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Posted by Akshit Prajapati 6 years, 11 months ago
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Posted by Akshit Prajapati 6 years, 11 months ago
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Puja Sahoo 6 years, 11 months ago
Posted by Roman Empire 6 years, 11 months ago
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Shivani Jangid 6 years, 11 months ago
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Posted by Abhinav Singh 6 years, 11 months ago
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Chētnà Pandey✌️ 6 years, 11 months ago
Posted by Abhishek Pandey 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Let the first term and common difference of the AP be A and D
pth term = a ……… (given)
= A + (p – 1)D = a ............(1)
qth term = b
{tex}\Rightarrow {/tex} A + (q - 1) D = b ......... (2)
rth term = c .......... Given
{tex}\Rightarrow {/tex} A + (r - 1) D = c ........ (3)
Multiplying equations (1), (2) and (3) by q - r, r - p and p - q respecitvely, we get
a(q - r) + b(r - p) + c(p - q)
= [A + (p - 1) D] (q - r) + [A + (q - 1)D] (r - p) + [A + (r - 1) D] (p - q)]
= A [q - r + r - p + p - q] + D [(p - q) (q - r) + (q - 1) (r- p) + (r - 1) (p - q)]
= A (0) + D(0)
= 0
Posted by Me ❣️ 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
ax + by = a - b multiply by a
bx - ay = a + b multiply by b

{tex}\Rightarrow{/tex} x = 1
{tex}\therefore{/tex} a + by = a - b
by = -b
y = -1
{tex}\therefore{/tex} x = 1
y = -1
Posted by Aryan Soni 6 years, 11 months ago
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Sumit Yadav 6 years, 11 months ago
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Diksha Y 6 years, 11 months ago
Posted by Lavish Tomar 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
Let one number be x.
therefore , another number = 16 - x (because sum of two numbers is 16)
also ,
1/x + 1/16 - x = 1/3 (Given)
(16 -x +x) / x(16 -x) = 1/3
16*3 = x(16 - x)
48 = 16x - x²
or x² - 16x + 48 = 0
or x² - 12x - 4x + 48 =0
x(x-12) -4(x-12) =0
x-4 = 0 or x-12 =0
x=4 or x=12
hence one Number is 4 .
and another number = 16 - x =16 - 4 = 12 .
Posted by Omkar Chahilya 6 years, 11 months ago
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