CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let PQ be the ladder such that is top Q is on the wall OQ.
The ladder is pulled away from the wall through a distance a, so Q slides and takes position Q'.
Clearly, $PQ = P'Q'.$
In $\Delta 's$ $POQ \ and \ P'OQ',$ we have
$\sin \alpha = \frac{{OQ}}{{PQ}},\cos \alpha = \frac{{OP}}{{PQ}},\sin \beta = \frac{{OQ'}}{{P'Q'}},\cos \beta = \frac{{OP'}}{{P'Q'}}$
$\Rightarrow \sin \alpha = \frac{{b + y}}{{PQ}},\cos \alpha \frac{x}{{PQ}},\sin \beta = \frac{y}{{PQ}},\cos \beta = \frac{{a + x}}{{PQ}}$
$\Rightarrow \sin \alpha - \sin \beta = \frac{{b + y}}{{PQ}} - \frac{y}{{PQ}}$ and
$\cos \beta - \cos \alpha = \frac{{a + x}}{{PQ}} - \frac{x}{{PQ}}$
$\Rightarrow \sin \alpha - \sin \beta = \frac{b}{{PQ}}$ and
$\cos \beta - \cos \alpha = \frac{a}{{PQ}}$
$\Rightarrow \frac{a}{b} = \frac{{\cos \alpha - \cos \beta }}{{\sin \beta - \sin \alpha }}$

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ANSWER

tan1 tan11 tan21 tan69 tan79 tan 89 = 1

Posted by Touheed Pathan 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Sandhya Sridhar 6 years, 6 months ago

Tan (90-1)tan (90-11) tan (90-21) tan69 tan79 tan89=1 Cot89 cot79 cot69 tan69 tan79 tan89=1 I/ tan89 1/tan79 1/ tan69 tan69 tan 79 tan 89 =1(1/tan=cot) 1=1

2Thank You

Touheed Pathan 6 years, 6 months ago

Solve this problem

4Thank You

ANSWER

If sum of the first 14 terms of an ap is 1050 and its first term is 10, find the 20th term

Posted by Rajbir Kaur 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 6 months ago

Here,

S₁₄ = 1050

n = 14,

a = 10

S_n = n/2 [2a + (n - 1)d]

1050 = 14/2 [20 + 13d]

1050 = 140 + 91d

910 = 91d

d = 10

Therefore,

a₂₀= 10 + (20 – 1) × 10 = 200

The 20th term is 200.

2Thank You

ANSWER

Surface area of hemisphere

Posted by Ravi Jindal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Sapna Jain 6 years, 6 months ago

3πrsquare

0Thank You

Yogita Ingle 6 years, 6 months ago

Total surface area of the hemisphere– While calculating the total surface area of a hemisphere, we need to consider the base of the hemisphere which is circular in shape. Thus the total surface area of a hemisphere is equal to

total surface area= curved surface area + area of the base circle

= <nobr>2πr²+πr²</nobr>

= <nobr>3πr²</nobr>

Area of Hollow Hemisphere = Area of External Hemisphere – Area of Internal Hemisphere

1Thank You

ANSWER

Is secA + tanA=p then find in terms of cosecA

Posted by Ishu Jain 6 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

find the sum of the first 50 odd natural numbers by using arithmetic progression

Posted by Archana Sarode 6 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Ravi Jindal 6 years, 6 months ago

1,3,5 is correct in place 1,2,3

1Thank You

Ravi Jindal 6 years, 6 months ago

1,2,3....... a=1,d=2,n=50 S=n/2(2a+(n-1)d) S=50/2(2(1)+(50-1)2 S=25(2+(49)2) S=25(2+98) S=25(100) S=2500

1Thank You

Yogita Ingle 6 years, 6 months ago

The first 50 natural odd numbers = 1,3,5,7... (upto 50 terms) which is an AP.
Now, s_n = n/2 [2a + (n-1)d]
S₅₀ = 50/2 [2x1 + (50-1)2]
= 25 (2 + 98)
= 25 x 100
= 2500

1Thank You

ANSWER

In triangle ABC, AD is perpendicular bisector of BC such that AD square = BD. CD ,prove that triangle ABC is right angle...

Posted by Archana Sarode 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Archana Sarode 6 years, 6 months ago

You can send the answer here also no need to give number brother I think you understood it nicely

1Thank You

Karan Singh 6 years, 6 months ago

I can send you answer on phone can you give your number.#if you want

1Thank You

ANSWER

What is formula of Area of segment of a circle

Posted by Aditya Raut 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 6 months ago

The circular region enclosed between a chord and the corresponding arc is called the segment of a circle.

Minor segment : If the boundary of a segment is a minor arc of a circle, then the corresponding segment is called a minor segment.

Major segment: A segment corresponding a major arc of a circle is called as major segment.
Area of Minor segment = θ/360 πr²
Area of major segment = Area if circle - Area of Minor segment

2Thank You

Karuna Kashyap 6 years, 6 months ago

Area of segment of a circle =area of the corresponding sector-area of the corresponding triangle

1Thank You

ANSWER

If x=2 & x=3 are the roots of the equation 3x2-2mx+2n=0 then find the value of m and n

Posted by Sahil Raj 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 6 months ago

3x² - 2mx + 2n = 0
x = 2
2 (2)² - 2m(2) + 2n = 0
2(4) - 4m +2n = 0
8 - 4m + 2n = 0
4- 2m + n = 0
2m - n = 4.... (i)
x = 3
2 (3)² - 2m(3) + 2n = 0
2(9) - 6m +2n = 0
18 - 6m + 2n = 0
3m - n = 9 ...... (ii)
After solving m = 5 and n = 6.

0Thank You

Dipti Singh 6 years, 6 months ago

M=15/2 N=9

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ANSWER

Find the area of minor segment of circle of radius 42 cm. If length of corresponding arc is 44cm.

Posted by Yash Mohite 6 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 6 months ago

Length of arc = θ/360 2πr = 44 cm
Putting r = 42cm, we get θ= 60°
Now, Area of minor segment= Area of minor sector-Area of ∆
Since = 60°, so the triangle formed will be an equilateral
∴ ∆ Area of minor segment= Area of minor sector - Area of equilateral ∆
i.e. Area of minor segment = θ/360 πr² - √3/4 a²
= 924 - 441√3 cm²

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Dipti Singh 6 years, 6 months ago

76 approx

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If a diameter of cicle is increased by40% find by how much percentage its area increases

Posted by Sandeep Adhikari 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 6 months ago

diameter = d
=> radius = d/2
new diameter = d + 40% of d = d + 2d/5 = 7d/5
=> increased radius = 7d/10
original area= 22/7 X d² / 4 = 11d² / 14
increased area = 22/7 X 49d²/100 = 539d² / 350
increase = (539d² - 297d²)/ 350 = 242d²/ 350
= 121d²/ 165

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ANSWER

If the mid point of the line segment joining the point P ( 6,a_2) and Q (_2,4) is (2 ,_4) , then find the value of a

Posted by Bhumika Patel 6 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Hii.... Friends Good morning

Posted by Akash Kumar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo 6 years, 6 months ago

Gd morning...☺☺

1Thank You

ANSWER

How to find frequency in the given table in formula of median

Posted by Aman Mandal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is hole number

Posted by Muskan Khan 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Sapna Jain 6 years, 6 months ago

Numbers from 0 to infinity

1Thank You

Ansh Giri 6 years, 6 months ago

If you are asking for whole numbers then answer is - numbers from 0 to infinity are called whole no.s O.k

1Thank You

Abhinav Yadav 6 years, 6 months ago

All natural numbers together with 0.

0Thank You

ANSWER

Find The co-ordinates to a point on y- axis which is nearest to the point( -2,5).

Posted by Mansi ??⚘?? 6 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Mansi ??⚘?? 6 years, 6 months ago

Thanks to both of यू

0Thank You

Yogita Ingle 6 years, 6 months ago

It will be (0,5) as we know that in coordinates we first keep x and then y, i.e., (x,y).
So the point on y-axis will be (0,x) , here we have supposed the point on y-axis as x.
As the nearest point is given (-2,5), so the nearest point will be 5 .
Thus the answer is (0,5).

1Thank You

Yogesh Birhman 6 years, 6 months ago

o,5 is the answer

1Thank You

ANSWER

How find similar triangle

Posted by Rk Shah 6 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Sapna Jain 6 years, 6 months ago

By any rule but most aa rule

0Thank You

Sourav Kumar 6 years, 6 months ago

By AA rulw

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Riyam Arora 6 years, 6 months ago

By AA RULE

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ANSWER

Factorization mein middle term split karte vakt middle mein common factors kaise nikalen.

Posted by Puja Sahoo 6 years, 6 months ago

CBSE > Class 10 > Mathematics

6 answers

Sapna Jain 6 years, 6 months ago

First and last term ko multiply krke jo aayega uske factor krne h

1Thank You

Puja Sahoo 6 years, 6 months ago

Tum log jo bhi bata rahe ho mujhe ata hai...

0Thank You

Puja Sahoo 6 years, 6 months ago

Magar vo do term choose karne mein hi problem hoti hai samjhe

0Thank You

Mahima Pandey 6 years, 6 months ago

Pehle x ^2 ke cofficient ko aur constant term ko multiply kro. Uske baad X ke cofficient ko factorise karke do numbers choose karo jise ki multiply karne ke baad hame x^2 ke cofficient aur constant term ka product mile aur use add ya subtract karne ke baad hameX ka cofficient mil jae. Example 4x^2 -10x +4 (4×4=16;10 ko split karege to hame 2,8 milega) 4x^2-10x+4 = 4x^2 -8x -2x +4. =4x(x-2)-2(x-2)=(4x-2)(x-2)=0 so x=2/4 and 2

1Thank You

Puja Sahoo 6 years, 6 months ago

Mujhe bhi pata hai but how to choose two middle terms ,middle vale ko kisme splitt karun.

1Thank You

Aryan Aggarwal 6 years, 6 months ago

First and last term ko multiply kar ke jo aayega

1Thank You

ANSWER

Kya koi online hai.........

Posted by Puja Sahoo 5 years, 3 months ago

CBSE > Class 10 > Mathematics