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  • 1 answers

Shivam Anand 7 years, 1 month ago

Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest. It is the result of reinvesting interest, rather than paying it out, so that interest in the next period is then earned on the principal sum plus previously accumulated interest.
  • 1 answers

Raj Soni 7 years, 1 month ago

Cbseacademic.nic.in
  • 1 answers

Mr. Singh 7 years, 1 month ago

4u square + 8u =0 4u(u+2)=0 4u=0,u=0 (u+2)=0 u=-2. (0,-2) Ans.✔
  • 5 answers

Raj Soni 7 years, 1 month ago

Cbseacademic.nic.in

Zohran Jamil 7 years, 1 month ago

Cbse academics se download kar lo jo cbse official website h

Saket Parihar 7 years, 1 month ago

Sample paper ki link kya ha

Ajay Patel 7 years, 1 month ago

Yes

Radhika :) Mishra:} 7 years, 1 month ago

Haan usse related questions aa sakte hai
  • 5 answers

Mr. Singh 7 years, 1 month ago

Nice que

Mr. Singh 7 years, 1 month ago

Mathematics is a old, board, deep discipline (field of study).people wrking to improve math education need to understand "what is math?"✔

Nidhi 23 7 years, 1 month ago

Maths is a field of study

Tamanna Soni 7 years, 1 month ago

??

Nidhi 23 7 years, 1 month ago

Full form of maths mere aatma tuse hamesa satayegi . It is a book by which we can feel bore.
  • 0 answers
Rr
  • 1 answers

Abhidipan Bhanja 7 years, 1 month ago

?
  • 1 answers

Sia ? 6 years, 6 months ago

We have,
{tex}2\left(\frac{\cos58^\circ}{\sin32^\circ}\right)-\sqrt3\left(\frac{\cos38^\circ cosec52^\circ}{\tan15^\circ\tan60^\circ\tan75^\circ}\right){/tex}
{tex}=2\left\{\frac{\cos\left(90^\circ-32^\circ\right)}{\sin32^\circ}\right\}-\sqrt3\left\{\frac{\cos38^\circ cosec\left(90^\circ-38^\circ\right)}{\tan15^\circ\tan60^\circ\tan\left(90^\circ-15^\circ\right)}\right\}{/tex}
{tex}= 2 \left( \frac { \sin 32 ^ { \circ } } { \sin 32 ^ { \circ } } \right) - \sqrt { 3 } \left\{ \frac { \cos 38 ^ { \circ } \sec 38 ^ { \circ } } { \tan 15 ^ { \circ } \times \sqrt { 3 } \times \cot 15 ^ { \circ } } \right\}{/tex}   {tex}\left[\because\;\cos\left(90-\theta\right)=\sin\theta\;,\;\cos ec\left(90-\theta\right)=sec\theta,\;\tan\left(90-\theta\right)=cot\theta\;\right]{/tex}
{tex}= 2 - \sqrt { 3 } \left\{ \frac { \cos 38 ^ { \circ } \times \frac { 1 } { \cos 38 ^ { \circ } } } { \tan 15 ^ { \circ } \times \sqrt { 3 } \times \frac { 1 } { \tan 15 ^ { \circ } } } \right\} = 2 - \frac { \sqrt { 3 } } { \sqrt { 3 } } = 2 - 1 = 1{/tex}    {tex}\left[sec\theta=\frac1{\cos\theta},\;cot\theta=\frac1{\tan\theta}\right]{/tex}

therefore, {tex}2\left(\frac{\cos58^\circ}{\sin32^\circ}\right)-\sqrt3\left(\frac{\cos38^\circ cosec52^\circ}{\tan15^\circ\tan60^\circ\tan75^\circ}\right)=1{/tex}

  • 2 answers

Sarita S 7 years, 1 month ago

3,6... a=3 ,d=3,n=8 =a+(n-1)×d =3+(8-1)×3 =3+7×3 =3+21 =24 T8=24 3,6,9,12,15,18,21,24

Abhishek Varma 7 years, 1 month ago

1st 8 multiples of 3 are- 3,6,9,12,15,18,21,24. Here, a=3 d=3 an=24 n=8(using an formula) Sn=112(using Sn formula).
  • 5 answers

Abhidipan Bhanja 7 years, 1 month ago

1

Feba Roji 7 years, 1 month ago

1

Mr. Singh 7 years, 1 month ago

1

Mr. Singh 7 years, 1 month ago

2

Jestin Samuel 7 years, 1 month ago

1
  • 2 answers

Shubham Sharma 7 years, 1 month ago

I don t know

Sarita S 7 years, 1 month ago

This ques is not complete
  • 1 answers

Sarita S 7 years, 1 month ago

What is this
  • 6 answers

Abhidipan Bhanja 7 years, 1 month ago

-b/a

Mr. Singh 7 years, 1 month ago

-b/a

Sanju Yadav 7 years, 1 month ago

Alpha +beta=-b/a

Utkarsh Verma 7 years, 1 month ago

In an quadratic equations -b/a

Ayush Malani 7 years, 1 month ago

-b/a

Velan Velan 7 years, 1 month ago

-b/a
  • 4 answers

Mr. Singh 7 years, 1 month ago

C/A.✅

Sanju Yadav 7 years, 1 month ago

(Alpha) (beta) =c/a

Utkarsh Verma 7 years, 1 month ago

c/a

Harsh Kumar 7 years, 1 month ago

c/a
  • 0 answers
  • 1 answers

Sia ? 6 years, 6 months ago

We have to draw a line segment of length 7 cm.Then,we have to find  a point P on it, which divides it in the ratio 3 : 5.
Steps of construction:

  1. Draw a line segment {tex}AB=7{/tex} cm.
  2. Draw a ray AX, making an acute {tex}\angle BAX{/tex} with AB.
  3. Mark {tex}3+5=8{/tex} points, i.e, {tex}A_1, A_2, A_3, A_4 ...A_8{/tex} on AX, such that {tex}AA_1 = A_1A_2 = A_2A_3 = A_3A_4 ... = A_7A_8{/tex}
  4. Join A{tex}_8{/tex}B
  5. From A3, draw {tex}A_3P || A_8B{/tex} which intersects AB at point P [ by making an angle at A3 equal to {tex}\angle AA_8B{/tex} 
    Then, P is the point on AB which divides it in the ratio 3:5. So, {tex}AP : PB = 3:5{/tex}

Justification: In {tex}\triangle ABA_8{/tex}, we have {tex}A_3P || A_8B{/tex} 
{tex}\therefore \frac{AP}{PB}=\frac{AA_3}{A_3A_8}{/tex} [ by basic proportionality theorem]
By construction, {tex}\frac{AA_3}{A_3A_8}=\frac{3}{5}{/tex} 
Hence, {tex}\frac{AP}{PB}=\frac{3}{5}{/tex}

  • 1 answers

Kanha Bhai 7 years, 1 month ago

An expression which is in the form of a0x²+a2x²+.....+anx² is called polynomial Where an a...an are real number Example: 5x+7=0 7x+x²+9=0
  • 3 answers

Garima Demla 7 years, 1 month ago

Please give the solution..

Rishika Rishika 7 years, 1 month ago

Ggdyh

Garima Demla 7 years, 1 month ago

Options are. 1.n/2 2.-n 3 zero 4.n
  • 1 answers

Sreehitha M 7 years, 1 month ago

1/2 • a(base side) • c (base side) • h (height)
  • 0 answers
  • 4 answers

Mrityunjay Sharma 7 years, 1 month ago

Sohan tera kya lagta hai Bhai

Golu Mis 7 years, 1 month ago

10x-5x=5x

Golu Mis 7 years, 1 month ago

Let sohan age is (x) and rohan age (x+5) 5(x)=5(2x) 5x=10x x-x=10-5 =5

Niraj Choudhury 7 years, 1 month ago

Uhdhsj
  • 1 answers

Sia ? 6 years, 6 months ago

According to the question, {tex}\triangle ABC {/tex} is an equilateral triangle.
In {tex}\triangle{/tex}ABD, using Pythagoras theorem,

{tex}\Rightarrow{/tex} AB2 = AD2 + BD2
{tex}\Rightarrow{/tex} BC2 = AD2 + BD2, (as AB = BC = CA)
{tex}\Rightarrow{/tex} (2 BD)2 = AD2 + BD2, (perpendicular is the median in an equilateral triangle)
{tex}\Rightarrow{/tex} 4BD2 - BD2 = AD2
{tex}\therefore{/tex} 3BD2 = AD2

  • 1 answers

Sreehitha M 7 years, 1 month ago

U can get the answers in mycbseguide app
  • 3 answers

Komal Jha 7 years, 1 month ago

Yes you are right practise hamesa karni chahiye

Zeenat Siddiqui?? 7 years, 1 month ago

Yes maths is the best subject Agr concept clear hoga nd practice hmesa krte rhnge to sabse jldi banne wala nd sabse asaan subject h maths

Komal Jha 7 years, 1 month ago

Kishne kha math best h math jab ati h to best h agar nhi ati to lagta h bakvas h
  • 1 answers

Kannu Kranti Yadav 7 years, 1 month ago

Let , √2 be a rational number . Then it can be written in the form of a/b where b≠0 and ( a,b are co prime no.s) √2=a/b , now squaring on both sides.. 2= a²/b²... 2b²=a² .. it means a² is divisible by 2 . So a is also divisible by 2. .......... Let , a=2c , now squaring on both sides a²=4 c² putting value of a²... 2b²=4c² --> b²=2c² it means b² is divisible by 2 , so b is also divisible by 2 . Therefore our assumption is wrong . Hence, due to contradiction √2 is an irrational number as it has other common factor other than a and b . Hence, proved that √2 is an irrational number
  • 2 answers

Ankush Pratap 7 years, 1 month ago

1/4 part of the circle is a quadrant

Mr. Singh 7 years, 1 month ago

The cartesian plane is divided by the axis of refrence into four part is known as quadrant .

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