankpal 7 years, 3 months ago

    Mode maximum class frequency is 20 modal class is 125-145 Mode=l+(f1+f2/2f-f0-f2)h By solving it we get Mode = 135.77 units

    2Thank You

    Vivek Sankpal 7 years, 3 months ago

    Median = First find cumulative frequency(cf) i.e 4,9,22,42,56,64,68 Now n=68 n/2=68/2=34 Cf greater than 34 is 42 Median class is 125-145 Now l=125,cf=22,f=20,h=20 Median =l+<(n/2-cf /f) h =125(34-22/20)20 =125+12 Median =137 units

    2Thank You

    ANSWER

    • Posted by Sagar Kumar 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sagar Kumar 7 years, 2 months ago

    Bdtrnfjyi

    0Thank You

    ANSWER

    • Posted by Harshita Kumari 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 6 answers

    Vivek Sankpal 7 years, 3 months ago

    Sorry for first answer It's addition of all three sides

    0Thank You

    Vivek Sankpal 7 years, 3 months ago

    3a were "a" is sides

    0Thank You

    Nishant Pal 7 years, 3 months ago

    3(sides of the triangle)

    0Thank You

    Kunal Waldia 7 years, 3 months ago

    Perimeter of triangle is sum of its sides

    1Thank You

    Kunal Waldia 7 years, 3 months ago

    That is area

    0Thank You

    Utkarsh Somvanshi 7 years, 3 months ago

    1/2× base × height

    0Thank You

    ANSWER

    • Posted by Kanika Sen Sen 7 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Krishna Priya Vijayan 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    {tex}\sqrt { 3 } x ^ { 2 } - 2 \sqrt { 2 } x - 2 \sqrt { 3 } = 0{/tex}

    {tex}\sqrt { 3 } x ^ { 2 } - 3 \sqrt { 2 } x + \sqrt { 2 } x - 2 \sqrt { 3 } = 0{/tex}
    {tex}\sqrt { 3 } x [ x - \sqrt { 6 } ] + \sqrt { 2 } [ x - \sqrt { 6 } ] = 0{/tex}
    or, {tex}( x - \sqrt { 6 } ) ( \sqrt { 3 } x + \sqrt { 2 } ) = 0{/tex}
    or, {tex}x = \sqrt { 6 } , - \sqrt { \frac { 2 } { 3 } }{/tex}

    0Thank You

    ANSWER

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