CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let us assume that rootp is irrational number Therefore rootp =a/b a=b×rootp a is rational number Therefore b×rootp is also rational number But rootp is irrational number Therefore rootp is also irrational number

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If rlfkdjck

Posted by Harshita Verma 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

Are u a mental

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Sapna Jain 7 years, 2 months ago

What

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Prove that the square of any positive no is of form 5q, 5q +1, 5q +4, for some integar q

Posted by Anubhav Pratap Singh 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sapna Jain 7 years, 2 months ago

This is ncert maths ques.exercise 1.1ques 4

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two player rahul rohan play a tennis match it is known that the probability of rohan winning the match is 0.62 what is the probability of rahul winning the match

Posted by Shubham Verma 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

0.38

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Saif Khan 7 years, 2 months ago

P(rahul winning the match )=0.38

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Chapter 6 triangle prove that theorem 6.4

Posted by Sanjana Sharma 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sapna Jain 7 years, 2 months ago

Isme maths nhi hoti

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In the figure,E is a point on side BC produced of an isosceles triangle ABC with AB=AC.If AD Perpendicular to BC& EF perpendicular to AC,prove that ∆ABC~∆EFC

Posted by Soumyak Purohit 7 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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>give any two real life examples for congruent shapes

Posted by Rabab Zehra 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

Our leg and textbook

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Pallavi Balotiya 7 years, 2 months ago

Our hand and text books

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Sin 23+Sin^2 67× Cos10+Cos^2 80

Posted by Rajeev Kumar Choudhary 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Genration King Shaurya Tripathi 7 years, 2 months ago

U want this solution but how i do ihave done in copy how i show you

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How to prove that 3+√2 is a irrational number?

Posted by Shiromani Jha 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Prashant Chandila Prashant Chandila 7 years, 2 months ago

Let us assume , to the contray , that 3+/2 is rational That is why can find coprime a and b (b =0)such that 3+/2=a/b Reranging , we get root 2=a/3b Since , 3, a and b aree integers,a/3b is rational , and so root 2 is rational But this contradicts the fact that root 2 is irrational So, we conclude that 3+root 2 is irrational

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Find the probability of having 53 Sunday in leap year and a non leap year

Posted by Saheen Ali 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Punit Khandelwal 7 years, 2 months ago

Your answer is wrong. The correct ans. Is 2/7

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Saurabh Singh Harariya 7 years, 2 months ago

53/365

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If the perimeter of a sector of a circle of radius 6.5cm is 29cm what is its area??

Posted by Mahua Deogharia 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sapna Jain 7 years, 2 months ago

Maths ke ques. Ispe nhi hote

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6+5

Posted by Jacob Sabu 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

1Thank You

Vansh Sehgal 7 years, 2 months ago

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(sin A+cosecA)square +(cos A+secA)square =7+tan square A +cot square A.

Posted by Preeti Roy 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayush Srivastava 7 years, 2 months ago

this can be donevby applying a²+b²then then sin²a+cos²a become 1 and other can be done by its recuprocal

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In whixh schhol do you study ....." yogita ingle " ??

Posted by Avika Chaudhary 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

Jai bharti school

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Prashant Chandila Prashant Chandila 7 years, 2 months ago

EMERALD CONVENT SCHOOL

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A chord of a circle of radius 12cm subtends an angle of 120° at the centre . find the area of the corresponding segment of the circle. (Use π = 3. 14 and root 3 =1. 73

Posted by Nakshu Garg 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Bavneet Kaur Saini 7 years, 2 months ago

Radius and angle is given apply minor segment formula

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Bavneet Kaur Saini 7 years, 2 months ago

Area of corresponding segment of circle is ,= area of minor segment

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Frsd i am students of class 10 how to improve in math plz tell me

Posted by Ankit Jaiswal 7 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Sapna Jain 7 years, 2 months ago

Hi. U solve many and many question in one day . Practise with ncert and examples . Ncert only gave u 70 marks . You take ques. In another

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Ayush Anand 7 years, 2 months ago

Solve only 20 questions daily from maths book u will see ur improvement , its my experience

2Thank You

Kannu Kranti Yadav 7 years, 2 months ago

Hi, you can improve in maths by solving more and more questions. U should know all the theorems with their proofs . U should solve all ncert questions and exampler . Even u can take help of ur teacher if u have any doubt. U can even prefer any extra or side book.? I hope it will help u some how.

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Asif Raza 7 years, 2 months ago

Me same

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Find the value of k sothat the lines 2x-3y=9 and kx- 9 y=18 will be parallel

Posted by Prem Singh 7 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 7 years, 2 months ago

K=6

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Kannu Kranti Yadav 7 years, 2 months ago

Condition for parallel lines or no solution ---> a1/a2 = b1/b2 ≠ c1/c2..... So 2/k = 1/3 ≠1/2. So from here by solving them we get , k=6 and k≠4.

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1+1/y power 8 =y power 8.find y

Posted by Ajay Vikal 7 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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The three vertices of a parallelogram are (3,4), (3,8), and (9,8). Find the fourth vertex

Posted by Akriti Dhaker 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let A(3, 4), B(3, 8) and C(9, 8) be the given points.
Let the fourth vertex be D (x, y)
{tex}A B = \sqrt { ( 3 - 3 ) ^ { 2 } + ( 8 - 4 ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad A B = \sqrt { 0 + ( 4 ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad A B = \sqrt { 16 }{/tex}
{tex}\Rightarrow{/tex} AB = 4
{tex}B C = \sqrt { ( 9 - 3 ) ^ { 2 } + ( 8 - 8 ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad B C = \sqrt { ( 6 ) ^ { 2 } + 0 }{/tex}
{tex}\Rightarrow \quad B C = \sqrt { 36 }{/tex}
{tex}\Rightarrow{/tex} BC = 6
{tex}C D = \sqrt { ( x - 9 ) ^ { 2 } + ( y - 8 ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad C D = \sqrt { x ^ { 2 } + \left( 9 ^ { 2 } \right) - 18 x + y ^ { 2 } + \left( 8 ^ { 2 } \right) - 16 y }{/tex}
{tex}\Rightarrow \quad C D = \sqrt { x ^ { 2 } + 81 - 18 x + y ^ { 2 } + 64 - 16 y }{/tex}
{tex}\Rightarrow \quad C D = \sqrt { x ^ { 2 } - 18 x + y ^ { 2 } - 16 y + 145 }{/tex}
{tex}A D = \sqrt { ( x - 3 ) ^ { 2 } + ( y - 4 ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad A D = \sqrt { x ^ { 2 } + 9 - 6 x + y ^ { 2 } + 16 - 8 y }{/tex}
{tex}\Rightarrow \quad A D = \sqrt { x ^ { 2 } - 6 x + y ^ { 2 } - 8 y + 25 }{/tex}
Since ABCD is a parallelogram and opposite sides of a parallelogram are equal.
AB = CD and AD = BC
AB = CD
AB² = CD²
{tex}\Rightarrow{/tex} x² - 18x + y² -16y + 145 = 16
{tex}\Rightarrow{/tex} x² - 18x + y² - 16y + 145 - 16 = 0
{tex}\Rightarrow{/tex} x²- 18x + y² - 16y + 129 = 0 ...(i)
BC = AD
BC²= AD²
x² - 6x + y² - 8y + 25 = 36
{tex}\Rightarrow{/tex} x² - 6x + y² - 8y + 25 -36 = 0
{tex}\Rightarrow{/tex} x²- 6x + y² - 8y - 11 = 0 ...(ii)
Solving (i) and (ii), we get
x = 9, y = 4
{tex}\therefore{/tex} The fourth vertex is D(9, 4).

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Does marks of half yearly is calculated in board result

Posted by Saatvik Gupta 7 years, 2 months ago

CBSE > Class 10 > Mathematics

6 answers

Aryan Yadav 7 years, 2 months ago

In which school do you study

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Avika Chaudhary 7 years, 2 months ago

No ...

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Dipanshu Kumar 7 years, 2 months ago

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Diwakar Kumar 7 years, 2 months ago

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Dev Khurana 7 years, 2 months ago

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Vansh Sehgal 7 years, 2 months ago

Yes

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Find the HCF of x cube-3x+2 and x square-4x+3.

Posted by Vanshika Gupta 7 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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How to prove 2root 3 is irrational number

Posted by Aditya Patil 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayush Chauhan 7 years, 2 months ago

Let 2√3 be rational 2√3 = p/q. ( where p and q are integer and q does not equal to 0) √3 = p/q ×2 Irrational = Rational But the contradicts that irrational does not equal to rational So, our supposition was wrong And 2√3 is irrational number

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How to prove root5 irrational

Posted by Gagan Raj 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Kannu Kranti Yadav 7 years, 2 months ago

Let √5 be a rational number then it can be written in the form of a/b where b≠0 , a and b are co prime numbers ... So √5= a/b , now squaring on both sides gives 5=a²/b². 5b² = a² . Now we can say that a² is divisible by 5 then a is also divisible by 5. Let a =5c , squaring on both sides gives a²=25 c². Putting value of a² ... 5b² =25 c²... b²=5c².. so we can say that b² is divisible by 5 then b is also divisible by 5. So our assumption is wrong , so due to contradiction √5 is an irrational number as it a common factor other than a and b . Hence proved.

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An equilateral triangle has two vertices at the points(3,4)and(-2,3),find the coordinates of the third vertex.

Posted by Gaurav Kr Bhardwaj 7 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Cross multipleplication

Posted by Shahnawaz Khan 7 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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If A (-2,4),B(0,0) and C(4,2) are vertices of triangle ABC ,then find the length of the median through the vertex A

Posted by Meheak Fathima 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Vipul Gupta 7 years, 2 months ago

First you find the vertices of d ,where the median A touch the line B and C . To find the vertices of D and then by the help of distance formula you can find the length of the median through vertices A

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Water in a canal 5.4m cbse 2017 clàss 10

Posted by Quyamuddin Ansari 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

According to the question,we have the following information.
Water flow in 1 hr = Area of cross-section {tex}\times{/tex} Speed of water
{tex}= 5 \cdot 4 \times 1 \cdot 8 \times 25000 \mathrm { m } ^ { 3 }{/tex}=54×18×250
Water flow in 40 minutes
{tex}= 54 \times 6 \times 500 \mathrm { m } ^ { 3 }{/tex}

Irrigated area {tex}\times \frac { 10 } { 100 } = 54 \times 6 \times 500{/tex}

Irrigated area {tex}= 54 \times 6 \times 500 \times 10{/tex}

{tex}= 1620000 \mathrm { m } ^ { 2}{/tex}

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Instead of studying ncert maths book which reference book is the best please tell me

Posted by Ayush Priyaarshi 7 years, 2 months ago

CBSE > Class 10 > Mathematics