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Ask QuestionPosted by Prabhjeet Singh 6 years, 11 months ago
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Posted by Yash Ramchandani 6 years, 11 months ago
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Puja Sahoo? 6 years, 11 months ago
Chētnà Pandey✌️ 6 years, 11 months ago
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Posted by Prateek Pandey 6 years, 11 months ago
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Ram Kushwah 6 years, 11 months ago
Volume of water in cuboid
=50×44×21/100=462 M3…...(1)
Let after t hrs the level goes up 21 cm, so water length l=15×1000×t=15000 t m
Vol of water flowing =22/7×7×7×15000t/(100×100)=231t m3…....(2)
From (1) and (2)
231 t=462
t =2 hr
Posted by Kaushal Sharma 6 years, 11 months ago
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Posted by Ritesh Tanwer 6 years, 11 months ago
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Lionel Messi⚽️ 6 years, 11 months ago
Posted by Jagdeep Singh Saini 6 years, 11 months ago
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Priya Bansal 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
24 = 2 × 2 × 2 × 3
36 = 2 × 2 × 3 × 3
15 = 3 × 5
HCF = 3
LCM = 2 × 2 × 2 × 3 × 3 × 5 = 360
Posted by Gurjar Naam ही भत्हैरा ??? 6 years, 11 months ago
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Raunak Pandey ?? 6 years, 11 months ago
Priya Bansal 6 years, 11 months ago
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Posted by Gurjar Naam ही भत्हैरा ??? 6 years, 11 months ago
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Anushka Jugran ? 6 years, 11 months ago
Gurjar Naam ही भत्हैरा ??? 6 years, 11 months ago
Anushka Jugran ? 6 years, 11 months ago
Posted by Nevin Johnson 6 years, 11 months ago
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Vanya Jain 6 years, 11 months ago
Posted by Tamman Patnaik 6 years, 11 months ago
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Gaurav Seth 6 years, 11 months ago
Sec2θ - tan2θ = 1
(secθ+tanθ)(secθ-tanθ)=1
or, secθ-tanθ=1/p ----------------(2)
Adding (1) and (2) we get,
2secθ=p+1/p
or, secθ=(p²+1)/2p
∴, cosθ=1/secθ=2p/(p²+1)
∴, sinθ=√(1-cos²θ)
=√[1-{2p/(p²+1)}²]
=√[1-4p²/(p²+1)²]
=√[{(p²+1)²-4p²}/(p²+1)²]
=√[(p⁴+2p²+1-4p²)/(p²+1)²]
=√(p⁴-2p²+1)/(p²+1)
=√(p²-1)²/(p²+1)
=(p²-1)/(p²+1)
∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1)
Another method:
Sec2θ - tan2θ = 1
(secθ + tanθ)( secθ - tanθ) = 1
p( secθ - tanθ) = 1
( secθ - tanθ) = 1/p and, ......-(1)
( secθ + tanθ) = p ..... - (2)
(1) + (2),
secθ = 1/2 (p + 1/p) ,
(2) - (1)
tanθ = 1/2 (p-1/p)
secθ / tanθ = cosecθ
Hence,
cosecθ = p +1/p / p-1/p = p2 +1 / p2 -1
</article>Posted by Lionel Messi⚽️ 6 years, 11 months ago
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Raunak Pandey ?? 6 years, 11 months ago
Posted by Lionel Messi⚽️ 6 years, 11 months ago
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Saurabh Yadav 6 years, 11 months ago
1Thank You