CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

If A(4, 3), B (-1, y), and C(3,4) are the vertices of a right triangle ABC, right angled at A, then, we have to find the value of y.
By Pythagoras theorm,
AB² + AC² = BC²
or,(4 + 1)² + (3 - y)² + (3 - 4 )² + (4 - 3)²= (3 + 1)² + (4- y)²
or, (5)² + (3 - y)² + (-1)² + (1)²= (4)² + (4 - y)²
or, 25 + 9 - 6y + y² + 1 + 1 = 16 + 16 - 8y +y²
or, 36 + 2y - 32 = 0
or, y = - 2

0Thank You

ANSWER

If alpha and beta are the zeros of the polynomial f(x)=x2+x-2,find the value of (1/aplha-1/beta)

Posted by Khushi Kumari 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 11 months ago

Say A=Alfa,B=betas

x²+x-2

A+B= -1,AB=-2

1/A-1/B=(B-A)/AB

{tex} = \sqrt{((A+B)^2-4AB)} \over AB{/tex}

=√(1+8)/(-2)= -3/2

1Thank You

ANSWER

A pole has to be erected at a point on the boundary of a circular park of diameter 17m in such a way that the difference of its distances from two diametrically opposite fixed gates A and B on the boundary is 7 meters.find the distance from the two gates where the pole is to be erected.

Posted by Mayank Kumawat 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let P be the position of the pole and A & B be the opposite fixed gates. Let, BP= x metres.
{tex}\therefore{/tex} AP = x + 7
In right triangle APB,
AP² + BP² = AB²
{tex}\Rightarrow{/tex}(x + 7)² + x² = 13²
{tex}\Rightarrow{/tex}x² + 49 + 14x + x² = 169
{tex}\Rightarrow{/tex} 2x² + 14x + 49 - 169 = 0
{tex}\Rightarrow{/tex}2x² + 14x - 120 = 0
{tex}\Rightarrow{/tex}2(x² + 7x - 60) = 0
{tex}\Rightarrow{/tex} x² + 7x - 60 = 0
{tex}\Rightarrow{/tex}x² + 12x - 5x - 60 = 0
{tex}\Rightarrow{/tex} x(x + 12) - 5(x + 12) = 0
{tex}\Rightarrow{/tex} (x + 12)(x - 5) = 0

{tex}\Rightarrow x=5 \ or \ -12{/tex}

As x can not be negative. So, x = 5.

Therefore, AP = 7+5 = 12
Hence, AP = 12 m and BP = 5 m

0Thank You

ANSWER

What stream u r thinking to take in 11th guys ?

Posted by Prisha Rathore 6 years, 11 months ago

CBSE > Class 10 > Mathematics

7 answers

Prisha Rathore 6 years, 11 months ago

PCB

0Thank You

Isha Arora 6 years, 11 months ago

Pata nhi

1Thank You

Naina Lamba 6 years, 11 months ago

Medical

2Thank You

Daksh Sharma 6 years, 11 months ago

Arts

3Thank You

Anurag Mishra 6 years, 11 months ago

PCMB

2Thank You

Anshika Agrawal 6 years, 11 months ago

Maths

2Thank You

Sameer Joshi 6 years, 11 months ago

Commers

3Thank You

ANSWER

Which questions are important from circles chapter??

Posted by Anshika Pal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Sachin Singh 6 years, 11 months ago

Only q 9,12,and13 are most important and the tangents theoram is also importamt

1Thank You

Prashant Mitraov 6 years, 11 months ago

8,9,11,12,13 of ex.10.2 and one is ready to come in board exam

3Thank You

ANSWER

If radius of a circle is increased by 10% then area is increased by how many %

Posted by Aayushi Shah 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Prashant Mitraov 6 years, 11 months ago

21℅ not 1.21 times because question ask by what ℅ not times the earlier

3Thank You

Ram Kushwah 5 years, 8 months ago

New radius =1.1r

Area=π(1.1r)²=1.21πr²

Hence area becomes 1.21 times

5Thank You

ANSWER

In fig. ABCDEF is a regular hexagon with different vertices A,B,C,D,E & F as the centres of the circle with the same radius "r" are drawn. Find the area of the shaded portion.

Posted by Ashish Raj 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Yaar 6 years, 11 months ago

What is the shaded part

2Thank You

ANSWER

solve for x and y bx+ ay=a+b and ax(1/ a-b - 1/a+b)+ by(1/b-a - 1/b+a) = 2a/a+b

Posted by Anoop Ashokan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If ( x/a sin - y/b cos) =1 and (x/a cos + y/b sin) =1 prove that (X square / a square + y square / b square) = 2

Posted by Janvi Rana Janvi Rana 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 11 months ago

x/a.cost+y/b.sint=1

x/a.sint-y/b.cost=1

Squaring and adding both the eqn we get

x²/a²(sin2t+cos2t)+y2/b2(sin2t+cos2t)+2xy/absintcost-2xy/absintcost-2xy=2

x2 /a2+y2/b2=2

1Thank You

ANSWER

A hemispherical tank of diameter 3M is full of water it is being emptied by a pipe at the rate of 3 whole 4.7 litre per second how much time will it take to make tank half emptied

Posted by Pratham Vardaan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Ram Kushwah 6 years, 11 months ago

Let tank empties in t sec

Volume of tank

=2/3πr³×1000 litre (1m³=1000 litres)

V=2/3×22/7×27/8×1000 litre,........(1)

Also V=speed×time=25/7×t...........(2)

From (1)and (2) we will get

t=1980 sec=33 minutes

0Thank You

Harish Gupta 6 years, 11 months ago

Here 3 whole means the quotient . When 25 is divided by 7 the remainder is 4 and quotient is 3

2Thank You

Harish Gupta 6 years, 11 months ago

16.5minutes

0Thank You

Prashant Mitraov 6 years, 11 months ago

3whole ka kya matlab

1Thank You

ANSWER

Prove that; cotA-cosA/cotA+cosA=cosecA-1/cosecA+1

Posted by Soham Nirhali 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Shubhanshu Tiwari 6 years, 11 months ago

We can write cot A minus Cos A upon cot A + cos A is equal to cosA upon sinA minus CosA.whole upon cos upon sinA + cosA now we will take cosA common from whole equation then we have 1upon sin minus 1 whole upon 1 upon sin + 1 then we know that one upon sin is equal to cosecA minus one whole upon 1 upon sin is equal to cosA plus 1 now we got our answer what we have to prove

3Thank You

ANSWER

Find cosec30 and cos 60 geometrically

Posted by Ro Cky 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Aradhana Singh 6 years, 11 months ago

Answer is 2

0Thank You

????? ❤️ 6 years, 11 months ago

Aise question bhi aaenge kya exam me??

0Thank You

Prashant Mitraov 5 years, 8 months ago

Good ques. Ans.mile to batana

3Thank You

ANSWER

a squre of diagonal 8cm is inscribed in a circle . find the area of shaded part

Posted by Mayuresh Bansiwal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Keerthana Maran 6 years, 11 months ago

Since it is a square, all 4 sides are equal.. the diagonal is also given.. 2AB^2=AC^2 AC=4 AB^2=8 AB=2root2 cm Side of the square is equal to diametre of the circle.. Therefore radius of the circle is root2 cm.. Area of the circle= 22/7×2root2×2root2 = 22×8/7 Area of square = 2root2×2root2=8cm Therefore area of shaded region = 8-(22×8/7) = 8-25 /-18/ .. negative areas within bar brackets

0Thank You

ANSWER

(Cos^2alpha-1)(cot^2alpha+1)+1=0

Posted by Atharva Bhosale 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Prashant Mitraov 6 years, 11 months ago

So value of alpha is 90°because by solving cos alpha=0

0Thank You

ANSWER

From an external point p, tangents PA and PB are drawn to a circle with centre O. If ‹PAB = 50 degree, then find angle AOB

Posted by Dushyant Chaudhary 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Prashant Mitraov 6 years, 11 months ago

130°

1Thank You

Susmita Mandal 6 years, 11 months ago

130°

0Thank You

ANSWER

Find the HCF of 4052 and 420 and their linear c ombination

Posted by Anshu Maurya 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Anshu Maurya 6 years, 11 months ago

Thanks for answer

0Thank You

Kashyap Patel 6 years, 11 months ago

4052=420×9+272 420=272×1+148 272=148×1+124 148=124×1+24 124=24×5+4 24=4×6+0 hence hcf is 4

1Thank You

Sourav Pant 6 years, 11 months ago

1Thank You

ANSWER

Solve by cross multiplication (a+b)x+(a-b)y =2ab and( a-b)x+(a+b )y=a^2+b ^2

Posted by Bableen Gill 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

x = a + b
{tex}\therefore{/tex} (a - b)(a + b) + (a + b)y = a² - b² - 2ab
a² - b² + (a + b)y = a² - b² - 2ab
{tex}y = \frac{{ - 2ab}}{{a + b}}{/tex}

0Thank You

ANSWER

What is the formula of total surface area of semi circla

Posted by Shivam Jaat 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

????? ❤️ 6 years, 11 months ago

Nhi πr^2/2

0Thank You

Mohit Dubey 6 years, 11 months ago

3 pie r sq.

0Thank You

ANSWER

An aeroplane leaves an airport and flies due north at as speed of 1000 km per hour . At the same time , another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour . How far apart will be the two planes after 1.5 hour

Posted by Suraj Kumar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Distance traveled by the plane flying toward north in {tex}1\frac{1}{2}{/tex}hrs
{tex} = 1,000 \times 1\frac{1}{2} = 1,500km{/tex}
Similarly, distance traveled by the plane flying towards west in {tex}1\frac{1}{2}{/tex}hrs
{tex} = 1,200 \times 1\frac{1}{2} = 1,800km{/tex}
Let these distances are represented by OA and OB respectively.
Now applying Pythagoras theorem
Distance between these planes after {tex}1\frac{1}{2}{/tex}hrs {tex}AB = \sqrt {O{A^2} + O{B^2}} {/tex}
{tex} = \sqrt {{{(1,500)}^2} + {{(1,800)}^2}}{/tex} {tex}= \sqrt {2250000 + 3240000}{/tex}
{tex} = \sqrt {5490000} = \sqrt {9 \times 610000} = 300\sqrt {61} {/tex}
So, distance between these planes will be {tex}300\sqrt {61} {/tex}km, after {tex}1\frac{1}{2}{/tex}hrs.

0Thank You

ANSWER

5-3.5/2

Posted by Avinash Vishwakarma 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Shardul Vinay Khanang 6 years, 11 months ago

Apply BODMAS rule, Then, 5-3.5/2 =5-1.75 =3.25.

1Thank You

Subham Jaiswal 6 years, 11 months ago

3.25 is the answer

2Thank You

Kuldeep Agrahari 6 years, 11 months ago

Answer=3.25

2Thank You

ANSWER

If sin theta +tan theta =m and sin theta - tan theta =n. Prove that m^2 - n ^2 =4 under root "mn"

Posted by Faizan Nabi 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Faizan Nabi 6 years, 11 months ago

Thank you for answers

0Thank You

Kuldeep Agrahari 6 years, 11 months ago

lHS=(sin+tan)^2-(sin^2-tan^2). A. (Sin^2+tan^2+2sin*tan)-(sin^2+tan^2-2sin*tan). B. Sin^2+tan^2+2sin*tan-sin^2-tan^2+2sin*tan. C. 4sin*tan D. RHS=4√(sin+tan)(sin-tan). A. =4√sin^2-tan^2. S. =4√sin^2-sin^2/cos^2. R. =4√sin^2*cos^2-sin^2. A. ------------------------------. F. Cos^2. A. =4√sin^2(cos^2-1). T. ---------------------. =4tan*sin. I. Cos^2

2Thank You

Varun Punia 6 years, 11 months ago

(TanA +sinA) ^2-2ho)(tanA-sinA)^2=√(tanA+sinA)(tanA-sinA)

3Thank You

ANSWER

Proof /5 is irrational.

Posted by Sumit Dhali 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Surbhi Yadav 6 years, 11 months ago

Let us assume to the contary that √5 is a rational no. So , √5 =p/q where pand q are co primes and q not equal to zero Squaring both the sides 5 = p^2 /q^2 5q^2 = p^2 This means that 5q^2 is factors p and p^2 (5a)^2=5 q^2 5a^2= q^2 This means that 5a^2 is factor of q^2 This quantradicts that √5 is rational no. And p and q are co primes

3Thank You

ANSWER

If one zero of the polynomial is reciprocal of second then find the value of k where p(x) 5x + x + k=0

Posted by Chirag Mittal 6 years, 11 months ago

CBSE > Class 10 > Mathematics