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Subtract 2nd term from the 1st you will get b as the common diff. and again if you will subtract 2nd term from the 3rd term and again you will get b as the common diff. This shows that.........

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Draw a circle of radius 8 cm take two points p and q on one of its extended diameter each at a distance of 7cm from its center draw the tangents to the circle from these points P andQ

Posted by Dilpreet Brar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Prisha Rathore 6 years, 11 months ago

How we will post the figure

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CosA/1+sinA+1+sinA/cosA=2secA

Posted by Soham Nirhali 6 years, 11 months ago

CBSE > Class 10 > Mathematics

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Prashant Mitraov 6 years, 11 months ago

L.C.M. se solve kar le bhai

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Prove that sin(A+B)=sinACosB+sinBcosA

Posted by Navjeet Singh 5 years, 8 months ago

CBSE > Class 10 > Mathematics

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Prove that the sum of the square of the diagonals of a Parallelogram is equal to the sum of the square of its side

Posted by Aditya Chahar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 6 months ago

Given: ABCD is a parallelogram whose diagonals are AC and BD.
To prove: AB² + BC² + CD² + DA² = AC² + BD²
Construction: Draw AM {tex} \bot {/tex} DC and BN {tex} \bot {/tex} D(Produced)

Proof: In right triangle AMD and BNC.
AD = BC ..............Opp.sides of a ||gm
AM = BN ............Both are altitudes of the same parallelogram to the same base
{tex}\therefore {/tex} {tex}\triangle {/tex} AMD {tex}\cong{/tex} {tex}\triangle {/tex} BNC ................RHS congruence criterion
{tex}\therefore {/tex} MD = NC .........(1).........CPCT
In right triangle BND,
{tex}\because {/tex} {tex}\angle{/tex} N=90°
{tex}\therefore {/tex} BD²= BN²+ DN² .............By Pythagoras theorem
= BN²+ (DC + CN)²
= BN²+ DC²+ CN²+ 2DC.CN
= (BN²+ CN²) + CN² + 2DC.CN
= BC²+ DC²+ 2DC.CN ..........(2)
In right triangle BNC with {tex}\angle{/tex}N = 90^o
BN²+CN² = BC² ......By Pythagoras theorem
In right triangle AMC
{tex}\because {/tex} {tex}\angle{/tex} M=90^o
{tex}\therefore {/tex} AC² = AM²+ MC²
= AM² = (DC - DM)²
= AM²+ DC²+ DM²- 2DC.DM
= (AM²+ DC²) + DC² - 2DC.DM
= AD²+ DC²- 2DC.DM
{tex}\because {/tex} In right triangle AMD with {tex}\angle{/tex} M=90°
AD²= AM² + DM² ..........[By Pythagoras theorem]
= AD²+ AB² - DC.CN .......From(1)
Adding (3) and (2) ,we get
AC²+ BD²= (AD²+ AB) + (BC²+ DC) = AB²+ BC²+ BC²+ CD²+ DA²

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If nth term of an AP is (2n+1) what is the sum of its three terms

Posted by Harsiddh Desai 6 years, 11 months ago

CBSE > Class 10 > Mathematics

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Anurag Mishra 6 years, 11 months ago

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Yashomani Maurya 6 years, 11 months ago

which three times

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Nature Video Real 6 years, 11 months ago

Wkt AP=2n+1 Let n=1,2,3 Then, 2.1

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The largest cone is curved out from one face of solid cube of side 21cm find the volume of the reamining solid

Posted by Amrita Patidar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

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Amrita Patidar 6 years, 11 months ago

Thnk u so much dear ??

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Sachin Singh 6 years, 11 months ago

We will subtract the volume of cone by the volume of cube which will be 6835.5cmcube

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If there are (2n+1) terms in an A.P, then prove that the ratio of the sum of odd terms and the sum of even terms is (n+1):n.

Posted by Durgesh Somani 6 years, 11 months ago

CBSE > Class 10 > Mathematics

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Sachin Singh 6 years, 11 months ago

Search on google I am providing u the link https://www.topperlearning.com/doubts-solutions/if-there-are-2n-1-terms-in-an-apthen-prove-that-ratio-of-sum-of-odd-numbers-to-that-of-even-numbers-is-n-1-n-3cgpw6ee/

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Find the sum of area of major sector of and their corresponding minor sector

Posted by Kumkum Saini 6 years, 11 months ago

CBSE > Class 10 > Mathematics